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A researcher reports survey results by stating that the standard error of the mean is \(20 .\) The population standard deviation is 500 a. How large was the sample used in this survey? b. What is the probability that the point estimate was within ±25 of the population mean?

Short Answer

Expert verified
a. The sample size is 625. b. The probability is 78.88%.

Step by step solution

01

Understand the standard error formula

The standard error (SE) of the mean is calculated using the formula \( SE = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the population standard deviation and \( n \) is the sample size. We know \( SE = 20 \) and \( \sigma = 500 \).
02

Solve for the sample size

Plug the known values into the standard error formula: \( 20 = \frac{500}{\sqrt{n}} \). To find \( n \), rearrange the formula: \( \sqrt{n} = \frac{500}{20} = 25 \). Square both sides to solve for \( n \): \( n = 25^2 = 625 \).
03

Compute the probability range

The value ±25 around the mean indicates a range of \( \pm \frac{25}{\sigma/\sqrt{n}} \) of the standard error units. With \( \sigma = 500 \) and \( n = 625 \), \( \sigma/\sqrt{n} = 20 \) as already calculated. So the range becomes \( \frac{25}{20} = 1.25 \) standard error units.
04

Use the standard normal distribution

The probability of being within ±1.25 standard errors of the mean on a normal distribution can be found using a Z-table. The Z-scores ±1.25 correspond to probabilities of approximately 0.8944 (multiplied by 2 to cover both sides of the mean), providing a probability of approximately 0.7888 or 78.88%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The standard error (SE) is a critical concept in inferential statistics, offering insight into how much the sample mean is expected to vary from the true population mean.
Essentially, it's a measure of the reliability of the mean calculated from a sample. The formula to determine the standard error of the mean is given by: \[ SE = \frac{\sigma}{\sqrt{n}} \]where:
  • \( \sigma \) is the population standard deviation
  • \( n \) is the sample size
A smaller standard error suggests that the sample mean is a more accurate reflection of the population mean. In the context of our exercise, the standard error is \( 20 \), indicating how much the sample mean spreads around the population mean. It plays a vital role in calculating confidence intervals and in hypothesis testing.
Understanding the standard error helps researchers decide on the reliability of their survey results, guiding decisions based on statistical evidence.
Sample Size Calculation
Calculating the sample size is vital for ensuring that a study has enough power to detect effects or differences.
In simpler terms, a properly calculated sample size means the study is likely to yield valid and reliable results. The relationship between the sample size, standard error, and population standard deviation is expressed by the formula:\[ SE = \frac{\sigma}{\sqrt{n}} \]In the provided exercise, it's important to solve this equation to find \( n \). Knowing that the standard error is \( 20 \) and the population standard deviation is \( 500 \), we can rearrange the formula:\[ 20 = \frac{500}{\sqrt{n}} \]By solving it, \( \sqrt{n} = 25 \), and squaring both sides, we find that \( n = 625 \).
A larger sample size generally leads to a smaller standard error, meaning the sample mean is more representative of the true population mean. This principle is crucial in designing experiments and interpreting data.
Normal Distribution
The normal distribution is a fundamental concept in statistics, crucial for understanding the behavior of data in many contexts. It is a continuous probability distribution that is symmetrical about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.
In our exercise, we assumed that the data follows a normal distribution to calculate probabilities regarding the sample mean. Within this scenario, the data around the sample mean is expressed in terms of standard error units (SEU). Using the Z-score, which translates these units onto the standard normal curve, we identify the probability that a sample mean is within a specific range of the population mean.
Here, the range of ±1.25 SEU indicates that we are looking at the probability of the sample mean falling within the limits of ±25. Using Z-tables or standard normal distribution tools, the probability was calculated to be approximately 78.88%.
This probability is highly informative, as it quantifies the likelihood of the sample mean being close to the population mean, thus validating the accuracy and reliability of the survey's findings.

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Most popular questions from this chapter

Roper ASW conducted a survey to learn about American adults' attitudes toward money and happiness (Money, October 2003). Fifty-six percent of the respondents said they balance their checkbook at least once a month. a. Suppose a sample of 400 American adults were taken. Show the sampling distribution of the proportion of adults who balance their checkbook at least once a month. b. What is the probability that the sample proportion will be within ±.02 of the population proportion? c. What is the probability that the sample proportion will be within ±.04 of the population proportion?

The average score for male golfers is 95 and the average score for female golfers is 106 (Golf Digest, April 2006). Use these values as the population means for men and women and assume that the population standard deviation is \(\sigma=14\) strokes for both. A simple random sample of 30 male golfers and another simple random sample of 45 female golfers will be taken. a. Show the sampling distribution of \(\bar{x}\) for male golfers. b. What is the probability that the sample mean is within three strokes of the population mean for the sample of male golfers? c. What is the probability that the sample mean is within three strokes of the population mean for the sample of female golfers? d. In which case, part (b) or part (c), is the probability of obtaining a sample mean within three strokes of the population mean higher? Why?

Assume the population standard deviation is \(\sigma=25 .\) Compute the standard error of the mean, \(\sigma_{\bar{x}},\) for sample sizes of \(50,100,150,\) and \(200 .\) What can you say about the size of the standard error of the mean as the sample size is increased?

The following data are from a simple random sample. \\[ 5 \quad 8 \quad 10 \quad 7 \quad 10 \quad 14 \\] a. What is the point estimate of the population mean? b. What is the point estimate of the population standard deviation?

The Cincinnati Enquirer reported that, in the United States, \(66 \%\) of adults and \(87 \%\) of youths ages 12 to 17 use the Internet (The Cincinnati Enquirer, February 7,2006 ). Use the reported numbers as the population proportions and assume that samples of 300 adults and 300 youths will be used to learn about attitudes toward Internet security. a. Show the sampling distribution of \(\bar{p}\), where \(\bar{p}\) is the sample proportion of adults using the Internet. b. What is the probability that the sample proportion of adults using the Internet will be within ±.04 of the population proportion? c. What is the probability that the sample proportion of youths using the Internet will be within ±.04 of the population proportion? d. Is the probability different in parts (b) and (c)? If so, why? e. Answer part (b) for a sample of size 600. Is the probability smaller? Why?

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