/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 In each part, construct a polyno... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In each part, construct a polynomial function with the indicated characteristics. a. Crosses the \(x\) -axis at least three times b. Crosses the \(x\) -axis at \(-1,3,\) and 10 c. Has a \(y\) -intercept of 4 and degree of 3 d. Has a \(y\) -intercept of -4 and degree of 5

Short Answer

Expert verified
a. \(P(x) = (x + 1)(x - 2)(x - 3)\), b. \(P(x) = (x + 1)(x - 3)(x - 10)\), c. \(P(x) = -\frac{2}{3}(x + 1)(x - 2)(x - 3)\), d. \(P(x) = -\frac{1}{12}(x + 2)(x - 1)(x - 2)(x - 3)(x - 4)\).

Step by step solution

01

Understanding the Requirements

We need to construct polynomial functions with given characteristics. Each part specifies different conditions for the polynomial.
02

Polynomial for Part A

To cross the x-axis at least three times, the polynomial must have at least three distinct real roots. One possible polynomial is a cubic function: \( P(x) = (x + 1)(x - 2)(x - 3) \). This polynomial has roots at -1, 2, and 3, crossing the x-axis at least three times.
03

Polynomial for Part B

To cross the x-axis at -1, 3, and 10, construct a polynomial with these roots: \( P(x) = (x + 1)(x - 3)(x - 10) \). This ensures the polynomial crosses the x-axis at the specified points.
04

Polynomial for Part C

To have a y-intercept of 4 and degree of 3, start with a cubic polynomial and adjust it to satisfy the y-intercept: \( P(x) = (x + 1)(x - 2)(x - 3) \). Checking the y-intercept, \( P(0) = (-1)(-2)(-3) = -6\). To adjust for a y-intercept of 4, multiply by a constant: \( P(x) = -\frac{2}{3}(x + 1)(x - 2)(x - 3) \).
05

Polynomial for Part D

To have a y-intercept of -4 and degree of 5, construct a degree 5 polynomial and adjust for the y-intercept: \( P(x) = (x + 2)(x - 1)(x - 2)(x - 3)(x - 4) \). Checking the y-intercept, \( P(0) = (2)(-1)(-2)(-3)(-4) = 48\). Adjust for a y-intercept of -4 by multiplying by a constant: \( P(x) = -\frac{1}{12}(x + 2)(x - 1)(x - 2)(x - 3)(x - 4) \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

