Chapter 10: Problem 31
Compute the indicated derivative. $$ U(t)=5.1 t^{2}+5.1 ; U^{\prime}(3) $$
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Chapter 10: Problem 31
Compute the indicated derivative. $$ U(t)=5.1 t^{2}+5.1 ; U^{\prime}(3) $$
These are the key concepts you need to understand to accurately answer the question.
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Compute the derivative function \(f^{\prime}(x)\) algebraically. (Notice that the functions are the same as those in Exercises \(1-14 .)\) HINT [See Examples 2 and \(3 .]\) $$ f(x)=-x-x^{2} $$
Compute \(f^{\prime}(a)\) algebraically for the given value of a. HINT [See Example 1.] $$ f(x)=2 x^{2}+x ; a=-2 $$
Weekly sales of an old brand of TV are given by $$ S(t)=100 e^{-t / 5} $$ sets per week, where \(t\) is the number of weeks after the introduction of a competing brand. Estimate \(S(5)\) and \(\left.\frac{d S}{d t}\right|_{t=5}\) and interpret your answers.
According to Einstein’s Special Theory of Relativity and relate to objects that are moving extremely fast. In science fiction terminology, a speed of warp 1 is the speed of light-about \(3 \times 10^{8}\) meters per second. (Thus, for instance, a speed of warp \(0.8\) corresponds to \(80 \%\) of the speed of light-about \(2.4 \times 10^{8}\) meters per second. \()\) \- \mathrm{\\{} L o r e n t z ~ C o n t r a c t i o n ~ A c c o r d i n g ~ t o ~ E i n s t e i n ' s ~ S p e c i a l ~ Theory of Relativity, a moving object appears to get shorter to a stationary observer as its speed approaches the speed of light. If a spaceship that has a length of 100 meters at rest travels at a speed of warp \(p\), its length in meters, as measured by a stationary observer, is given by $$ L(p)=100 \sqrt{1-p^{2}} $$ with domain \([0,1)\). Estimate \(L(0.95)\) and \(L^{\prime}(0.95)\). What do these figures tell you?
Compute \(f^{\prime}(a)\) algebraically for the given value of a. HINT [See Example 1.] $$ f(x)=\frac{x}{k}-b(k \neq 0) ; a=12 $$
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