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Rewrite the following statements using logs: a. \(10^{2}=100\) b. \(10^{7}=10,000,000\) c. \(10^{-3}=0.001\) Rewrite the following statements using exponents: d. \(\log 10=1\) e. \(\log 10,000=4\) f. \(\log 0.0001=-4\)

Short Answer

Expert verified
a. \( \text{log}_{10}(100) = 2 \) b. \( \text{log}_{10}(10,000,000) = 7 \) c. \( \text{log}_{10}(0.001) = -3 \) d. \(10^1 = 10 \) e. \( 10^4 = 10,000 \) f. \( 10^{-4} = 0.0001 \).

Step by step solution

01

Understanding Logarithms

Logarithms are the inverses of exponentiations. In other words, \( \text{if} \ a^b = c, \ \text{then} \ \log_a(c) = b \).
02

Converting Equation a to Logarithms

Given equation: \(10^2 = 100\). In logarithmic form, \( \text{log}_{10}(100) = 2 \).
03

Converting Equation b to Logarithms

Given equation: \( 10^7 = 10,000,000 \). In logarithmic form, \( \text{log}_{10}(10,000,000) = 7 \).
04

Converting Equation c to Logarithms

Given equation: \( 10^{-3} = 0.001 \). In logarithmic form, \( \text{log}_{10}(0.001) = -3 \).
05

Understanding Exponents

To convert from logarithms to exponents, the equation \( \text{log}_a (b) = c \) can be written as \( a^c = b \).
06

Converting Equation d to Exponents

Given equation: \( \text{log}_{10} (10) = 1 \). In exponential form, \( 10^1 = 10 \).
07

Converting Equation e to Exponents

Given equation: \( \text{log}_{10} (10,000) = 4 \). In exponential form, \( 10^4 = 10,000 \).
08

Converting Equation f to Exponents

Given equation: \( \text{log}_{10} (0.0001) = -4 \). In exponential form, \( 10^{-4} = 0.0001 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Operations
Inverse operations are fundamental in mathematics. They are operations that undo each other. For example, addition and subtraction are inverse operations. If you add a number and then subtract the same number, you get back to your starting value. Similarly, multiplication and division are inverses.
In the context of logarithms and exponents, these operations are also inverses of each other. If you start with an exponential function like \(10^2 = 100\), taking the logarithm base 10 of 100 would return you back to 2: \( \text{log}_{10}(100) = 2 \). This relationship helps in solving different types of equations where either logarithms or exponents appear.
Logarithmic Functions
A logarithm answers the question: To what exponent must we raise a given base to get a certain number? For instance, if you have \(10^2 = 100\), then \( \text{log}_{10}(100) = 2\). This tells you that 10 raised to the power of 2 equals 100.
Logarithmic functions are particularly useful for solving equations where the variable is an exponent. They appear in many scientific fields such as biology, astronomy, and economics.
Common properties of logarithms include:
  • \( \text{log}_a(b \times c) = \text{log}_a(b) + \text{log}_a(c) \)
  • \( \text{log}_a(\frac{b}{c}) = \text{log}_a(b) - \text{log}_a(c) \)
  • \( \text{log}_a(b^c) = c \times \text{log}_a(b) \)
  • \( \text{log}_a(a) = 1 \)
  • \( \text{log}_a(1) = 0 \)
These properties can simplify complex calculations and are powerful tools in algebra and calculus.
Exponential Functions
Exponential functions involve constant rates of growth or decay. They have the form \( f(x) = a \times b^{x} \), where 'a' is a constant, 'b' is the base, and 'x' is the exponent. In such functions, the variable appears in the exponent.
One of the most common bases is 10, especially in scientific notation. For instance, \(10^3 = 1000\), which means 10 raised to the power of 3 is 1000.
Exponential functions are the opposite of logarithmic functions. Transforming a logarithm back into an exponential form can simplify many problems. If you have \( \text{log}_{10}(1000) = 3 \), you can rewrite it as \(10^3 = 1000\).
Exponential functions model many real-world phenomena:
  • Population growth
  • Radioactive decay
  • Interest calculation in finance
  • Growth of bacteria
Understanding exponential functions is crucial in various fields like physics, finance, and computer science.

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Most popular questions from this chapter

A homeowner would like to spread shredded bark (mulch) over her flowerbeds. She has three flowerbeds measuring \(25 \mathrm{ft}\) by \(3 \mathrm{ft}, 15 \mathrm{ft}\) by \(4 \mathrm{ft},\) and \(30 \mathrm{ft}\) by \(1.5 \mathrm{ft}\). The recommended depth for the mulch is 4 inches, and the shredded bark costs \(\$ 27.00\) per one cubic yard. How much will it cost to cover all of the flowerbeds with shredded bark? (Note: You cannot buy a portion of a cubic yard of mulch.)

A nanosecond is \(10^{-9}\) second. Modern computers can perform on the order of one operation every nanosecond. Approximately how many feet does an electrical signal moving at the speed of light travel in a computer in 1 nanosecond?

Rewrite the following equations using logs instead of exponents. Estimate a solution for \(x\) and then check your estimate with a calculator. Round the value of \(x\) to three decimal places. a. \(10^{x}=153\) b. \(10^{x}=153,000\) c. \(10^{x}=0.125\) d. \(10^{x}=0.00125\)

Evaluate and write the result using scientific notation: a. \(\left(2.3 \cdot 10^{4}\right)\left(2.0 \cdot 10^{6}\right)\) b. \(\left(3.7 \cdot 10^{-5}\right)\left(1.1 \cdot 10^{8}\right)\) c. \(\frac{8.19 \cdot 10^{23}}{5.37 \cdot 10^{12}}\) d. \(\frac{3.25 \cdot 10^{8}}{6.29 \cdot 10^{15}}\) e. \(\left(6.2 \cdot 10^{52}\right)^{3}\) f. \(\left(5.1 \cdot 10^{-11}\right)^{2}\)

The difference in the noise levels of two sounds is measured in decibels, where decibels \(=10 \log \left(\frac{I_{2}}{I_{1}}\right)\) and \(I_{1}\) and \(I_{2}\) are the intensities of the two sounds. Compare noise levels when \(I_{1}=10^{-15}\) watts/cm \(^{2}\) and \(I_{2}=10^{-8}\) watts \(/ \mathrm{cm}^{2}\).

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