/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 On the same axes, graph (and lab... [FREE SOLUTION] | 91Ó°ÊÓ

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On the same axes, graph (and label with the correct equation) three lines that go through the point (0,2) and have the following slopes: a. \(m=\frac{1}{2}\) b. \(m=2\) c. \(m=\frac{5}{6}\)

Short Answer

Expert verified
The equations are: \(y = \frac{1}{2}x + 2\), \(y = 2x + 2\), and \(y = \frac{5}{6}x + 2\). Plot these on the same graph.

Step by step solution

01

Understand the Point-Slope Form

The point-slope form of a line equation is given by \( y = mx + c \), where \(m\) is the slope and \(c\) is the y-intercept. In this problem, all lines pass through the point (0,2), so the y-intercept \(c\) for each line is 2.
02

Write the Equation for Each Slope

Using the point-slope form with point (0,2), write the equations for each given slope: a. For slope \(m= \frac{1}{2}\): \( y = \frac{1}{2}x + 2 \) b. For slope \(m=2\): \( y = 2x + 2 \) c. For slope \(m=\frac{5}{6}\): \( y = \frac{5}{6}x + 2 \)
03

Plot the Equations on the Graph

On a graph with axes, plot the lines corresponding to these equations. Start by plotting the y-intercept at (0,2) for all three lines. Then, use the given slopes to determine the rise over run for each line: a. For \( y = \frac{1}{2}x + 2 \), starting from (0,2), move up 1 unit and right 2 units. b. For \( y = 2x + 2 \), starting from (0,2), move up 2 units and right 1 unit. c. For \( y = \frac{5}{6}x + 2 \), starting from (0,2), move up 5 units and right 6 units. Draw and label each line accordingly.
04

Check and Label Your Graph

Make sure each line is clearly labeled with its respective equation so it’s easy to identify: a. The line for \( y = \frac{1}{2}x + 2\) b. The line for \( y = 2x + 2\) c. The line for \( y = \frac{5}{6}x + 2\) Check that all lines accurately pass through the shared point (0,2).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

slope
The slope of a line describes its steepness and is represented by the letter \(m\).
The slope is calculated as the 'rise over run', or the change in the y-coordinate divided by the change in the x-coordinate between two points.
For example, in the line equation \(y = \frac{1}{2}x + 2\), the slope is \(\frac{1}{2}\), meaning for every 2 units you move to the right on the x-axis, you will move up 1 unit on the y-axis.
Slopes can be positive, negative, or even zero. A positive slope means the line goes up as you move to the right. A negative slope means the line goes down. A zero slope is a horizontal line. For instance, a slope of 2 means you will rise 2 units for each unit you move to the right.
y-intercept
The y-intercept is where a line crosses the y-axis. This point is crucial to graphing linear equations.
It is represented by the letter \(c\) in the equation \(y = mx + c\).
In the given problem, all lines pass through the y-intercept \(c = 2\), where they cross the y-axis at the point (0,2).
To find the y-intercept from the equation, set \(x = 0\). If your equation is \(y = \frac{5}{6}x + 2\), substitute 0 for \(x\), which makes \(y = 2\).
Thus, the graph touches the y-axis at 2. Always start your graph at the y-intercept.
This strategy simplifies plotting the entire line.
point-slope form
The point-slope form of a linear equation helps easily graph a line when you know the slope and a point on the line.
It is generally written as \ (y - y_1) = m(x - x_1) \. Here, \(m\) is the slope and \( (x_1,y_1) \) is the given point.
For the point (0,2) and slope \ (\frac{1}{2}) \, the equation becomes \ y - 2 =\frac{1}{2} (x - 0) \.
Solving for \ y \, you get \ y =\frac{1}{2}x + 2 \.
You can apply this formula to any slope and point. This form makes it easier when lines have various slopes but share the same y-intercept.
Hence, each of the given equations starts with y = and ends with 2 as the y-intercept is fixed at that value.
linear equations
Linear equations graph as straight lines and have the form \ y = mx + c \. Here, \(m\) is the slope and \(c\) is the y-intercept.
They represent the relationship between two variables resulting in a straight line when plotted.
The general solution steps: find the y-intercept, use the slope to determine the next points, and draw the line.
In these exercises, you plot each equation by starting at the y-intercept (0,2), and using the slopes \ (\frac{1}{2}), (2), (\frac{5}{6}) \ to find subsequent points.
Each line must pass through the y-intercept and extend left/right according to its slope.
Practicing with different slopes can help understand how lines behave in a graph and aid in solving linear equation problems.

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