/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 (Graphing program optional.) For... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(Graphing program optional.) For each quadratic function convert to \(a-h-k\) form by using \(h=-\frac{b}{2 a}\) and then find \(k\). If available, use technology to graph the two forms of the function to confirm that they are the same. a. \(y=x^{2}+6 x+13\) d. \(p(r)=-3 r^{2}+18 r-9\) b. \(f(x)=x^{2}-5 x-5\) e. \(m(z)=2 z^{2}+8 z-5\) c. \(g(x)=x^{2}-3 x+6\)

Short Answer

Expert verified
Converting these functions to vertex forms: (a): \(y=(x+3)^2+4\), (b): \(f(x)=(x-2.5)^2-11.25\), (c): \(g(x)=(x-1.5)^2+3.75\), (d): \(p(r)= -3(r-3)^2 +18\), (e): \(m(z)= 2(z+2)^2-13\).

Step by step solution

01

Identify the Quadratic Standard Form

Each function is given in the standard form: \(y=ax^2+bx+c\), \(p(r)=ar^2+br+c\), \(f(x)=ax^2+bx+c\), \(m(z)=az^2+bz+c\), \(g(x)=ax^2+bx+c\).
02

Use the formula for h

To convert to vertex form \(y=a(x-h)^2+k\), we start by finding\(h=-\frac{b}{2a}\).
03

Compute h and k for each function

Compute \(h\) and \(k\) for each of the quadratic functions provided:(a) \(y=x^2+6x+13\),(b) \(f(x)=x^2-5x-5\),(c) \(g(x)=x^2-3x+6\),(d) \(p(r)=-3r^2+18r-9\),(e) \(m(z)=2z^2+8z-5\).
04

Calculate k for each function

For each function, substitute the value of \(h\) into the original quadratic equation to find \(k\).
05

Graph the original and vertex forms

Graph the original standard form and the vertex form for each quadratic function to verify they are equivalent. This step can be done using graphing technology.
06

Example Solution for (a)

For (a) \(y=x^2+6x+13\):1. Identify coefficients: \(a=1\), \(b=6\), \(c=13\).2. Find \(h=-\frac{b}{2a}=-\frac{6}{2(1)}=-3\).3. Find \(k\) by substituting \(h\) into the original equation:\(k=y(-3)=(1)(-3)^2+6(-3)+13=9-18+13=4\).4. Vertex form: \(y=1(x+3)^2+4\).
07

Example Solution for (d)

For (d) \(p(r)=-3r^2+18r-9\):1. Identify coefficients: \(a=-3\), \(b=18\), \(c=-9\).2. Find \(h=-\frac{b}{2a}=-\frac{18}{2(-3)}=3\).3. Find \(k\) by substituting \(h\) into the original equation:\(k=p(3)=(-3)(3)^2+18(3)-9=-27+54-9=18\).4. Vertex form: \(p(r)=-3(r-3)^2+18\).
08

Example Solution for (b)

For (b) \(f(x)=x^2-5x-5\):1. Identify coefficients: \(a=1\), \(b=-5\), \(c=-5\).2. Find \(h=-\frac{b}{2a}=-\frac{-5}{2(1)}=2.5\).3. Find \(k\) by substituting \(h\) into the original equation:\(k=f(2.5)=(1)(2.5)^2-5(2.5)-5=6.25-12.5-5=-11.25\).4. Vertex form: \(f(x)=1(x-2.5)^2-11.25\).
09

Example Solution for (e)

For (e) \(m(z)=2z^2+8z-5\):1. Identify coefficients: \(a=2\), \(b=8\), \(c=-5\).2. Find \(h=-\frac{b}{2a}=-\frac{8}{2(2)}=-2\).3. Find \(k\) by substituting \(h\) into the original equation:\(k=m(-2)=(2)(-2)^2+8(-2)-5=8-16-5=-13\).4. Vertex form: \(m(z)=2(z+2)^2-13\).
10

Example Solution for (c)

