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The Auto Times charges \(g\) dollars for a classified ad with \(m\) or less lines. Each additional line is \(d\) dollars. If \(x>m,\) express the cost of an \(x\) -line ad algebraically.

Short Answer

Expert verified
The cost of an \(x\)-line ad, given \(x > m\), is expressed as \(g + (x - m) * d\).

Step by step solution

01

Identify the Values

Identify the known values; \(g\) dollars is the cost for \(m\) lines or less, and every additional line over m lines costs \(d\) dollars.
02

Determine the Additional Lines

The number of additional lines, \(x-m\), is needed since each of these lines comes with an extra cost of \(d\) dollars. This happens only if \(x > m\). If \(x \leq m\), the cost is \(g\) dollars.
03

Express the Total Cost Algebraically

The total cost can be found by adding the initial cost of \(g\) dollars to the extra cost, which can be expressed algebraically as \((x - m) * d\) dollars.
04

Formulate the Equation

Combine these together to get the algebraic expression for the total cost of an \(x\)-line ad. The formula is: \(g + (x - m) * d\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebraic Cost Calculation
Understanding algebraic cost calculation involves translating real-world financial situations into mathematical expressions, a fundamental skill in both math and everyday life. Let's take the example provided: the cost of a classified ad. If an ad costs a base price of \(g\) dollars for up to \(m\) lines, to calculate the cost for more lines, you must consider the additional charge.

For example, if you wanted to place an ad with \(x\) lines where \(x > m\), you need to account for the extra lines. Each of these lines costs \(d\) dollars. Therefore, the total cost can be calculated by adding the base cost \(g\) to the product of the number of extra lines, \(x-m\), and the cost per additional line, \(d\). This gives us the algebraic expression for the total cost: \( g + (x - m) * d \).
Linear Equations
Linear equations form the basis of algebra and represent straight lines in coordinate geometry. They are used to describe a relationship between variables that can be plotted as a straight line on a graph. The algebraic expression from our problem, \( g + (x - m) * d \), can be considered a linear equation if we treat it as equivalent to a certain cost, say \(C\).

Using the classified ad example, we see a direct, proportional increase in cost as extra lines are added, reflecting the characteristics of a linear equation. When expressed as \( C = g + (x - m) * d \), where \(C\) represents the total cost of the ad, our variables are clearly defined and the relationship between the number of lines and the total cost is linear. This equation allows us to calculate the total cost for any number of lines beyond the base amount, \(m\), and is especially useful for predicting expenses for various ad lengths.
Math Word Problems
Math word problems are a way to apply mathematical theory to real-world scenarios. They require a combination of reading comprehension and mathematical skills to translate text into a mathematical representation. The key is to identify the variables and the relationships between them—in our ad cost problem, these were the cost for a base number of lines \(g\), the number of lines in the ad \(x\), the base number of lines offered \(m\), and the cost for each additional line \(d\).

Diligently reading the problem, identifying known and unknown values, and determining how they logically relate to one another, students can build a step-by-step strategy to solve complex problems. By practicing word problems, students enhance their analytical skills and their ability to use algebra to solve various challenges in different contexts.

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Most popular questions from this chapter

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