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Assume that you start with 1000 units of some quantity \(Q\). Construct an exponential function that will describe the value of \(Q\) over time \(T\) if, for each unit increase in \(T, Q\) increases by: a. \(300 \%\) b. \(30 \%\) c. \(3 \%\) d. \(0.3 \%\)

Short Answer

Expert verified
a) \(1000 \times 4^T\), b) \(1000 \times 1.3^T\), c) \(1000 \times 1.03^T\), d) \(1000 \times 1.003^T\).

Step by step solution

01

Understand the Problem

You need to construct exponential functions for different percentage increases in the quantity over time. The general form of an exponential function is given by: \[ Q(T) = Q_0 \times (1 + r)^T \] where \(Q_0\) is the initial quantity, \(r\) is the rate of increase per time unit, and \(T\) is the time.
02

Determine the Initial Quantity

The initial quantity \(Q_0\) is given as 1000 units. This will be the starting point for all the exponential functions.
03

Convert Percentage Increases to Decimal Form

Convert each percentage increase to its decimal form by dividing by 100.- 300% becomes 3.00 - 30% becomes 0.30 - 3% becomes 0.03 - 0.3% becomes 0.003
04

Construct the Exponential Functions

Use the converted rates to construct the functions.(a) For 300%:\[ Q(T) = 1000 \times (1 + 3.00)^T = 1000 \times 4^T \](b) For 30%:\[ Q(T) = 1000 \times (1 + 0.30)^T = 1000 \times 1.3^T \](c) For 3%:\[ Q(T) = 1000 \times (1 + 0.03)^T = 1000 \times 1.03^T \](d) For 0.3%:\[ Q(T) = 1000 \times (1 + 0.003)^T = 1000 \times 1.003^T \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

growth rates
The growth rate is the percentage increase of a quantity over time. In exponential functions, the growth rate plays a crucial role in determining how fast the initial quantity grows. To use a growth rate in calculations, you first need to convert it into decimal form by dividing the percentage value by 100.

An exponential growth rate of 300% becomes 3.00 in decimal form, while 30%, 3%, and 0.3% become 0.30, 0.03, and 0.003, respectively. Using these decimal values in the exponential function helps accurately model the increase over time.

Understanding growth rates helps predict future quantities and analyze trends in various fields like finance, biology, and physics.
exponential growth
Exponential growth occurs when the increase of a quantity is proportional to its current size. This means the larger the quantity gets, the faster it grows.

The general form of an exponential growth function is: \[ Q(T) = Q_0 \times (1 + r)^T \]
where:
  • \(Q_0\) = initial quantity
  • \(r\) = growth rate (in decimal form)
  • \(T\) = time


For example, if you start with 1000 units and have a growth rate of 30%, your exponential growth function would be:
\[ Q(T) = 1000 \times (1 + 0.30)^T = 1000 \times 1.3^T \]

This formula indicates that the quantity grows by 30% every time unit. Exponential growth is powerful because small growth rates can lead to large increases over time. It's important to note how this type of growth can lead to rapid increases in values.
initial quantity (Q0)
The initial quantity, denoted as \( Q_0 \), is the starting value in an exponential function. It's the value you have before any growth occurs.

In our exercise, the initial quantity is given as 1000 units. This serves as the baseline for our exponential functions. No matter the growth rate, every function begins with this initial amount.

The role of the initial quantity is critical in predicting future values. For instance, an initial quantity of 1000 units with a growth rate of 30% will grow faster than if you start with a smaller initial quantity, like 500 units.

Understanding and accurately identifying \( Q_0\) ensures that any calculations, forecasts, or predictions based on the exponential growth model are correct.
time (T)
Time, denoted as \( T \), is a fundamental variable in exponential functions. It represents the period over which the growth occurs.

In the exponential function \[ Q(T) = Q_0 \times (1 + r)^T \], time affects how many times the growth rate \( r \) is applied to the initial quantity \(Q_0 \). Each unit increase in \( T \) applies the growth rate once.

For example, if \( T \) is 5 years and the growth rate is 30% per year, the function becomes:
\[ Q(5) = 1000 \times (1 + 0.30)^5 \]

This means the initial quantity grows by 30% each year for 5 years, resulting in substantial growth over the period.

Time allows us to project future quantities and understand how quickly growth can escalate. Keeping track of \( T \) is critical for long-term planning and analysis.

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Most popular questions from this chapter

MCI, a phone company that provides long-distance service, introduced a marketing strategy called "Friends and Family." Each person who signed up received a discounted calling rate to ten specified individuals. The catch was that the ten people also had to join the "Friends and Family" program. a. Assume that one individual agrees to join the "Friends and Family" program and that this individual recruits ten new members, who in turn each recruit ten new members, and so on. Write a function to describe the number of new people who have signed up for "Friends and Family" at the \(n\) th round of recruiting. b. Now write a function that would describe the total number of people (including the originator) signed up after \(n\) rounds of recruiting. c. How many "Friends and Family" members. stemming from this one person, will there be after five rounds of recruiting? After ten rounds? d. Write a 60 -second summary of the pros and cons of this recruiting strategy. Why will this strategy eventually collapse?

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On November \(25,2003,\) National Public Radio did a report on Under Armour, a sports clothing company, stating that their "profits have increased by \(1200 \%\) in the last 5 years." a. Let \(P(t)\) represent the profit of the company during every 5-year period, with \(A_{0}\) the initial amount. Write the exponential model for the company's profit. b. Assuming an initial profit of \(\$ 100,000,\) what would be the profit in year 5 ? Year \(10 ?\) c. Determine the \(a n n u a l\) growth rate for Under Armour.

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