roots of polynomials
The roots of a polynomial, also known as zeros, are the values of x for which the polynomial is equal to zero. In other words, if you plug a root back into the polynomial, the result is zero.
For example, if we have the polynomial function \( P(x) = (x + 1)(x - 2)(x - 3) \), the roots of this function are -1, 2, and 3. This is because plugging these values into the polynomial will yield zero:
When \( x = -1 \), \( P(-1) = 0 \)
When \( x = 2 \), \( P(2) = 0 \)
When \( x = 3 \), \( P(3) = 0 \)
The importance of roots lies in the fact that they determine where the graph of the polynomial crosses the x-axis. The number of times a polynomial crosses the x-axis is equal to the number of distinct real roots it has.
y-intercept
The y-intercept of a polynomial is the point where the graph of the polynomial crosses the y-axis. To find the y-intercept of a polynomial function \( P(x) \), you simply evaluate the function at \( x = 0 \).
For instance, to find the y-intercept of the polynomial \( P(x) = -\frac{2}{3}(x + 1)(x - 2)(x - 3) \), we substitute \( x \) with 0 and simplify:
\[ P(0) = -\frac{2}{3}(0 + 1)(0 - 2)(0 - 3) \] Simplifying the expression, we get:
\[ P(0) = -\frac{2}{3} \cdot 1 \cdot (-2) \cdot (-3) = -6 \cdot -\frac{2}{3} = 4 \] As a result, the y-intercept of this polynomial is 4. The y-intercept gives us a point on the graph of the polynomial and can be helpful in determining how the polynomial behaves.
degree of polynomial
The degree of a polynomial is the highest power of the variable in the polynomial. It gives us an idea of the overall shape and behavior of the polynomial's graph. Higher degrees usually indicate more complex graphs with more turning points.
For example, in the polynomial \( P(x) = (x + 1)(x - 2)(x - 3) \), if we expand it, we can see that the highest power of \( x \) is 3 since it’s a cubic polynomial:
\( P(x) = x^3 - 4x^2 + x - 6 \)
Therefore, the degree of this polynomial is 3. Generally, a polynomial of degree \( n \) will cross the x-axis at most \( n \) times and can have up to \( n-1 \) turning points or places where the graph changes direction.
constructing polynomials
Constructing polynomials with specific characteristics involves combining these concepts. Suppose you need a polynomial that crosses the x-axis at -1, 3, and 10. You would create a polynomial with roots at these points:
\( P(x) = (x + 1)(x - 3)(x - 10) \)
If the polynomial also needs a specific y-intercept or degree, additional steps are involved. For example, to have a y-intercept of -4 and a degree of 5, you could start with a degree 5 polynomial and adjust it:
\( P(x) = (x+2)(x-1)(x-2)(x-3)(x-4) \)
Finding the y-intercept (where \( x = 0 \)) and then multiplying by an appropriate constant ensures the polynomial has the required y-intercept:
\[ P(0) = 48 \rightarrow P(x) = -\frac{1}{12}(x + 2)(x - 1)(x - 2)(x - 3)(x - 4) \] Constructing polynomials in this way allows you to tailor them to specific requirements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(Graphing program required.) At low speeds an automobile engine is not at its peak efficiency; efficiency initially rises with speed and then declines at higher speeds. When efficiency is at its maximum, the consumption rate of gas (measured in gallons per hour) is at a minimum. The gas consumption rate of a particular car can be modeled by the following equation, where \(G\) is the gas consumption rate in gallons per hour and \(M\) is speed in miles per hour: \(G=0.0002 M^{2}-0.013 M+1.07\) a. Construct a graph of gas consumption rate versus speed. Estimate the minimum gas consumption rate from your graph and the speed at which it occurs. b. Using the equation for \(G,\) calculate the speed at which the gas consumption rate is at its minimum. What is the minimum gas consumption rate? c. If you travel for 2 hours at peak efficiency, how much gas will you use and how far will you go? d. If you travel at \(60 \mathrm{mph}\), what is your gas consumption rate? How long does it take to go the same distance that you calculated in part (c)? (Recall that travel distance = speed \(\times\) time traveled.) How much gas is required for the trip? e. Compare the answers for parts (c) and (d), which tell you how much gas is used for the same-length trip at two different speeds. Is gas actually saved for the trip by traveling at the speed that gives the minimum gas consumption rate? f. Using the function \(G,\) generate data for gas consumption rate measured in gallons per mile by completing the following table. Plot gallons per mile (on the vertical axis) vs. miles per hour (on the horizontal axis). At what speed is gallons per mile at a minimum? g. Add a fourth column to the data table. This time compute miles/gal \(=\mathrm{mph} /(\mathrm{gal} / \mathrm{hr}) .\) Plot miles per gallon vs. miles per hour. At what speed is miles per gallon at a maximum? This is the inverse of the preceding question; we are normally used to maximizing miles per gallon instead of minimizing gallons per mile. Does your answer make sense in terms of what you found for parts (b) and (f)?

Identify the stretch/compression factor and the vertex for each of the following. a. \(y_{1}=0.3(x-1)^{2}+8\) c. \(y_{3}=0.01(x+20)^{2}\) b. \(y_{2}=30 x^{2}-11\) d. \(y_{4}=-6 x^{2}+12 x\)

a. In economics, revenue \(R\) is defined as the amount of money derived from the sale of a product and is equal to the number \(x\) of units sold times the selling price \(p\) of each unit. What is the equation for revenue? b. If the selling price is given by the equation \(p=-\frac{1}{10} x+20,\) express revenue \(R\) as a function of the number \(x\) of units sold. c. Using technology, plot the function and estimate the number of units that need to be sold to achieve maximum revenue. Then estimate the maximum revenue.

Let \(f(x)=x^{3}\). a. Write the equation for the new function \(g(x)\) that results from each of the following transformations of \(f(x)\). Explain in words the effect of the transformations. i. \(f(-x)\) iii. \(f(x+2)\) ii. \(-2 f(x)-1\) iv. \(-f(-x)\) b. Sketch by hand the graph of \(f(x)\) and each function in part (a).

Find the coordinates of the vertex for each quadratic function listed. Then specify whether each vertex is a maximum or minimum. a. \(y=4 x^{2}\) c. \(P(n)=\left(\frac{1}{12}\right) n^{2}\) b. \(f(x)=-8 x^{2}\) d. \(Q(t)=-\left(\frac{1}{24}\right) t^{2}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.