Chapter 0: Problem 24
By any method, determine all possible real solutions of each equation Check your answers by substitution. \(16 x^{2}=-24 x-9\)
Short Answer
Expert verified
The real solution to the equation \(16x^2 + 24x + 9 = 0\) is \(x = -\frac{3}{4}\).
Step by step solution
01
Identify Quadratic Equation Parameters
First, rewrite the equation in the following standard form: \(ax^2 + bx + c = 0\). This will make it easier to identify the parameters, a, b, and c, that we need to use in the quadratic formula.
Our given equation is \(16x^2 = -24x -9\), so we have:
\(16x^2 + 24x + 9 = 0\)
Now we can clearly see that:
a = 16
b = 24
c = 9
02
Apply the Quadratic Formula
Next, we apply the quadratic formula, which states that for any quadratic equation in the standard form \(ax^2 + bx + c = 0\), the solutions for x are given by the following formula:
\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Plug in the values of a, b, and c that we found in Step 1:
\(x = \frac{-24 \pm \sqrt{24^2 - 4(16)(9)}}{2(16)}\)
03
Simplify the Expression
Simplify the expression to find the two possible values for x:
\(x = \frac{-24 \pm \sqrt{576 - 576}}{32}\)
\(x = \frac{-24 \pm \sqrt{0}}{32}\)
Since the square root of 0 is 0, we can write:
\(x = \frac{-24 \pm 0}{32}\)
04
Calculate the Solution
There is only one possible solution for x in this case, which is:
\(x = \frac{-24}{32}\)
Simplify the fraction:
\(x = -\frac{3}{4}\)
05
Check the Solution by Substitution
To check if our solution is correct, we need to substitute the value of x back into the original equation and see if the equation holds true. Here's the original equation:
\(16x^2 = -24x -9\)
Substitute \(x = -\frac{3}{4}\):
\(16\left(-\frac{3}{4}\right)^2 = -24\left(-\frac{3}{4}\right) - 9\)
Simplify:
\(16\frac{9}{16} = 18 - 9\)
\(9 = 9\)
The equation holds true with the solution we found, so we can conclude that x = -3/4 is the only real solution to the given quadratic equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \(ax^2 + bx + c = 0\). This formula provides a direct way to find the solutions, or roots, of the equation. The quadratic formula is expressed as:
The plus-minus symbol (\(\pm\)) indicates that there can be two solutions:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
The plus-minus symbol (\(\pm\)) indicates that there can be two solutions:
- One where you add the square root
- Another where you subtract it
Real Solutions
Real solutions are the values of \(x\) that satisfy the quadratic equation and exist within the set of real numbers. To determine if a quadratic equation has real solutions, you calculate the discriminant, \(b^2 - 4ac\), from inside the square root of the quadratic formula.
In our example, where we find \(b = 24\), \(a = 16\), and \(c = 9\), the discriminant becomes \(24^2 - 4 \cdot 16 \cdot 9 = 576 - 576 = 0\).
In our example, where we find \(b = 24\), \(a = 16\), and \(c = 9\), the discriminant becomes \(24^2 - 4 \cdot 16 \cdot 9 = 576 - 576 = 0\).
- If the discriminant is positive, there are two distinct real solutions.
- If it is zero, like our example, there is exactly one real solution.
- If it is negative, the equation has no real solutions, only complex ones.
Substitution Method
The substitution method is a simple check to verify the solution you have found for a quadratic equation. Once you've calculated a solution, you substitute that value back into the original equation to confirm it satisfies the equation.
For the equation \(16x^2 = -24x - 9\), and our solution \(x = -\frac{3}{4}\), substitution involves replacing \(x\) with \(-\frac{3}{4}\) in the original equation:
For the equation \(16x^2 = -24x - 9\), and our solution \(x = -\frac{3}{4}\), substitution involves replacing \(x\) with \(-\frac{3}{4}\) in the original equation:
- Compute \(16\left(-\frac{3}{4}\right)^2\)
- Compare to \(-24\left(-\frac{3}{4}\right) - 9\)
Equation Solving
Equation solving is finding all values for a variable that satisfy a given equation. For quadratic equations, solving involves finding all possible values of \(x\) that will make the equation true.
Methods to solve quadratic equations include:
Simplification leads directly to the solutions. In our problem, we simplified the expression with the formula to find \(x = -\frac{3}{4}\), which is the real solution.
Methods to solve quadratic equations include:
- Factoring
- Completing the square
- Using the quadratic formula
Simplification leads directly to the solutions. In our problem, we simplified the expression with the formula to find \(x = -\frac{3}{4}\), which is the real solution.
Quadratic Equation Parameters
Understanding the parameters of a quadratic equation is crucial for solving it effectively. These parameters are the coefficients \(a\), \(b\), and \(c\) present in the standard quadratic form \(ax^2 + bx + c = 0\).
- \(a\) is the coefficient of \(x^2\), determining the parabola's "width" and direction (open upwards/downwards).
- \(b\) is the coefficient of \(x\), affecting the parabola's axis of symmetry and vertex position.
- \(c\) is the constant term, contributing to the vertical shift of the parabola.