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Find the \(x\) -intercepts for each of the following functions. Will the vertex lie above, below, or on the \(x\) -axis? Find the vertex and sketch the graph, labeling the \(x\) -intercepts. a. \(y=(x+2)(x+1)\) d. \(y=\frac{1}{2}(x)(x-5)\) b. \(y=3(1-2 x)(x+3)\) e. \(q(x)=2(x-3)(x+2)\) c. \(y=-4(x+3)^{2}\) f. \(f(x)=-2(5-x)(3-2 x)\)

Short Answer

Expert verified
a) x-intercepts: -2, -1, vertex: (-1.5, -0.25); d) x-intercepts: 0, 5, vertex: (2.5, -3.125); b) x-intercepts: 0.5, -3, vertex: (-1.25, 18.375); e) x-intercepts: 3, -2, vertex: (0.5, -12.5); c) x-intercept: -3, vertex: (-3, 0); f) x-intercepts: 5, 1.5, vertex: (3.25, 12.25)

Step by step solution

01

Identifying the x-intercepts for part a

For the function \(y=(x+2)(x+1)\), set \(y\) to 0 and solve for \(x\). \(0=(x+2)(x+1)\) Solutions: \(x = -2\) and \(x = -1\)
02

Finding the vertex for part a

Since the function is given in factored form, the vertex's x-coordinate is the average of the roots. \(x_v = \frac{-2 + (-1)}{2} = -1.5\) Substitute \(x = -1.5\) into the original function: \(y = (-1.5 + 2)(-1.5 + 1) = (0.5)(-0.5) = -0.25\) So, the vertex is \((-1.5, -0.25)\)
03

Drawing conclusions for part a

The vertex lies below the \(x\)-axis because \(-0.25\) is negative.
04

Identifying the x-intercepts for part d

For the function \(y=\frac{1}{2}(x)(x-5)\), set \(y\) to 0 and solve for \(x\). \(0=\frac{1}{2}(x)(x-5)\) Solutions: \(x = 0\) and \(x = 5\)
05

Finding the vertex for part d

Since the function is given in factored form, the vertex's x-coordinate is the average of the roots. \(x_v = \frac{0 + 5}{2} = 2.5\) Substitute \(x = 2.5\) into the original function: \(y = \frac{1}{2}(2.5)(2.5-5) = \frac{1}{2}(2.5)(-2.5) = -3.125\) So, the vertex is \((2.5, -3.125)\)
06

Drawing conclusions for part d

The vertex lies below the \(x\)-axis because \(-3.125\) is negative.
07

Identifying the x-intercepts for part b

For the function \(y=3(1-2x)(x+3)\), set \(y\) to 0 and solve for \(x\). \(0=3(1-2x)(x+3)\) Solutions: \(x = \frac{1}{2}\) and \(x = -3\)
08

Finding the vertex for part b

Since the function is given in factored form, the vertex's x-coordinate is the average of the roots. \(x_v = \frac{-3 + \frac{1}{2}}{2} = -1.25\) Substitute \(x = -1.25\) into the original function: \(y = 3(1-2(-1.25))(-1.25+3) = 3(1+2.5)(1.75) = 3(3.5)(1.75) = 18.375\) So, the vertex is \((-1.25, 18.375)\)
09

Drawing conclusions for part b

The vertex lies above the \(x\)-axis because \(18.375\) is positive.
10

Identifying the x-intercepts for part e

For the function \(q(x)=2(x-3)(x+2)\), set \(y\) to 0 and solve for \(x\). \(0=2(x-3)(x+2)\) Solutions: \(x = 3\) and \(x = -2\)
11

Finding the vertex for part e

Since the function is given in factored form, the vertex's x-coordinate is the average of the roots. \(x_v = \frac{3 + (-2)}{2} = 0.5\) Substitute \(x = 0.5\) into the original function: \(y = 2(0.5-3)(0.5+2) = 2(-2.5)(2.5) = 2(-6.25) = -12.5\) So, the vertex is \((0.5, -12.5)\)
12

Drawing conclusions for part e

The vertex lies below the \(x\)-axis because \(-12.5\) is negative.
13

Identifying the x-intercepts for part c

For the function \(y=-4(x+3)^{2}\), this is a quadratic equation in vertex form. To find the x-intercepts, set \(y\) to 0 and solve for \(x\). \(0=-4(x+3)^{2}\) Since the right-hand side is always non-negative, and the coefficient \(-4\) makes it non-positive, the only solution is when \((x+3)^{2} = 0\). Solution: \(x = -3\)
14

