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91Ó°ÊÓ

According to the University of Nevada Center for Logistics Management, \(6 \%\) of all merchandise sold in the United States is returned ( Business Week , January 15,2007 ). A Houston department store sampled 80 items sold in January and found that 12 of the items were returned. a. Construct a point estimate of the proportion of items returned for the population of sales transactions at the Houston store. b. Construct a \(95 \%\) confidence interval for the porportion of returns at the Houston store. c. Is the proportion of returns at the Houston store significantly different from the returns for the nation as a whole? Provide statistical support for your answer.

Short Answer

Expert verified
a. The point estimate is 0.15. b. The 95% confidence interval is (0.0698, 0.2302). c. Yes, the proportion is significantly different from the national standard.

Step by step solution

01

Calculate the Use Sample Proportion

To calculate the sample proportion of items returned at the Houston department store, use the formula \[\hat{p} = \frac{x}{n},\]where \(x\) is the number of returned items, and \(n\) is the total number of items sampled.Here, \(x = 12\) and \(n = 80\). So, the sample proportion is \[\hat{p} = \frac{12}{80} = 0.15.\]
02

Calculate the Standard Error

The standard error (SE) of the sample proportion is calculated using the formula \[SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}},\]where \(\hat{p}\) is the sample proportion and \(n\) is the sample size.Substituting the known values:\[SE = \sqrt{\frac{0.15 \times 0.85}{80}} \approx 0.0407.\]
03

Construct a 95% Confidence Interval

To construct a 95% confidence interval for the sample proportion, we use the formula \[\hat{p} \pm z \times SE,\]where \(z\) is the z-score corresponding to the desired confidence level. For a 95% confidence interval, \(z \approx 1.96\).The confidence interval is:\[0.15 \pm 1.96 \times 0.0407 = (0.0698, 0.2302).\]
04

Formulate and Conduct Hypothesis Test

To determine if the proportion at the Houston store is different from the national standard of 0.06, set up the hypotheses:- Null Hypothesis (\(H_0\)): The Houston store's return rate is 6% (\(p = 0.06\)).- Alternative Hypothesis (\(H_a\)): The Houston store's return rate is not 6% (\(p eq 0.06\)).Calculate the test statistic:\[z = \frac{\hat{p} - p_0}{SE},\]where \(p_0 = 0.06\) and \(SE = \sqrt{\frac{p_0(1-p_0)}{n}}\).\[z = \frac{0.15 - 0.06}{\sqrt{\frac{0.06 \times 0.94}{80}}} \approx 2.88.\]Compare this z-score to the critical value of \(1.96\). Since \(|2.88| > 1.96\), reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point Estimate
When statisticians talk about a point estimate, they are referring to a single value that serves as an estimate of a population parameter. In our exercise, the point estimate is the sample proportion of items returned at a store.
  • To obtain the point estimate, you calculate the sample proportion, \( \hat{p} \).
  • This is done by dividing the number of successes (returned items) by the total number of observations (total items sampled).
For the given problem, we've seen that the point estimate is calculated as \( \hat{p} = \frac{x}{n} \), where \( x = 12 \) (number of returned items) and \( n = 80 \) (total items sampled). Hence, the point estimate, or sample proportion, is \( \hat{p} = \frac{12}{80} = 0.15 \). This estimate tells us that around 15% of the sampled items were returned, which serves as a practical estimate of the overall return rate at the Houston store.
Sample Proportion
The sample proportion is a fundamental concept in statistical analysis, especially in scenarios like our exercise where you want to infer about a larger population based on a sample.
  • It is represented by \( \hat{p} \) and calculated using the formula \( \hat{p} = \frac{x}{n} \).
  • Here, \( x \) is the number of sampled observations with the desired attribute (e.g., returns), and \( n \) is the total sample size.
This value makes it easier to estimate other statistical measures, such as confidence intervals or conducting hypothesis tests. In our specific problem, the sample proportion is 0.15, informing us about the rate of returns in the sampled items. Since this is derived from the sample, it might vary from the actual population proportion due to sample variability. However, by understanding this number, decisions about inventory, customer service, and other store operations can be more informed.
Hypothesis Test
Hypothesis testing is a vital statistical method used to determine if there's enough evidence to draw conclusions about a population parameter based on sample data. In our exercise, we're using hypothesis testing to compare the store's return rate against the national average.
  • The null hypothesis \( H_0 \) suggests that the proportion of returns at the Houston store is the same as the national rate, i.e., 6% or 0.06.
  • The alternative hypothesis \( H_a \) posits that the store's return rate differs from this national metric.
The hypothesis test uses a z-test for proportions to compute a test statistic. This involves calculating the standard error using the population proportion in the null hypothesis and comparing the computed z-value against the critical value from the z-distribution.In this exercise, with a calculated z-score of approximately 2.88 and a critical value of 1.96 for a 95% confidence level, we found that \(|2.88| > 1.96\). Thus, we can confidently reject the null hypothesis, concluding that the store's return rate is statistically different from the national average.

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Most popular questions from this chapter

Consider the following hypothesis test: \\[ \begin{array}{l} H_{0}: \mu=15 \\ H_{\mathrm{a}}: \mu \neq 15 \end{array} \\] A sample of 50 provided a sample mean of \(14.15 .\) The population standard deviation is 3 a. Compute the value of the test statistic. b. What is the \(p\) -value? c. \(\quad\) At \(\alpha=.05,\) what is your conclusion? d. What is the rejection rule using the critical value? What is your conclusion?

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