For (c) \(g(x)=x^2-3x+6\):1. Identify coefficients: \(a=1\), \(b=-3\), \(c=6\).2. Find \(h=-\frac{b}{2a}=-\frac{-3}{2(1)}=1.5\).3. Find \(k\) by substituting \(h\) into the original equation:\(k=g(1.5)=(1)(1.5)^2-3(1.5)+6=2.25-4.5+6=3.75\).4. Vertex form: \(g(x)=1(x-1.5)^2+3.75\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
Quadratic functions are mathematical expressions of the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. These functions graph as parabolas, which can open upwards or downwards depending on the sign of the leading coefficient, \( a \). Understanding quadratic functions is crucial because they appear in various real-world scenarios, such as projectile motion and area problems.
Key characteristics involve:
  • The vertex, the highest or lowest point on the graph.
  • The axis of symmetry, a vertical line that divides the parabola into two mirror images.
  • The direction in which the parabola opens, defined by the sign of \( a \).
By converting quadratics to vertex form, you simplify the process of identifying these attributes.
Standard Form
The standard form of a quadratic function is \( y = ax^2 + bx + c \). This form is useful for quickly identifying the values of \( a \), \( b \), and \( c \).
  • \( a \): The coefficient of the quadratic term, which influences the width and direction of the parabola.
  • \( b \): The coefficient of the linear term, affecting the position of the vertex horizontally.
  • \( c \): The constant term, representing the y-intercept of the graph.
To convert a quadratic function from standard form to vertex form, you need to find the vertex coordinates. The horizontal coordinate \( h \) is computed using the formula \( h = -\frac{b}{2a} \).
Once \( h \) is found, substitute it back into the original quadratic equation to solve for \( k \), which gives the y-coordinate of the vertex: \( k = y(h) = a(h)^2 + b(h) + c \). This helps form the vertex equation, \( y = a(x-h)^2 + k \).
Graphing Technology
Graphing technology, such as graphing calculators or software (like Desmos), is very helpful when working with quadratic functions. These tools allow you to:
  • Visualize the parabolas easily.
  • Confirm the transformations from standard form to vertex form.
  • Instantly identify the vertex and other characteristics of the graph.
When using graphing technology:
  • Input the quadratic equation in standard form and observe the resulting graph.
  • Transform the quadratic to vertex form and graph it again to ensure both forms produce the same parabola.
  • Utilize zoom and trace features to explore the exact values of critical points, such as the vertex and intercepts.
Using these tools reinforces understanding and provides visual confirmation of mathematical transformations.
Vertex Form
The vertex form of a quadratic function is \( y = a(x-h)^2 + k \), where \( (h, k) \) is the vertex of the parabola. This form makes it easier to graph and understand quadratic functions because:
  • \( h \) represents the x-coordinate of the vertex.
  • \( k \) stands for the y-coordinate of the vertex.
  • \( a \) affects the width and direction of the parabola.
To convert a function from standard form to vertex form, follow these steps:
1. Start with the standard form: \( y = ax^2 + bx + c \).
2. Compute \( h \) using \( h = -\frac{b}{2a} \).
3. Substitute \( h \) back into the original quadratic equation to find \( k \).
4. Write the vertex form as \( y = a(x-h)^2 + k \).
Understanding vertex form simplifies finding the vertex and graphing the quadratic function accurately. It highlights the transformation from the general shape to a specific, vertex-oriented perspective.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises \(16-22,\) show that the two functions are inverses of each other. $$ F(t)=e^{3 t} \text { and } G(t)=\ln \left(t^{1 / 3}\right) $$

If you do an Internet search on formulas for "ideal body weight" (IBW), one that comes up frequently was created by Dr. B. J. Devine. His formula states \(\mathrm{IBW}\) for men (in kilograms) = \(50+(2.3 \mathrm{~kg}\) per inch over 5 feet) IBW for women (in kilograms) = \(45.5+(2.3 \mathrm{~kg}\) per inch over 5 feet) a. Write the functions for IBW (in kg) for men and women, \(W_{\text {mea }}(h)\) and \(W_{\text {wamen }}(h),\) where \(h\) is a person's height in inches. Give a reasonable domain for each. b. Evaluate \(W_{\operatorname{men}}(70)\) and \(W_{\text {womes }}(66) .\) Describe your results in terms of height and weight. c. Evaluate \(W^{-1}\) mea \((77.6) .\) What does this tell you? d. Given that \(1 \mathrm{lb}=0.4356 \mathrm{~kg}\), alter the functions to create \(W_{\text {newmen }}(h)\) and \(W_{\text {acwaomen }}(h)\) so that the weight is given in pounds rather than kilograms. e. Use your functions in part (d) to find \(W^{-1}\) newwomea (125) . What does this tell you?

Complete the following table, and then summarize your findings. $$ \begin{array}{ll} i^{1}=\sqrt{-1}=i & i^{5}=? \\ i^{2}=i \cdot i=-1 & i^{6}=? \\ i^{3}=i \cdot i^{2}=? & i^{7}=? \\ i^{4}=i^{2} \cdot i^{2}=? & i^{8}=? \end{array} $$

A Norman window has the shape of a rectangle surmounted by a semicircle of diameter equal to the width of the rectangle (see the accompanying figure). If the perimeter of the window is 20 feet (including the semicircle), what dimensions will admit the most light (maximize the area)? (Hint: Express \(L\) in terms of \(r\). Recall that the circumference of a circle \(=2 \pi r,\) and the area of a circle \(=\pi r^{2},\) where \(r\) is the radius of the circle.)

Given the function \(g(t)\), identify the simplest function \(f(t)\) (linear, power, exponential, or logarithmic) from which \(g(t)\) could have been constructed. Describe the transformations that changed \(f(t)\) to \(g(t)\) a. \(g(t)=\frac{t-1}{2}\) b. \(g(t)=3\left(\frac{1}{2}\right)^{t+4}\) c. \(g(t)=\frac{-7}{t-5}-2\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.