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Ron estimates that it will cost \(400,000 to send his daughter to a private college in 18 years. He currently has \)90,000 to deposit in an account. What simple interest rate must his account have to reach a balance of $400,000 in 18 years? Round to the nearest percent.

Short Answer

Expert verified
The interest rate should be approximately 2%

Step by step solution

01

Organize the Information

The following information is given: The principal \(P\) is $90,000, the time \(t\) is 18 years, and the total amount \(A\) is $400,000. Using the formula for the total amount with simple interest \(A = P + I = P+ Prt\), where \(r\) is what we have to calculate, \(I\) is already included in the total.
02

Setting Up the Equation

Substitute \(P\), \(A\), and \(t\) into the equation to get: \(400,000 = 90,000 + 90,000*r*18\).
03

Simplification

This equation can be simplified and set up as a linear equation: \(90,000*r*18 = 400,000 - 90,000\). Simplify further to get \(r = \frac{400,000 - 90,000}{90,000*18}\).
04

Calculation

Calculate the value of \(r\).
05

Conversion to Percentage

After getting the solution, it is necessary to convert \(r\) to a percentage and round to the nearest percent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interest Rate Calculation
Calculating the interest rate involves determining the percentage rate at which your principal amount grows over time. In the context of simple interest, which is the type of interest calculation used in the given exercise, the interest is calculated straightforwardly without compounding. The basic formula you need to be familiar with is the simple interest formula:\[ A = P + Prt \]where:
  • A is the total amount after interest,
  • P is the principal amount (initial investment),
  • r is the interest rate (expressed as a decimal),
  • t is the time in years.
To find the interest rate, you rearrange the formula to solve for \( r \) by isolating it on one side of the equation. For instance, if you need \(400,000 after 18 years from \)90,000, understanding this formula helps you see how each component affects the outcome.
Financial Algebra
Financial algebra refers to applying algebraic techniques to financial problems such as loan calculations, saving plans, and investment interest. It provides a structured method to navigate various scenarios in finance, allowing you to solve for unknowns. In the exercise above, we have an equation derived from the simple interest formula:\[ A = P + Prt \]
This setup is a classic example of applying algebra to figure out the unknown interest rate \( r \). You place known values—here, the future sum \( A \), the current investment \( P \), and the time \( t \)—into the equation to solve for \( r \).

Knowing how to handle algebraic manipulations enables you to focus on solving for different variables in any financial scenario. It’s a way to make informed decisions, whether planning for education expenses, like Ron, or managing personal finances.
Linear Equations
A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a single variable. These are straightforward equations where the relationships are linear, meaning they form a straight line when graphed.

In the example problem, you're dealing with a linear equation when calculating the simple interest. The expression \( 90,000 + 90,000r \times 18 = 400,000 \) simplifies to finding \( r \), producing a simple linear equation format:\[ 90,000r \times 18 = 310,000 \] or equivalent transformations.
Once rearranged, it visually represents 'solving for \( r \)' as finding the point where this equation holds true. Understanding linear equations in financial contexts helps demystify how adjustments to the interest rate or time period can influence financial goals.
This makes it essential to grasp how altering one variable, while keeping others constant, can take you closer to or further from achieving specific financial targets.

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Most popular questions from this chapter

One day before the end of the month, George had an opening balance of \(m\) dollars in an account that pays 2.25\(\%\) interest compounded monthly. On the last day of the month, he made a deposit equal to twice his opening balance. Express his ending balance on the last day of the month algebraically.

Whitney deposits \(\$9,000\) for two years. She compares two different banks. State Bank will pay her 4.1% interest, compounded monthly. Kings Savings will pay her 4.01% interest, compounded continuously. a. How much interest does State Bank pay? b. How much interest does Kings Savings pay? c. Which bank pays higher interest? How much higher? d. What other factors might affect Whitney’s choice besides interest?

Joby had \(\$ 421.56\) in her checking account when she deposited \(g\) twenty- dollar bills and \(k\) quarters. Write an expression that represents the amount of money in her account after the deposit.

Jill has not been able to maintain the \(\$ 1,000\) minimum balance required to avoid fees on her checking account. She wants to switch to a different account with a fee of \(\$ 0.20\) per check and a \(\$ 12.50\) monthly maintenance fill wants to estimate the fees for her new account. Below is a summary of the checks she has written from May to August. $$\begin{array}{|c|c|}\hline & {\text { Number of }} {\text { Checks on }}\\\ \text { Month } & {\text { Statement }} \\ \hline\text { May } & {14} \\\ \hline \text { June } & {19} \\ \hline {\text { July }} & {23} \\\ \hline{\text { August }} & {24} \\ \hline\end{array}$$ a. What is the mean number of checks Jill wrote per month during the last four months? b. Based on the mean, estimate how much Jill expects to pay in per-check fees each month after she switches to the new account. c. Estimate the total monthly fees Jill will pay each month for the new checking account.

John cashed a check for \(\$ 630 .\) The teller gave him three fifty-dollar bills, eighteen twenty-dollar bills, and \(t\) ten-dollar bills. Determine the value of \(t .\)

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