Chapter 10: Problem 41
Find the equation of the tangent to the graph at the indicated point. HINT [Compute the derivative algebraically; then see Example \(2(\mathrm{~b})\) in Section \(10.5 .]\) $$ f(x)=-2 x-4 ; a=3 $$
Short Answer
Expert verified
The equation of the tangent line to the graph of the function \(f(x)=-2x-4\) at the point \(a=3\) is \(y=-2x-4\).
Step by step solution
01
Find the derivative of the function
To find the derivative, we will use the power rule, which states that if \(f(x) = x^n\), then \(f'(x) = nx^{n-1}\). In our case, the function is \(f(x) = -2x - 4\). So, first, find the derivative of each term.
The derivative of \(-2x\) with respect to \(x\):
\[\frac{d}{dx}(-2x) = -2\]
The derivative of \(-4\) (constant term) with respect to \(x\):
\[\frac{d}{dx}(-4) = 0\]
Now, combine these derivatives to get the derivative of the function:
\[f'(x) = -2\]
02
Find the slope of the tangent at a given point
Since we already found that \(f'(x) = -2\), the slope of the tangent is -2 for all values of x; hence, the slope of the tangent at \(a = 3\) is also -2.
03
Find the value of the function at the given point
Now, we need to find the value of the function at the given point \(a = 3\). We will use this value as the y-coordinate of the point where the tangent touches the graph. Plug in the value of \(a\) in the function:
\[f(3) = -2(3) - 4 = -6 - 4 = -10\]
So, the point of tangency on the graph is \((3, -10)\).
04
Use the point-slope form to find the equation of the tangent line
The point-slope form of a line equation is given by:
\(y - y_1 = m(x - x_1)\),
where \(m\) is the slope, and \((x_1, y_1)\) are the coordinates of the point on the line.
In our case, \(m = -2\), and the point \((x_1, y_1) = (3, -10)\). Substituting these values, we get:
\(y - (-10) = -2(x - 3)\),
\(y + 10 = -2x + 6\).
Now, rearrange this equation to give the equation of the tangent line:
\(y = -2x + 6 - 10\),
\(y = -2x - 4\).
Thus, the equation of the tangent line to the graph of the function \(f(x) = -2x - 4\) at the point \(a = 3\) is \(y = -2x - 4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
A derivative is a fundamental concept in calculus that represents the rate at which a function is changing at any given point. To put it simply, it tells us how steep a function is at a particular point.
- The derivative of a function gives the slope of the tangent line at any point on the function's graph.
- Derivatives are calculated using various rules depending on the structure of the function, such as the power rule, product rule, or chain rule.
Tangent Line
The tangent line is a straight line that touches a curve at a single point and has the same slope as the curve at that point.
- Mathematically, the tangent line at a point on a function is defined by the function's derivative at that point.
- For linear functions, like our example \(f(x) = -2x - 4\), the entire graph is essentially its own tangent line because it maintains a constant slope.
Power Rule
The power rule is one of the basic techniques used in differentiation, which is the process of finding a derivative. It is applicable to functions where the variable is raised to a power.
- The power rule states: If \(f(x) = x^n\), then the derivative \(f'(x) = nx^{n-1}\).
- This rule simplifies the differentiation of polynomials and is especially useful for functions that are combinations of powers of \(x\).
Point-Slope Form
The point-slope form is a way to write the equation of a line given a point and the slope. It provides a convenient method for translating the mathematical relationship between points and lines into an equation.
- The formula for the point-slope form is given by \(y - y_1 = m(x - x_1)\).
- Here, \((x_1, y_1)\) is a point on the line, and \(m\) is the slope of the line.