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Calculate the derivatives of the functions in Exercises 1-46. HINT [See Example 1.] \(g(z)=\left(\frac{z}{1+z^{2}}\right)^{3}\)

Short Answer

Expert verified
The short answer is: \[\frac{d}{dz}g(z) = 3\left(\frac{z}{1+z^2}\right)^2 \cdot \frac{1-z^2}{(1+z^2)^2}\]

Step by step solution

01

Identify the outer and inner functions

We can rewrite the function as: \[g(z) = [f(u(z))]^3\] Where the outer function \(f(u) = u^3\) and the inner function \(u(z) = \frac{z}{1+z^{2}}\).
02

Find the derivative of the outer function

Using the power rule, we can find the derivative of the outer function \(f(u)\) with respect to \(u\): \[f'(u) = \frac{d}{du}(u^3) = 3u^2\]
03

Find the derivative of the inner function

Now we need to find the derivative of the inner function \(u(z)\) with respect to \(z\). Since \(u(z) = \frac{z}{1+z^{2}}\), we can use the quotient rule to differentiate it: \[\frac{d}{dz}\left(\frac{z}{1+z^{2}}\right) = \frac{(1+z^{2})\cdot1 - z\cdot2z}{(1+z^{2})^2}\] Simplify the expression: \[\frac{d}{dz}u(z)=\frac{1+z^{2}-2z^{2}}{(1+z^{2})^2} = \frac{1-z^{2}}{(1+z^{2})^2}\]
04

Apply the chain rule to find the derivative of the original function

Now that we have the derivatives of the outer and inner functions, we can apply the chain rule to find the derivative of the original function \(g(z)\) with respect to \(z\): \[\frac{d}{dz}g(z) = f'(u(z)) \cdot \frac{d}{dz}u(z)\] Substitute the values from Steps 2 and 3: \[\frac{d}{dz}g(z) = [3u^2] \cdot \left[\frac{1-z^{2}}{(1+z^{2})^2}\right]\] Now, replace \(u\) with the inner function from Step 1: \[\frac{d}{dz}g(z) = 3\left(\frac{z}{1+z^2}\right)^2 \cdot \frac{1-z^2}{(1+z^2)^2}\] Here, we have found the derivative of the given function with respect to \(z\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
In calculus, the chain rule is a formula for finding the derivative of a composition of functions. It is essential when dealing with composite functions, where one function is nested inside another. For example, if you have a function \(g(z) = [f(u(z))]^3\), you are dealing with a composite function made from an inner function \(u(z)\) and an outer function \(f(u) = u^3\).

To apply the chain rule, follow these steps:
  • First, differentiate the outer function with respect to its argument. In this case, differentiate \(f(u) = u^3\) to get \(f'(u) = 3u^2\).
  • Next, differentiate the inner function with respect to \(z\), which is \(u(z)\). This has been done in a previous step using the quotient rule.
  • Finally, multiply the derivative of the outer function by the derivative of the inner function. This gives you the final derivative of the composite function.
The chain rule helps you break down complex differentiations into manageable steps, finding the rate at which the output of the composite function changes with respect to the input.
Power Rule
The power rule is one of the most fundamental techniques in calculus for finding derivatives. It is particularly useful when you need to find the derivative of polynomials or functions raised to a power.

When you have a function of the form \(u^n\), where \(n\) is a constant, the power rule states that the derivative is \(nu^{n-1}\). For example, in our function \(f(u) = u^3\), using the power rule gives us \(f'(u) = 3u^2\).

The power rule simplifies the process by providing a straightforward way to calculate the derivative of simple power functions, allowing you to quickly proceed to more complex rules like the chain rule when necessary. By recognizing when the power rule can be applied, you can effectively tackle polynomials of various degrees.
Quotient Rule
The quotient rule is a method used to differentiate functions that are the ratio of two differentiable functions. It is crucial when the function you need to differentiate is in the form of one function divided by another.

Given a function \(u(z) = \frac{z}{1+z^2}\), we apply the quotient rule to find its derivative. The quotient rule states that for a function \(\frac{f(z)}{g(z)}\), the derivative is:\[\frac{d}{dz}\left(\frac{f(z)}{g(z)}\right) = \frac{g(z)f'(z) - f(z)g'(z)}{[g(z)]^2}\]In our function, \(f(z) = z\) and \(g(z) = 1+z^2\). By applying the quotient rule, you find the derivative:\[\frac{1+z^2\cdot1 - z\cdot2z}{(1+z^2)^2} = \frac{1-z^2}{(1+z^2)^2}\]This step is essential in the calculation of the chain rule, where you first need the inner derivative before applying the outer function's derivative. The quotient rule provides a clear process to handle derivatives in fractional forms efficiently.

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Most popular questions from this chapter

Calculate the derivatives of the functions in Exercises 1-46. HINT [See Example 1.] \(f(x)=(2 x+1)^{0.5}\)

The weekly revenue from the sale of emeralds at Eduardo’s Emerald Emporium (EEE) is decreasing at a rate of €500 per €1 increase in price, and the price is decreasing at a rate of €0.45 per additional emerald sold. What is the marginal revenue? (Be sure to state the units of measurement.) Interpret the result

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