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Without using a calculator, find two consecutive integers such that one is smaller and one is larger than each of the following (for example, \(3<\sqrt{11}<4\) ). Show your reasoning. a. \(\sqrt{13}\) b. \(\sqrt{22}\) c. \(\sqrt{40}\)

Short Answer

Expert verified
a. 3, 4 b. 4, 5 c. 6, 7

Step by step solution

01

Identify perfect squares around the number - Part (a)

Find two integers such that their squares are closest to the number inside the square root. For \(\sqrt{13}\), consider 9 (since \(3^2 = 9\)) and 16 (since \(4^2 = 16\)).
02

Determine integers for Part (a)

It follows that \(3 < \sqrt{13} < 4\).
03

Identify perfect squares around the number - Part (b)

For \(\sqrt{22}\), consider 16 (since \(4^2 = 16\)) and 25 (since \(5^2 = 25\)).
04

Determine integers for Part (b)

It follows that \(4 < \sqrt{22} < 5\).
05

Identify perfect squares around the number - Part (c)

For \(\sqrt{40}\), consider 36 (since \(6^2 = 36\)) and 49 (since \(7^2 = 49\)).
06

Determine integers for Part (c)

It follows that \(6 < \sqrt{40} < 7\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Consecutive Integers
When finding the square root of a number, a useful approach to estimate it is to identify two consecutive integers. These are numbers that follow each other in order. For example, 3 and 4 are consecutive integers, and so are 10 and 11. Consecutive integers differ by exactly one unit.

In the given exercise, we find two consecutive integers such that one is smaller and one is larger than the given square root. It makes finding the square root more intuitive.

Let's take \( \sqrt{13} \) as an example:

  • First, look for perfect squares near the number 13.
  • The perfect squares 9 (from \(3^2\)) and 16 (from \(4^2\)) are close to 13.
  • Thus, \(\sqrt{13}\) must lie between 3 and 4.
This process applies to any number whose square root you need to estimate. By identifying consecutive integers, you can better understand how to approximate square roots in general.
Perfect Squares
Perfect squares are numbers that can be expressed as the product of an integer with itself. For example, 9 is a perfect square because it is \(3 \times 3 = 9\). Similarly, 16 is a perfect square because \(4 \times 4 = 16\).

When we are finding the square root of a number that’s not a perfect square, knowing the perfect squares around it helps. For instance, in the exercise:

  • For \( \sqrt{13} \), we look at perfect squares like 9 and 16.
  • For \( \sqrt{22} \), we consider 16 and 25.
  • For \( \sqrt{40} \), we consider 36 and 49.
Knowing these perfect squares around the number gives a clear boundary for the actual square root. For example, 13 is between 9 and 16, so \( \sqrt{13}\) is between 3 and 4.

This way, perfect squares simplify the process of estimating square roots and help identify the consecutive integers bounding the square root.
Inequalities
Inequalities are expressions that show the relationship between two values when they are not equal. They use symbols like < (<) and > (>). Here’s an example from the exercise:

For \( \sqrt{13} \), we determine the relationship to be \( 3 < \sqrt{13} < 4 \).

This inequality shows that the value of \( \sqrt{13} \) is greater than 3 but less than 4. The same reasoning applies to the other parts of the exercise:
  • For \( \sqrt{22} \): \( 4 < \sqrt{22} < 5 \).
  • For \( \sqrt{40} \): \( 6 < \sqrt{40} < 7 \).
By understanding how to express these relationships using inequalities, students can clearly articulate the bounds within which the actual square root lies.

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Most popular questions from this chapter

Rewrite the following equations using exponents instead of logs. Estimate a solution for \(x\) and then check your estimate with a calculator. Round the value of \(x\) to the nearest integer. a. \(\log x=1.255\) b. \(\log x=3.51\) c. \(\log x=4.23\) d. \(\log x=7.65\)

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Computer technology refers to the storage capacity for information with its own special units. Each minuscule electrical switch is called a "bit" and can be off or on. As the information capacity of computers has increased, the industry has developed some much larger units based on the bit: 1 byte \(=8\) bits 1 kilobit \(=2^{10}\) bits, or 1024 bits (a kilobit is sometimes abbreviated Kbit) kilobyte \(=2^{10}\) bytes, or 1024 bytes (a kilobyte is sometimes abbreviated Kbyte) megabit \(=2^{20}\) bits, or 1,048,576 bits megabyte \(=2^{20}\) bytes, or 1,048,576 bytes gigabyte \(=2^{30}\) bytes, or 1,073,741,824 bytes a. How many kilobytes are there in a megabyte? Express your answer as a power of 2 and in scientific notation. b. How many bits are there in a gigabyte? Express your answer as a power of 2 and in scientific notation.

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Write each of the following in scientific notation: a. 0.00029 d. 0.00000000001 $$ \text { g. }-0.0049 $$ b. 654.456 e. 0.00000245 c. 720,000 $$ \text { f. }-1,980,000 $$

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