/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 The average price of a gallon of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The average price of a gallon of unleaded regular gasoline was reported to be \(\$ 2.34\) in northern Kentucky (The Cincinnati Enquirer, January 21,2006 ). Use this price as the population mean, and assume the population standard deviation is \(\$ .20\). a. What is the probability that the mean price for a sample of 30 service stations is within \(\$ .03\) of the population mean? b. What is the probability that the mean price for a sample of 50 service stations is within \(\$ .03\) of the population mean? c. What is the probability that the mean price for a sample of 100 service stations is within \(\$ .03\) of the population mean? d. Which, if any, of the sample sizes in parts (a), (b), and (c) would you recommend to have at least a .95 probability that the sample mean is within \(\$ .03\) of the population mean?

Short Answer

Expert verified
None of the sample sizes (30, 50, 100) meet the 0.95 probability requirement.

Step by step solution

01

Identify Given Information

Given population mean, \( \mu = 2.34 \) and population standard deviation, \( \sigma = 0.20 \). The problem asks for probabilities within \( \pm 0.03 \) of the mean for different sample sizes.
02

Determine the Standard Error for Each Sample

The standard error (SE) is calculated using \( SE = \frac{\sigma}{\sqrt{n}} \). For \( n = 30, 50, \) and \( 100 \), find the SE.- For \( n=30 \): \( SE = \frac{0.20}{\sqrt{30}} \approx 0.0365 \)- For \( n=50 \): \( SE = \frac{0.20}{\sqrt{50}} \approx 0.0283 \)- For \( n=100 \): \( SE = \frac{0.20}{\sqrt{100}} = 0.020 \)
03

Calculate the Z-score for Each Case

The Z-score is calculated using \( Z = \frac{x - \mu}{SE} \). Here, \( x \) represents the sample mean we want to find the probability for, which is \( \mu \pm 0.03 \). Therefore, \( Z = \frac{0.03}{SE} \). Calculate Z-scores for each sample size:- For \( n=30 \): \( Z = \frac{0.03}{0.0365} \approx 0.82 \)- For \( n=50 \): \( Z = \frac{0.03}{0.0283} \approx 1.06 \)- For \( n=100 \): \( Z = \frac{0.03}{0.020} = 1.5 \)
04

Find the Probability for Each Z-score

Use the standard normal distribution to find probabilities. First, find the probability \( P(Z) \) corresponding to each Z-score:- For \( n=30 \): \( P(-0.82 \leq Z \leq 0.82) \approx 2 \times 0.2939 = 0.5878 \)- For \( n=50 \): \( P(-1.06 \leq Z \leq 1.06) \approx 2 \times 0.3557 = 0.7114 \)- For \( n=100 \): \( P(-1.5 \leq Z \leq 1.5) \approx 2 \times 0.4332 = 0.8664 \)
05