Finding the vertex for part c

In the vertex form \(y = -4(x + 3)^{2}\), the vertex is at \((-3, 0)\).
15

Drawing conclusions for part c

The vertex is on the \(x\)-axis because \(y = 0\).
16

Identifying the x-intercepts for part f

For the function \(f(x)=-2(5-x)(3-2x)\), set \(y\) to 0 and solve for \(x\). \(0=-2(5-x)(3-2x)\) Solutions: \(x = 5\) and \(x = 1.5\)
17

Finding the vertex for part f

Since the function is given in factored form, the vertex's x-coordinate is the average of the roots. \(x_v = \frac{5 + 1.5}{2} = 3.25\) Substitute \(x = 3.25\) into the original function: \(y = -2(5-3.25)(3-2(3.25)) = -2(1.75)(-3.5) = -2(-6.125) = 12.25\) So, the vertex is \((3.25, 12.25)\)
18

Drawing conclusions for part f

The vertex lies above the \(x\)-axis because \(12.25\) is positive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding x-intercepts
X-intercepts, also known as roots or zeros, are points where a function crosses the x-axis. For a quadratic function, the x-intercepts can be found by setting the function equal to zero and solving for x. For example, in the function \(y=(x+2)(x+1)\), set \(y\) to zero and solve for \(x\): \(0=(x+2)(x+1)\). This gives us the solutions \(x = -2\) and \(x = -1\). These are the x-intercepts of the function.
Identifying these points helps in graphing the parabola, as they indicate where the graph crosses or touches the x-axis. Understanding x-intercepts is crucial because:
  • They provide information about the graph's behavior*
  • They help locate the vertex*
  • They are essential in solving quadratic equations
Exploring the Vertex Form
The vertex form of a quadratic function makes it easy to identify the vertex of the parabola. The vertex form is given by \(y = a(x - h)^{2} + k\), where \((h,k)\) is the vertex. For example, the equation \(y=-4(x+3)^{2}\) is in vertex form, where the vertex is at \((-3, 0)\).
To convert a quadratic function into vertex form if it is not already, you can complete the square or use the formula for the vertex coordinates from the standard form. Understanding the vertex form is useful because:
  • It allows you to easily identify the maximum or minimum point of the parabola
  • It simplifies the process of graphing the function
  • It provides insight into the transformation of the graph, such as shifts and reflections
Graphing Quadratic Functions
Graphing a quadratic function involves plotting the vertex, the x-intercepts, and other key points to draw the parabola. Here are the steps to graphing a quadratic function:
1. Identify the x-intercepts by setting the function equal to zero and solving for x.
2. Find the vertex of the parabola, which is the highest or lowest point.
3. Plot the vertex and x-intercepts on a coordinate plane.
4. Choose additional points to plot by substituting values for x into the function and solving for y.
5. Draw a smooth curve through the points to complete the parabola.
For instance, graph the function \(y=\frac{1}{2}(x)(x-5)\) by finding the x-intercepts \(x = 0\) and \(x = 5\), and the vertex \((2.5, -3.125)\). Use these points to sketch the graph, and ensure the parabola correctly represents the function.
Factored Form of Quadratic Functions
The factored form of a quadratic function makes it straightforward to find the x-intercepts, as seen in functions like \(y = 3(1-2x)(x+3)\). This form is expressed as \(y = a(x-r_1)(x-r_2)\), where \(r_1\) and \(r_2\) are the roots or x-intercepts.
The factored form is beneficial because:
  • It allows for the immediate identification of x-intercepts
  • It simplifies finding the vertex, which can be calculated as the midpoint of the x-intercepts
  • It provides an efficient way to solve quadratic equations

By rewriting the quadratic equation in factored form, one can quickly outline the graph's shape and key characteristics. For example, the function \(q(x)=2(x-3)(x+2)\) has x-intercepts at \(x = 3\) and \(x = -2\), with a vertex at \((0.5, -12.5)\). This information can then be used to graph the parabola effectively.

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Most popular questions from this chapter

Without drawing the graph, list the following parabolas in order, from the narrowest to the broadest. Verify your results with technology. a. \(y=x^{2}+20\) d. \(y=4 x^{2}\) b. \(y=0.5 x^{2}-1\) e. \(y=0.1 x^{2}+2\) c. \(y=\frac{1}{3} x^{2}+x+1\) f. \(y=-2 x^{2}-5 x+4\)

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The management of a company is negotiating with a union over salary increases for the company's employees for the next 5 years. One plan under consideration gives each worker a bonus of \(\$ 1500\) per year. The company currently employs 1025 workers and pays them an average salary of \(\$ 30,000\) a year. It also plans to increase its workforce by 20 workers a year. a. Construct a function \(C(t)\) that models the projected cost of this plan (in dollars) as a function of time \(t\) (in years). b. What will the annual cost be in 5 years?

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