/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 220 Determine the parity of \(\sigma... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the parity of \(\sigma=542163\).

Short Answer

Expert verified
The given permutation is \(\sigma=542163\). After identifying and counting the inversions, there are 9 inversions in total. Since 9 is an odd number, the parity of the permutation \(\sigma=542163\) is odd.

Step by step solution

01

Write down the given permutation

The given permutation is \(\sigma=542163\).
02

Identify the inversions

An inversion in a permutation is a pair of elements such that \(a_i > a_j\) for \(i < j\). In this case, let's find all the inversions in the given permutation: 1. 5 and 4 (1st and 2nd elements) 2. 5 and 2 (1st and 3rd elements) 3. 5 and 1 (1st and 5th elements) 4. 5 and 3 (1st and 6th elements) 5. 4 and 2 (2nd and 3rd elements) 6. 4 and 1 (2nd and 5th elements) 7. 4 and 3 (2nd and 6th elements) 8. 2 and 1 (3rd and 5th elements) 9. 6 and 3 (4th and 6th elements)
03

Count the number of inversions

We have identified 9 inversions in the given permutation.
04

Determine the parity

As there are 9 inversions, and 9 is an odd number, the parity of the permutation \(\sigma=542163\) is odd.

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Most popular questions from this chapter

1\. Which of the following matrices are in reduced-row chelon form? \(\begin{array}{lllllll}\text { (a) } & \mid 1 & 0 & 0 & \text { (b) } & \mid 0 & 1 & 0 \\ & \mid 0 & 0 & 0 \mid & & 1 & 0 & 0 \\ & \mid 0 & 0 & 1 & & 0 & 0 & 0\end{array}\) (c) \(\begin{array}{rrr}\mid 1 & 1 & 0 \\ & \mid 0 & 1 & 0 \\ & \mid 0 & 0 & 0\end{array} \mid\) (d) \(\begin{array}{lllll} & 11 & 2 & 0 & 3 & 0 \\ & 10 & 0 & 1 & 1 & 0 \\ & \mid 0 & 0 & 0 & 0 & 1 \\ & \mid 0 & 0 & 0 & 0 & 0\end{array}\) (e) \(\begin{array}{llll} & 1 & 0 & 0 & 5 \mid \\ & \mid 0 & 0 & 1 & 3 \mid \\\ & \mid 0 & 1 & 0 & 4\end{array}\) (f) \(\quad \begin{array}{cccc}1 & 0 & 3 & 1 \mid \\ & 0 & 1 & 2 & 4\end{array}\) 2\. Which of the following matrices are in row-echelon form? (a) \(\begin{array}{ccc}\mid 1 & 2 & 3 \\ & \mid 0 & 0 & 0 \\ & \mid 0 & 0 & 1\end{array}\) (b) \(\quad\left|\begin{array}{ccc}1 & -7 & 5 & 5 \mid \\ & \mid 0 & 1 & 3 & 2\end{array}\right|\) (c) \(\begin{array}{rrr} & \mid 1 & 1 & 0 \\ & \mid 0 & 1 & 0 \mid \\ & \mid 0 & 0 & 0\end{array} \mid\) (d) \(\begin{array}{rllll} & 1 & 3 & 0 & 2 & 0 \\ & 11 & 0 & 2 & 2 & 0 \\ & 10 & 0 & 0 & 0 & 1 \mid \\ & 10 & 0 & 0 & 0 & 0\end{array}\) (e) \(\begin{array}{rll} & \mid 2 & 3 & 4 \mid \\ & \mid 0 & 1 & 2 \mid \\ & \mid 0 & 0 & 3\end{array} \mid\) (f) \(\begin{array}{ccc} & \mid 0 & 0 & 0 \\ & \mid 0 & 0 & 0 \\ & \mid 0 & 0 & 0\end{array} \mid\)

Find the rank of the matrix A where: (i) \(\quad \begin{array}{rrrrrr} & \mid 1 & 3 & 1 & -2 & -3 \mid \\ & A=\mid 1 & 4 & 3 & -1 & -4 \mid \\ & \mid 2 & 3 & -4 & -7 & -3 \\ & \mid 3 & 8 & 1 & -7 & -8 \mid\end{array}\) (ii) \(\quad \begin{aligned}&\mid 1 & 2 & -3 \mid \\\&A= & \mid 2 & 1 & 0 \mid \\\&\mid-2 & -1 & 3 \\\&\mid-1 & 4 & -2\end{aligned} \mid\) (iii) \(\quad \begin{array}{rr}\mid 1 & 3 \mid \\ A=\mid & -2 \mid \\ \mid 5 & -1 \mid \\ \mid-2 & 3\end{array} \mid\)

Compute \(\mathrm{u} \cdot \mathrm{v}\) where i) \(\mathrm{u}=(2,-3,6) ; \mathrm{v}=(8,2,-3)\); ii) \(\mathrm{u}=(1,-8,0,5), \mathrm{v}=(3,6,4)\) iii) \(\mathrm{u}=(3,-5,2,1), \mathrm{v}=(4,1,-2,5)\)

\(\mathrm{A}=\mid \begin{array}{lll}1 & 1 \mid \text { and } \mathrm{P}=\mid 1 & 1 \mid \\ \mid \begin{array}{ll}0 & 1 \mid\end{array} & \mid 1 & -1 \mid \text { . }\end{array}\) (a) Find \(\mathrm{P}^{-1}\). (b) Find \(\mathrm{P}^{-1} \mathrm{AP}\). (c) Verify that, if \(\mathrm{B}\) is similar to \(\mathrm{A}\) then \(\mathrm{A}\) is similar to \(\mathrm{B}\). (d) Show that \(\mathrm{B}^{\mathrm{k}}=\mathrm{P}^{-1} \mathrm{~A}^{\mathrm{k} \mathrm{P}}\) if \(\mathrm{B}=\mathrm{P}^{-1}\) AP where \(\mathrm{k}\) is any positive integer.

Show that the following system has more than one solution. $$ \begin{aligned} 3 \mathrm{x}-\mathrm{y}+7 \mathrm{z} &=0 \\ 2 \mathrm{x}-\mathrm{y}+4 \mathrm{z} &=1 / 2 \\ \mathrm{x}-\mathrm{y}+\mathrm{z} &=1 \\ 6 \mathrm{x}-4 \mathrm{y}+10 \mathrm{z} &=3 \end{aligned} $$

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