/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Find the value for \(k\), the co... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the value for \(k\), the constant of proportionality, if: a. \(y=\frac{k}{x}\) and \(y=3\) when \(x=2\). b. \(y=\frac{k}{x^{2}}\) and \(y=\frac{1}{4}\) when \(x=8\). c. \(y=\frac{k}{x^{2}}\) and \(y=\frac{1}{16}\) when \(x=2\). d. \(y=\frac{k}{\sqrt{x}}\) and \(y=1\) when \(x=9\).

Short Answer

Expert verified
a) 6, b) 16, c) 1/4, d) 3

Step by step solution

01

Identify the given relationship (a)

In part (a), the relationship given is: \[y = \frac{k}{x}\]We need to find the constant of proportionality, \(k\), when \(y = 3\) and \(x = 2\).
02

Solve for k (a)

Substitute \(y = 3\) and \(x = 2\) into the equation: \[3 = \frac{k}{2}\]Multiply both sides by 2 to solve for \(k\): \[k = 3 \times 2 = 6\]
03

Identify the given relationship (b)

In part (b), the relationship given is: \[y = \frac{k}{x^{2}}\]We need to find the constant of proportionality, \(k\), when \(y = \frac{1}{4}\) and \(x = 8\).
04

Solve for k (b)

Substitute \(y = \frac{1}{4}\) and \(x = 8\) into the equation: \[\frac{1}{4} = \frac{k}{8^{2}}\]Since \(8^{2} = 64\), the equation becomes: \[\frac{1}{4} = \frac{k}{64}\]Multiply both sides by 64 to solve for \(k\): \[k = 64 \times \frac{1}{4} = 16\]
05

Identify the given relationship (c)

In part (c), the relationship given is: \[y = \frac{k}{x^{2}}\]We need to find the constant of proportionality, \(k\), when \(y = \frac{1}{16}\) and \(x = 2\).
06

Solve for k (c)

Substitute \(y = \frac{1}{16}\) and \(x = 2\) into the equation: \[\frac{1}{16} = \frac{k}{2^{2}}\]Since \(2^{2} = 4\), the equation becomes: \[\frac{1}{16} = \frac{k}{4}\]Multiply both sides by 4 to solve for \(k\): \[k = 4 \times \frac{1}{16} = \frac{1}{4}\]
07

Identify the given relationship (d)

In part (d), the relationship given is: \[y = \frac{k}{\sqrt{x}}\]We need to find the constant of proportionality, \(k\), when \(y = 1\) and \(x = 9\).
08

Solve for k (d)

Substitute \(y = 1\) and \(x = 9\) into the equation: \[1 = \frac{k}{\sqrt{9}}\]Since \(\sqrt{9} = 3\), the equation becomes: \[1 = \frac{k}{3}\]Multiply both sides by 3 to solve for \(k\): \[k = 3 \times 1 = 3\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Direct Variation
Direct variation is when two variables are related in such a way that the ratio of their values always remains constant. In other words, one variable is a constant multiple of the other. The equation representing direct variation is usually written as follows:
\( y=kx \)
where:
  • \( y \) is the dependent variable,
  • \( x \) is the independent variable,
  • \( k \) is the constant of proportionality.
To find the value of \( k \), we can use given values for \( x \) and \( y \), and solve for \( k \) by rearranging the equation. For example, if \( y = 3 \) and \( x = 2 \), then \( k = \frac{y}{x} = \frac{3}{2} = 1.5 \).
This constant \( k \) stays the same for any pair of values, making it clear that the relationship between \( x \) and \( y \) is consistent and proportional.
Inverse Variation
Inverse variation describes a situation where the product of two variables remains constant; as one variable increases, the other decreases. The general form of the equation representing inverse variation is:
\( y = \frac{k}{x} \)
where:
  • \( y \) is the dependent variable,
  • \( x \) is the independent variable,
  • \( k \) is the constant of proportionality.
To determine the constant of proportionality \( k \), you use known values for \( x \) and \( y \), and then solve for \( k \). For instance, if \( y = 3 \) when \( x = 2 \), then \( k = y \times x = 3 \times 2 = 6 \). This shows that for any value of \( x \), multiplying it by the corresponding value of \( y \) will always give 6 in this scenario. Variations can also involve different forms such as \( y = \frac{k}{x^2} \) or \( y = \frac{k}{\sqrt{x}} \), where you would adjust the formula to fit these situations appropriately.
Solving Equations
Solving equations involves finding the value of the variable that makes the equation true. This can be achieved through various methods like substitution, elimination, or using algebraic manipulations.
For the given problems, solving equations largely involves isolating the variable \( k \). Here’s a step-by-step approach using substitution:
  • Identify the relationship and the given values.
  • Substitute the known values into the equation.
  • Rearrange the equation to solve for the unknown variable.
Take, for example, the equation \( y = \frac{k}{x} \), where you need to find \( k \). If given \( y = 3 \) and \( x = 2 \), you substitute these values in and solve for \( k \): \( 3 = \frac{k}{2} \). Multiply both sides by 2 to get \( k = 6 \).
This method ensures clear and systematic solving of equations, helping you always arrive at the correct value for the unknown variable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

a. An insulation blanket for a cylindrical hot water heater is sold in a roll 48 in \(\times 75\) in \(\times 2\) in. Assuming a hot water heater 48 inches high, for what diameter water heater is this insulation blanket made? (Round to the nearest \(\frac{1}{2}\) inch.) b. What is the volume of the hot water heater in part (a)? ( Note: Ignore the thickness of the heater walls.) c. If 1 gallon \(=231\) in \(^{3},\) what is the maximum number of gallons of water that a cylinder the size of this water heater could hold?

(Graphing program optional.) Given \(f(x)=4 x^{2}\), construct a function that is a reflection of \(f(x)\) across the horizontal axis. Graph the functions and confirm your answer.

(Graphing program optional.) In each part, sketch the three graphs on the same grid and label each function. Describe how the three graphs are similar and how they are different. a. \(y_{1}=x^{-1} \quad y_{2}=x^{-3} \quad y_{3}=x^{-5}\) b. \(y_{1}=x^{0} \quad y_{2}=x^{-2} \quad y_{3}=x^{-4}\) c. \(y_{1}=2 x^{-1} \quad y_{2}=4 x^{-1} \quad y_{3}=-2 x^{-1}\)

a. Construct an equation to represent a relationship where w is directly proportional to both \(y\) and \(z\) and inversely proportional to the square of \(x\). b. Assume that \(w=10\) when \(y=12, z=15,\) and \(x=6 .\) Find \(k,\) the constant of proportionality. c. Using your equation from part (b), find \(x\) when \(w=2\), \(y=5,\) and \(z=6\)

The data in the table satisfy the equation \(y=k x^{n}\), where \(n\) is a positive integer. Find \(k\) and \(n\). $$ \begin{array}{ccccc} \hline x & 2 & 3 & 4 & 5 \\ y & 1 & 2.25 & 4 & 6.25 \\ \hline \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.