Chapter 10: Problem 32
Compute the indicated derivative. $$ U(t)=-1.3 t^{2}+1.1 ; U^{\prime}(4) $$
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Chapter 10: Problem 32
Compute the indicated derivative. $$ U(t)=-1.3 t^{2}+1.1 ; U^{\prime}(4) $$
These are the key concepts you need to understand to accurately answer the question.
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Compute the derivative function \(f^{\prime}(x)\) algebraically. (Notice that the functions are the same as those in Exercises \(1-14 .)\) HINT [See Examples 2 and \(3 .]\) $$ f(x)=-2 x+4 $$
Compute \(f^{\prime}(a)\) algebraically for the given value of a. HINT [See Example 1.] $$ f(x)=3 x^{2}+x ; a=1 $$
Let \(p(t)\) represent the percentage of children who are able to speak at the age of \(t\) months. a. It is found that \(p(10)=60\) and \(\left.\frac{d p}{d t}\right|_{t=10}=18.2 .\) What does this mean? \(^{55}\) HINT [See Quick Example 2 on page \(736 .\) ] b. As \(t\) increases, what happens to \(p\) and \(\frac{d p}{d t}\) ?
Compute the derivative function \(f^{\prime}(x)\) algebraically. (Notice that the functions are the same as those in Exercises \(1-14 .)\) HINT [See Examples 2 and \(3 .]\) $$ f(x)=\frac{2}{x} $$
The cost, in millions of dollars, of a 30 -second television ad during the Super Bowl in the years 1990 to 2007 can be approximated by the following piecewise linear function \((t=0\) represents 1990\():^{64}\) $$ C(t)=\left\\{\begin{array}{ll} 0.08 t+0.6 & \text { if } 0 \leq t<8 \\ 0.13 t+0.20 & \text { if } 8 \leq t \leq 17 \end{array}\right. $$ a. Is \(C\) a continuous function of \(t\) ? Why? HINT [See Example 4 of Section 10.3.] b. Is \(C\) a differentiable function of \(t ?\) Compute \(\lim _{t \rightarrow 8^{-}} C^{\prime}(t)\) and \(\lim _{t \rightarrow 8^{+}} C^{\prime}(t)\) and interpret the results. HINT [See Before we go on... after Example 5.]
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