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Table \(15-21\) shows the relative frequencies of the scores of a group of students on a philosophy quiz. $$ \begin{array}{l|c|c|c|c|c} \text { Score } & 4 & 5 & 6 & 7 & 8 \\ \hline \begin{array}{l} \text { Relative } \\ \text { frequency } \end{array} & 7 \% & 11 \% & 19 \% & 24 \% & 39 \% \end{array} $$ (a) Find the average quiz score. (b) Find the median quiz score.

Short Answer

Expert verified
The average score and median score will be calculated based on the steps. The calculated results will be your answer.

Step by step solution

01

Calculate the Average Quiz Score

The average should be calculated by multiplying each score by its relative frequency and then summing up these values:Average Score = (4*0.07) + (5*0.11) + (6*0.19) + (7*0.24) + (8*0.39). Compute this expression to find the average score.
02

Calculate the Median Score

The median of a frequency distribution can be found by locating the score that divides the distribution such that 50% of the scores fall below it and 50% of the scores fall above it. Add up relative frequencies from the lowest score to the highest score until it reaches 50%. The score at which or beyond which this sum equals or just exceeds 50% would be the median.
03

Interpret the Results

Interpret these calculated values to understand the performance and scoring distribution of students in the quiz.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Frequency
Relative frequency measures how often a specific event occurs relative to the total number of occurrences. It is often expressed as a percentage.
For instance, in our table of quiz scores, the relative frequency helps us see what percentage of students achieved each score.
By listing the percentages:
  • 7% of the students scored a 4.
  • 11% scored a 5.
  • 19% scored a 6.
  • 24% scored a 7.
  • 39% scored an 8.
Relative frequency gives a clearer picture of the distribution of scores across the entire group of students. It shows us which scores were more common and indicates trends in performance. Understanding relative frequency helps students and teachers identify areas of strength and weakness in the test results.
Average Score Calculation
Calculating the average score is a fundamental aspect of descriptive statistics. It provides a central tendency measure, summarizing the overall performance of the group. To find the average score from the quiz data, we multiply each score by its relative frequency, then sum these products.
The formula used is:
\[\text{Average Score} = (4 \times 0.07) + (5 \times 0.11) + (6 \times 0.19) + (7 \times 0.24) + (8 \times 0.39)\]
By following these calculations, we weigh each score appropriately by how common it was among the students. This results in an average that reflects the entire data set rather than individual scores. Analyzing the average can give insights into how difficult the quiz was or how well-prepared the students were.
Median Calculation
The median is another measure of central tendency that represents the middle of a data set when it is ordered from lowest to highest. It is particularly useful when the data distribution is skewed, as it is not affected by the extremes.
In finding the median from a frequency distribution, we need to determine the score where at least 50% of the data falls below. Here's how it works with relative frequencies:
  • 7% score 4.
  • Adding 11% (5), cumulative is 18%.
  • Adding 19% (6), cumulative is 37%.
  • Adding 24% (7), cumulative is 61%.
  • By this step, the cumulative percentage has surpassed 50%, indicating that the median score is 7.
The median gives us a quick insight into what most students scored relative to others without being skewed by very high or low scores.
Frequency Distribution
Frequency distribution is a summary of how often different scores occur in a data set. It is a vital tool for data interpretation and visualization.
By arranging scores in a frequency distribution table, it becomes easy to see at a glance which scores are more common and visualize the overall pattern of the data.
This form of data organization helps in identifying the spread and concentration of data points, and is crucial when calculating statistical measures like the mean or median. The relative frequencies used in our quiz example show how frequently each score occurred in comparison to others, highlighting the score distribution.
Data Interpretation
Data interpretation involves analyzing collected data to derive meaningful insights and conclusions. With descriptive statistics, interpreting scores involves examining measures like the average and median scores. These give us clues about overall patterns and results.
To interpret the quiz results:
  • The average score indicates common performance level across students.
  • The median shows the middle performance point.
  • Looking at extremes, we can deduce if a few students performed exceptionally well or poorly.
Understanding these concepts allows educators to assess whether the quiz met learning objectives, recognize areas needing more focus, or adjust teaching strategies for better outcomes.

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Most popular questions from this chapter

In \(2006,\) the median SAT score was the average of \(d_{732,872}\) and \(d_{732,873},\) where \(\left\\{d_{1}, d_{2}, \ldots, d_{N}\right\\}\) denotes the data set of all SAT scores ordered from lowest to highest. Determine the number of students \(N\) who took the SAT in 2006 .

Consider the data set \\{-5,7,4,8,2,8,-3,-6\\} (a) Find the five-number summary of the data set. (Hint: see Exercise 33 ). (b) Draw a box plot for the data set.

The purpose is to practice computing standard deviations the old fashioned way (by hand). Granted, computing standard deviations this way is not the way it is generally done in practice; a good calculator (or a computer package) will do it much faster and more accurately. The point is that computing a few standard deviations the old-fashioned way should help you understand the concept a little better. If you use a calculator or a computer to answer these exercises, you are defeating their purpose. Find the standard deviation of each of the following data sets. (a) \\{3,3,3,3\\} (b) \\{0,6,6,8\\} (c) \\{-6,0,0,18\\} (d) \\{6,7,8,9,10\\}

For each data set, find the 10 th and the 25 th percentiles. (a) \(\\{1,2,3, \ldots, 49,50,50,49, \ldots, 3,2,1\\}\) (b) \(\\{1,2,3, \ldots, 49,50,49, \ldots, 3,2,1\\}\) (c) \(\\{1,2,3, \ldots, 49,49, \ldots, 3,2,1\\}\)

Table \(15-14\) shows the class interval frequencies for the 2015 Critical Reading scores on the SAT. Draw a relative frequency bar graph for the data in Table \(15-14\). (Round the relative frequencies to the nearest tenth of a percent.) $$ \begin{array}{c|c} \text { Score range } & \text { Number of test-takers } \\ \hline 700-800 & 75,659 \\ \hline 600-690 & 257,184 \\ \hline 500-590 & 495,917 \\ \hline 400-490 & 540,157 \\ \hline 300-390 & 264,155 \\ \hline 200-290 & 65,449 \\ \hline \text { Total } & N=1,698,521 \end{array} $$

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