Evaluate and Recommend the Sample Size

To achieve at least a 0.95 probability, we analyze each case:- For \( n=30 \): Probability is 0.5878- For \( n=50 \): Probability is 0.7114- For \( n=100 \): Probability is 0.8664None of the sample sizes meet the 0.95 probability requirement. Therefore, a larger sample size than 100 would be required.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability in statistics is the measure of how likely an event is to occur, given certain conditions. In this exercise, probability is used to evaluate how likely the mean price of gasoline at a sample of service stations is close to the known population mean, which is $2.34.
To calculate probability, we often use the concept of a Z-score, which helps standardize the differences between sample means and population means, making them easier to interpret using a standard normal distribution.
When working with probabilities, it is essential to understand not only how to compute them but also what they mean in a practical context. A higher probability indicates a greater likelihood of observing an event within a certain range, making statistical predictions more reliable.
Sampling Distribution
A sampling distribution refers to the probability distribution of a statistic (like the sample mean) obtained through repeated sampling from a population. In this exercise, we focus on how often we expect the sample mean to fall within a specific range of the population mean when we draw samples of different sizes.
Think of it as gathering a bunch of samples and noting which average happens most frequently. The larger the sample size, the more the sampling distribution of the mean tends to resemble the normal distribution due to the Central Limit Theorem. This effect is crucial in this exercise as we consider sample sizes of 30, 50, and 100.
A well-behaved sampling distribution helps in predicting the likely range of values for the sample mean, given we know the population mean and standard deviation. The shape and spread of the distribution inform us about the likelihood of the sample mean being close to the known population mean.
Standard Error
Standard error (SE) is a key concept in statistics, as it measures how much the sample mean of a population is expected to vary. It gives us an idea of the precision of the sample mean as an estimate of the population mean.
The formula for standard error is given by: \[ SE = \frac{\sigma}{\sqrt{n}} \] where \( \sigma \) is the population standard deviation, and \( n \) is the sample size.
As you can see, the standard error decreases as the sample size increases. This is evident in the exercise where the SE was calculated to be 0.0365, 0.0283, and 0.020 for sample sizes of 30, 50, and 100, respectively. A smaller standard error suggests that the sample mean is a more accurate reflection of the population mean, making our probability calculations more reliable and the predictions more precise.
Population Mean
The population mean, denoted by \( \mu \), is the average of all the individuals in a population. In this exercise, the population mean is given as $2.34 for the price of gasoline per gallon. This value serves as the benchmark for comparison with our sample means.
Understanding the population mean is essential because it helps in setting the frame of reference for any sample mean derived from the population. It tells us what we expect on average when repeatedly sampling from the population.
In practical scenarios, knowing the population mean enables businesses to make informed decisions. For example, in pricing strategies, understanding the mean gas price helps companies stay competitive. It offers a baseline to gauge deviations from typical conditions in the sampled data and ensure processes are aligned with market realities.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A population proportion is \(.40 .\) A simple random sample of size 200 will be taken and the sample proportion \(\bar{p}\) will be used to estimate the population proportion. a. What is the probability that the sample proportion will be within ±.03 of the population proportion? b. What is the probability that the sample proportion will be within ±.05 of the population proportion?

A sample of 50 Fortune 500 companies (Fortune, April 14,2003 ) showed 5 were based in New York, 6 in California, 2 in Minnesota, and 1 in Wisconsin. a. Develop an estimate of the proportion of Fortune 500 companies based in New York. b. Develop an estimate of the number of Fortune 500 companies based in Minnesota. c. Develop an estimate of the proportion of Fortune 500 companies that are not based in these four states.

Three firms carry inventories that differ in size. Firm A's inventory contains 2000 items, firm B's inventory contains 5000 items, and firm C's inventory contains 10,000 items. The population standard deviation for the cost of the items in each firm's inventory is \(\sigma=144\) A statistical consultant recommends that each firm take a sample of 50 items from its inventory to provide statistically valid estimates of the average cost per item. Managers of the small firm state that because it has the smallest population, it should be able to make the estimate from a much smaller sample than that required by the larger firms. However, the consultant states that to obtain the same standard error and thus the same precision in the sample results, all firms should use the same sample size regardless of population size. a. Using the finite population correction factor, compute the standard error for each of the three firms given a sample of size 50 b. What is the probability that for each firm the sample mean \(\bar{x}\) will be within ±25 of the population mean \(\mu ?\)

BusinessWeek surveyed MBA alumni 10 years after graduation \((\text {Business Week} \text { , September } 22,\) 2003 ). One finding was that alumni spend an average of \(\$ 115.50\) per week eating out socially. You have been asked to conduct a follow-up study by taking a sample of 40 of these MBA alumni. Assume the population standard deviation is \(\$ 35\) a. Show the sampling distribution of \(\bar{x}\), the sample mean weekly expenditure for the \(40 \mathrm{MBA}\) alumni. b. What is the probability that the sample mean will be within \(\$ 10\) of the population mean? c. Suppose you find a sample mean of \(\$ 100 .\) What is the probability of finding a sample mean of \(\$ 100\) or less? Would you consider this sample to be an unusually low spending group of alumni? Why or why not?

People end up tossing \(12 \%\) of what they buy at the grocery store (Reader 's Digest, March, 2009 ). Assume this is the true population proportion and that you plan to take a sample survey of 540 grocery shoppers to further investigate their behavior. a. Show the sampling distribution of \(\bar{p},\) the proportion of groceries thrown out by your sample respondents. b. What is the probability that your survey will provide a sample proportion within ±.03 of the population proportion? c. What is the probability that your survey will provide a sample proportion within ±.015 of the population proportion?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.