/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Calculate the derivatives of the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculate the derivatives of the functions in Exercises 1-46. HINT [See Example 1.] \(f(x)=(2 x-1)^{-2}\)

Short Answer

Expert verified
The derivative of the function \(f(x) = (2x - 1)^{-2}\) is: \(f'(x) = -4(2x - 1)^{-3}\).

Step by step solution

01

Identify g(x) and h(x)

First, let's identify the functions \(g(x)\) and \(h(x)\) in our given function \(f(x) = (2x - 1)^{-2}\). We have: - \(g(x) = x^{-2}\) - \(h(x) = 2x - 1\)
02

Find g'(x) and h'(x)

Now, we need to find the derivatives of \(g(x)\) and \(h(x)\). For \(g(x) = x^{-2}\), using the power rule: \[g'(x) = -2x^{-3}\] For \(h(x) = 2x - 1\): \[h'(x) = 2\]
03

Apply the Chain Rule

Now, we apply the chain rule to find the derivative of \(f(x)\): \[f'(x) = g'(h(x))h'(x)\] Substitute g'(x), h(x), and h'(x): \[f'(x) = -2(2x - 1)^{-3}(2)\]
04

Simplify

Simplify the expression for the derivative: \[f'(x) = -4(2x - 1)^{-3}\] So, the derivative of the function \(f(x) = (2x - 1)^{-2}\) is: \[f'(x) = -4(2x - 1)^{-3}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Calculations
Understanding derivative calculations is crucial in calculus, as it allows you to determine the rate at which a function is changing at any given point. With derivatives, you can find slopes of tangent lines, rates of change, and understand the behavior of graphs more deeply.

When calculating derivatives, one often deals with not just simple functions but more complex ones where one function is nested inside another. This is where rules like the chain rule come into play. For instance, the function mentioned in the exercise, \(f(x) = (2x - 1)^{-2}\), requires implementing the chain rule for its derivative calculation because you have an outer function raised to a power and an inner function \(2x - 1\). Derivative calculations often involve breaking down the given function following the chain rule outlined in the solution to correctly find the derivative.
Power Rule
The power rule is a fundamental technique in finding derivatives and is particularly useful for functions that are monomials, such as \(x^n\), where \(n\) is any real number.

The rule states that to find the derivative of \(x^n\), you multiply \(n\) by \(x\) raised to the power of \(n-1\). Mathematically, this is represented as \(\frac{d}{dx}(x^n) = nx^{n-1}\). In our example, the power rule is applied to the function \(g(x) = x^{-2}\) resulting in \(g'(x) = -2x^{-3}\). Remember that this rule facilitates derivative calculations of any power, positive or negative, which makes it a versatile tool in the differentiation process.
Function Differentiation
Function differentiation is the process of finding the derivative of a function, which gives us the rate at which the function's value changes with respect to changes in its input value.

In the context of the exercise, function differentiation helps us understand how the composite function \(f(x) = (2x - 1)^{-2}\) behaves in terms of its change. When differentiating functions that are compositions, like this one, we apply the chain rule to differentiate the outside function (usually \(g(x)\)) and multiply it by the derivative of the inside function (\(h(x)\)). This creates a new function that tells us how steep or flat the graph of \(f(x)\) is at any point along its domain. The process outlined in the solution steps effectively demonstrates how to use the chain rule to differentiate complex functions, showing that composite functions are essentially products of their constituent parts when it comes to differentiation.

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Most popular questions from this chapter

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