Chapter 13: Problem 2
Evaluate the integrals. $$ \int x^{7} d x $$
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Chapter 13: Problem 2
Evaluate the integrals. $$ \int x^{7} d x $$
These are the key concepts you need to understand to accurately answer the question.
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According to the special theory of relativity, the apparent mass of an object depends on its velocity according to the formula $$ m=\frac{m_{0}}{\left(1-\frac{v^{2}}{c^{2}}\right)^{1 / 2}} $$ where \(v\) is its velocity, \(m_{0}\) is the "rest mass" of the object (that is, its mass when \(v=0\) ), and \(c\) is the velocity of light: approximately \(3 \times 10^{8}\) meters per second. a. Show that, if \(p=m v\) is the momentum, $$ \frac{d p}{d v}=\frac{m_{0}}{\left(1-\frac{v^{2}}{c^{2}}\right)^{3 / 2}} $$ b. Use the integral formula for \(W\) in the preceding exercise, together with the result in part (a) to show that the work required to accelerate an object from a velocity of \(v_{0}\) to \(v_{1}\) is given by $$ W=\frac{m_{0} c^{2}}{\sqrt{1-\frac{v_{1}^{2}}{c^{2}}}}-\frac{m_{0} c^{2}}{\sqrt{1-\frac{v_{0}^{2}}{c^{2}}}} . $$ We call the quantity \(\frac{m_{0} c^{2}}{\sqrt{1-\frac{v^{2}}{c^{2}}}}\) the total relativistic energy of an object moving at velocity \(v\). Thus, the work to accelerate an object from one velocity to another is given by the change in its total relativistic energy. c. Deduce (as Albert Einstein did) that the total relativistic energy \(E\) of a body at rest with rest mass \(m\) is given by the famous equation $$ E=m c^{2} $$.
The marginal cost of producing the \(x\) th box of light bulbs is \(5+x^{2} / 1,000\) dollars. Determine how much is added to the total cost by a change in production from \(x=10\) to \(x=100\) boxes. HINT [See Example 5.]
Complete the following: The total sales from time \(a\) to time \(b\) are obtained from the marginal sales by taking its ______ from ______ to ______.
Calculate the total area of the regions described. Do not count area beneath the \(x\) -axis as negative. HINT [See Example 6.] Bounded by the curve \(y=1-x^{2}\), the \(x\) -axis, and the lines \(x=-1\) and \(x=2\)
A car traveling down a road has a velocity of \(v(t)=60-e^{-t / 10}\) mph at time \(t\) hours. Find the distance it has traveled from time \(t=1\) hour to time \(t=6\) hours. (Round your answer to the nearest mile.)
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