/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Use a graph to determine whether... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a graph to determine whether the given function is continuous on its domain. If it is not continuous on its domain, list the points of discontinuity. $$ f(x)=\frac{|x|}{x} $$

Short Answer

Expert verified
The function \(f(x) = \frac{|x|}{x}\) can be simplified as: \[f(x) = \begin{cases} 1 & \text{if}\ x > 0 \\ -1 & \text{if}\ x < 0 \\ \end{cases} \] The function is continuous for all positive and negative x, but at x = 0, the function is undefined, resulting in a point of discontinuity. Therefore, the function is continuous on its domain except at x = 0.

Step by step solution

01

Graph the function

Begin by graphing the function \(f(x) = \frac{|x|}{x}\). It is important to consider both positive and negative values of x as well as values close to 0.
02

Simplify the function

Recognize that the function can be simplified as follows: \[f(x) = \frac{|x|}{x} = \begin{cases} 1 & \text{if}\ x > 0 \\ -1 & \text{if}\ x < 0 \\ \end{cases} \] We can see that the function takes the value 1 for all positive x, and -1 for all negative x.
03

Analyze continuity

A function is continuous if it does not have any 'jumps', 'holes', or 'breaks' in the graph. Since f(x) = 1 for all positive x and f(x) = -1 for all negative x, the only point at which continuity may be questioned is x = 0.
04

Determine the value at x = 0

Although we have defined the function for x > 0 and x < 0, we have not defined the function for x = 0. As the function is of the form \(\frac{|x|}{x}\), for x = 0, it becomes \(\frac{0}{0}\), which is undefined. Thus, the function is not defined at x = 0.
05

Identify points of discontinuity

Since the function is not defined at x = 0, there is a point of discontinuity at x = 0. Therefore, the function \(f(x) = \frac{|x|}{x}\) is continuous everywhere on its domain except at x = 0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Points of Discontinuity
When studying functions and their graphs, identifying points of discontinuity is essential. Discontinuities occur when there is a disruption in the function's output at certain points in its domain. These can take the form of 'jumps', 'holes', or 'infinite breaks'.

In the function given by \( f(x) = \frac{|x|}{x} \), a point of discontinuity is found at \( x = 0 \). This occurs because the function is undefined at this value, resulting in a break in the graph. Specifically, evaluating the function at zero results in an indeterminate form \( \frac{0}{0} \), reinforcing the discontinuity at that point. Therefore, while the function behaves predictably for \( x > 0 \) and \( x < 0 \), \( x = 0 \) is where it "breaks" or becomes undefined.
Piecewise Functions
Piecewise functions are functions that have different expressions or rules for different parts of their domain. They are used to describe situations where a function behaves differently over various intervals.

For the function \( f(x) = \frac{|x|}{x} \), it can be expressed as a piecewise function:
  • \( f(x) = 1 \) if \( x > 0 \)
  • \( f(x) = -1 \) if \( x < 0 \)
This means that the function outputs 1 when \( x \) is a positive number, and outputs -1 when \( x \) is negative. There is no definition given for when \( x = 0 \), which contributes to the discontinuity discussed in the previous section.
Graphical Analysis
Graphical analysis involves examining the graph of a function to understand its behavior across its domain. For the function \( f(x) = \frac{|x|}{x} \), analyzing the graph can provide insights into how the function operates and where it might have discontinuities.

When graphed, \( f(x) = \frac{|x|}{x} \) appears as two distinct horizontal lines on either side of the y-axis:
  • A horizontal line at \( y = 1 \) for positive \( x \)
  • A horizontal line at \( y = -1 \) for negative \( x \)
There is a visible gap at \( x = 0 \) due to the function being undefined at that point. By observing the graph, the discontinuity at \( x = 0 \) becomes clear, as the lines for positive and negative \( x \) do not connect. This type of analysis is valuable in visualizing how piecewise and discontinuous functions behave.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(F(t)\) represent the net earnings of Footbook Inc. in millions of dollars \(t\) years after its inception in 3020 . It is found that \(F(100)=-10\) and \(F^{\prime}(100)=60\). This means that, in 3120 (Multiple Choice): (A) Footbook lost \(\$ 10\) million but its net earnings were increasing at a rate of \(\$ 60\) million per year. (B) Footbook earned \(\$ 60\) million but its earnings were decreasing at a rate of \(\$ 10\) million per year. (C) Footbook's net earnings had increased by \(\$ 60\) million since the year before, but it still lost \(\$ 10\) million. (D) Footbook earned \(\$ 10\) million but its net earnings were decreasing at a rate of \(\$ 60\) million per year. (E) Footbook's net earnings had decreased by \(\$ 10\) million since the year before, but it still earned \(\$ 60\) million.

Compute \(f^{\prime}(a)\) algebraically for the given value of a. HINT [See Example 1.] $$ f(x)=x-2 x^{3} ; a=1 $$

If a stone is dropped from a height of 400 feet, its height after \(t\) seconds is given by \(s=400-16 t^{2}\). Find its instantaneous velocity function and its velocity at time \(t=4\). HINT [See Example 4.]

On January 1,1996, America Online was the biggest online service provider, with \(4.5\) million subscribers, and was adding new subscribers at a rate of 60,000 per week. \(^{53}\) If \(A(t)\) is the number of America Online subscribers \(t\) weeks after January 1,1996, what do the given data tell you about values of the function \(A\) and its derivative? HINT [See Quick Example 2 on page \(736 .\) ]

Compute the derivative function \(f^{\prime}(x)\) algebraically. (Notice that the functions are the same as those in Exercises \(1-14 .)\) HINT [See Examples 2 and \(3 .]\) $$ f(x)=x^{2}-3 $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.