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Compute \(f^{\prime}(a)\) algebraically for the given value of a. HINT [See Example 1.] $$ f(x)=\frac{-1}{x} ; a=1 \text { HINT [See Example 3.] } $$

Short Answer

Expert verified
Rewrite the function as \(f(x) = -x^{-1}\), then apply the power rule for differentiation to obtain \(f'(x) = 1x^{-2}\) or \(f'(x) = \frac{1}{x^2}\). Next, compute the derivative at the given value of \(a=1\), resulting in \(f^{\prime}(1) = \frac{1}{(1)^2} = 1\).

Step by step solution

01

Rewrite the function in the form of a power function #

Instead of writing the function as a fraction, we will rewrite it as a power function to make differentiation easier. The given function \(f(x)=\frac{-1}{x}\) can be rewritten as \(f(x) = -x^{-1}\).
02

Apply the power rule for differentiation #

The power rule for differentiation states that if \(f(x) = x^n\), then \(f'(x) = nx^{n-1}\). Applying this rule to our function \(f(x) = -x^{-1}\), we get the following: \(f'(x) = (-1)\cdot (-1)x^{-1-1}\)
03

Simplify the expression #

Let's simplify the expression we got in the previous step: \(f'(x) = 1x^{-2}\) Now, we can rewrite this back in the form of a fraction: \(f'(x) = \frac{1}{x^2}\)
04

Compute the derivative at the given value of 'a' #

Now, we will find the value of the derivative at the given value of 'a' which is \(a=1\). Substitute \(x=1\) into the expression for the derivative: \(f'(1) = \frac{1}{(1)^2}\)
05

Simplify the expression and find the final value of the derivative #

Finally, simplify the expression to find the value of the derivative at \(a=1\): \(f'(1) = \frac{1}{1} = 1\) So, \(f^{\prime}(1) = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Differentiation
Understanding the power rule for differentiation is essential for computing derivatives of power functions. The power rule states that for any function of the form
\( f(x) = x^n \)
the derivative, denoted \( f'(x) \), is given by multiplying the exponent \( n \) by the coefficient (if any) and decreasing the exponent by one. The formula for this can be expressed as:
\( f'(x) = nx^{n-1} \)
In the context of the provided exercise, the function \( f(x) = -x^{-1} \) is a power function where the exponent \( n \) is \( -1 \). By applying the power rule, we calculate the derivative as \( f'(x) = (-1)(-x^{-1-1}) \), which simplifies to \( f'(x) = x^{-2} \).
When using the power rule, it's important to remember that it applies to all real number exponents, even if they are negative or fractions.
Algebraic Computation of Derivatives
The process of finding derivatives algebraically involves manipulating the algebraic form of the function according to well-established rules, like the power rule. Before applying the power rule, one might need to rewrite the function in a form that clearly shows the power, such as changing \( \frac{-1}{x} \) to \( -x^{-1} \).
Once we have the function in the correct form, we apply the differentiation rules to find the derivative. The strength of algebraic computation lies in its precision and reliability — every step is based on mathematical laws and the application of theorems. It's worth noting that being comfortable with these algebraic techniques can greatly simplify the process of finding derivatives for more complex functions, especially when functions are nested or when products and quotients of functions are involved.
Simplifying Expressions
Simplification is a key step in algebra and calculus that involves rewriting expressions in their most basic form while keeping their values unchanged. It often makes further computation or understanding the nature of a function much easier.
In differentiation, after applying rules like the power rule, the result may require simplification as seen in the exercise. For instance, after using the power rule, we got \( f'(x) = x^{-2} \), which we further simplify by rewriting it as \( f'(x) = \frac{1}{x^2} \). This not only looks cleaner but also makes evaluating the derivative at a certain point straightforward.

Remember the Exponent Rules

When simplifying expressions, it's essential to remember the exponent rules. Expressions with negative exponents can be rewritten as fractions (as in the example above), and expressions with positive exponents can sometimes be factored or expanded to simplify further. Always aim to present the final step of the calculation as clearly as possible to facilitate easy checks and practical applications.

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Most popular questions from this chapter

Use the balanced difference quotient formula, $$ f^{\prime}(a)=\lim _{h \rightarrow 0} \frac{f(a+h)-f(a-h)}{2 h} $$ to compute \(f^{\prime}(3)\) when \(f(x)=x^{2}\). What do you find?

Estimate the given quantity. \(f(x)=\ln x ;\) estimate \(f^{\prime}(1)\)

The oxygen consumption of a bird embryo increases from the time the egg is laid through the time the chick hatches. In a typical galliform bird, the oxygen consumption (in milliliters per hour) can be approximated by \(c(t)=-0.0027 t^{3}+0.14 t^{2}-0.89 t+0.15 \quad(8 \leq t \leq 30)\) where \(t\) is the time (in days) since the egg was laid. \({ }^{57}\) (An egg will typically hatch at around \(t=28 .\) ) Use technology to graph \(c^{\prime}(t)\) and use your graph to answer the following questions. HINT [See Example 5.] 1\. Over the interval \([8,30]\) the derivative \(c^{\prime}\) is (A) increasing, then decreasing (B) decreasing, then increasing (C) decreasing (D) increasing \- When, to the nearest day, is the oxygen consumption increasing the fastest? When, to the nearest day, is the oxygen consumption increasing at the slowest rate?

Compute \(f^{\prime}(a)\) algebraically for the given value of a. HINT [See Example 1.] $$ f(x)=2 x-x^{2} ; a=-1 $$

Daily oil imports to the United States from Mexico can be approximated by \(I(t)=-0.015 t^{2}+0.1 t+1.4\) million barrels \(\quad(0 \leq t \leq 8)\) where \(t\) is time in years since the start of \(2000 .^{58}\) Find the derivative function \(\frac{d I}{d t} .\) At what rate were oil imports changing at the start of \(2007(t=7) ?\) HINT [See Example 4.]

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