/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 The mean annual cost of automobi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The mean annual cost of automobile insurance is \(\$ 939\) (CNBC, February 23,2006 ). Assume that the standard deviation is \(\sigma=\$ 245\) a. What is the probability that a simple random sample of automobile insurance policies will have a sample mean within \(\$ 25\) of the population mean for each of the following sample sizes: \(30,50,100,\) and \(400 ?\) b. What is the advantage of a larger sample size when attempting to estimate the population mean?

Short Answer

Expert verified
Larger sample sizes decrease the standard error, increasing the probability that the sample mean is close to the population mean.

Step by step solution

01

Define the Variables

Before tackling the problem, we identify the given values. The population mean \( \mu \) is \( 939 \), and the population standard deviation \( \sigma \) is \( 245 \). We need to find the probability that the sample mean \( \bar{x} \) is within \( 25 \) units of the population mean for different sample sizes \( n = 30, 50, 100, 400 \). This translates to finding \( P(914 \leq \bar{x} \leq 964) \).
02

Calculate the Standard Error

The standard error (SE) of the mean is calculated as \( SE = \frac{\sigma}{\sqrt{n}} \). This measures how much the sample mean \( \bar{x} \) is expected to vary from the population mean \( \mu \). Calculate the SE for each sample size: 30, 50, 100, and 400.
03

Compute the Z-Scores

For each sample size, the Z-scores are computed using the formula \( Z = \frac{\bar{x} - \mu}{SE} \). Here, we find the Z-scores for the sample mean being \( 25 \) units below and above the population mean: \( Z_1 = \frac{914 - 939}{SE} \) and \( Z_2 = \frac{964 - 939}{SE} \).
04

Find the Probabilities Using the Z-Table

Use the Z-scores to find the probabilities from the standard normal distribution (Z-table). The probability that the sample mean is within \( 25 \) units of the population mean is given by \( P(Z_1 \leq Z \leq Z_2) = P(Z_2) - P(Z_1) \). Perform this calculation for each sample size.
05

Analyze the Impact of Sample Size

Compare the probabilities calculated for the different sample sizes. Note how these probabilities increase as the sample size increases, demonstrating that larger sample sizes provide more accurate estimates of the population mean.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
In the world of statistics, the sample size of your data can significantly influence the reliability and accuracy of your conclusions. A sample is a smaller, manageable version of a larger group (the population). When we increase the sample size, we gain more information about the population we are studying, which in turn helps improve the accuracy of our estimates of the population parameters like the mean.

Why does a larger sample size matter? Here are the key advantages:
  • **Greater Accuracy:** A larger sample size diminishes the spread of the sample mean, making it closely reflect the true population mean.
  • **Reduced Sampling Error:** With more data points, the variations caused by chance are diminished, leading to more reliable results.
This exercise demonstrates the principle clearly: as the sample size grows, the probability that the sample mean falls within a specified range of the population mean increases. This happens because larger samples tend to provide a more precise estimate of the population mean.
Standard Error
The Standard Error (SE) is a critical concept when dealing with sample data. It provides a measure of the dispersion or spread of the sample mean around the population mean. Essentially, it tells us how an individual sample mean deviates from the expected population mean.

The formula for calculating SE is:\[ SE = \frac{\sigma}{\sqrt{n}} \]where \( \sigma \) is the population standard deviation, and \( n \) is the sample size.

**Insights from the Formula:**
  • **Inverse Relationship with Sample Size:** As the sample size increases, the SE decreases, indicating more precise estimates of the population parameter.
  • **Reflecting Variability:** SE reflects how much the sample mean might vary from the population mean, providing a gauge of the reliability of our data.
In the exercise, by calculating the SE for specified sample sizes, we can understand the likelihood of the sample mean being within a particular range of the population mean. Smaller SEs mean less variability around the population mean, implying a higher probability of obtaining an accurate estimate.
Probability Calculations
Probability calculations in statistics allow us to determine the likelihood of a specific outcome occurring. Through these calculations, we can assess the range of values (like the sample mean) and the chances of those values falling within certain intervals.

In this context, we are calculating the probability that the sample mean of automobile insurance costs will be within $25 of the actual population mean. Here's how we approach it:
  • **Use of Z-Scores:** First, we calculate Z-scores, which standardize the differently scaled sample means by measuring how many standard errors a raw score is from the mean.
  • **Interval Probability:** We determine the probability of the sample mean falling within two specific Z-scores derived from the interval of interest.
Using a standard normal distribution table (Z-table), we can find these probabilities for each Z-score and compute the probability of the sample mean lying within our defined range. Consequently, these calculations help us draw conclusions about the population with concrete statistical backing.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

BusinessWeek surveyed MBA alumni 10 years after graduation \((\text {Business Week} \text { , September } 22,\) 2003 ). One finding was that alumni spend an average of \(\$ 115.50\) per week eating out socially. You have been asked to conduct a follow-up study by taking a sample of 40 of these MBA alumni. Assume the population standard deviation is \(\$ 35\) a. Show the sampling distribution of \(\bar{x}\), the sample mean weekly expenditure for the \(40 \mathrm{MBA}\) alumni. b. What is the probability that the sample mean will be within \(\$ 10\) of the population mean? c. Suppose you find a sample mean of \(\$ 100 .\) What is the probability of finding a sample mean of \(\$ 100\) or less? Would you consider this sample to be an unusually low spending group of alumni? Why or why not?

A population proportion is \(.40 .\) A simple random sample of size 200 will be taken and the sample proportion \(\bar{p}\) will be used to estimate the population proportion. a. What is the probability that the sample proportion will be within ±.03 of the population proportion? b. What is the probability that the sample proportion will be within ±.05 of the population proportion?

A production process is checked periodically by a quality control inspector. The inspector selects simple random samples of 30 finished products and computes the sample mean product weights \(\bar{x}\). If test results over a long period of time show that \(5 \%\) of the \(\bar{x}\) values are over 2.1 pounds and \(5 \%\) are under 1.9 pounds, what are the mean and the standard deviation for the population of products produced with this process?

The American Association of Individual Investors (AAII) polls its subscribers on a weekly basis to determine the number who are bullish, bearish, or neutral on the short-term prospects for the stock market. Their findings for the week ending March \(2,2006,\) are consistent with the following sample results (AAII website, March 7, 2006). Bullish \(409 \quad\) Neutral \(299 \quad\) Bearish \(291\) Develop a point estimate of the following population parameters. a. The proportion of all AAII subscribers who are bullish on the stock market. b. The proportion of all AAII subscribers who are neutral on the stock market. c. The proportion of all AAII subscribers who are bearish on the stock market.

The following data are from a simple random sample. \\[ 5 \quad 8 \quad 10 \quad 7 \quad 10 \quad 14 \\] a. What is the point estimate of the population mean? b. What is the point estimate of the population standard deviation?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.