/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A simple random sample of 5 mont... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A simple random sample of 5 months of sales data provided the following information: \\[ \begin{array}{lrrrrr} \text {Month:} & 1 & 2 & 3 & 4 & 5 \\ \text {Units Sold:} & 94 & 100 & 85 & 94 & 92 \end{array} \\] a. Develop a point estimate of the population mean number of units sold per month. b. Develop a point estimate of the population standard deviation.

Short Answer

Expert verified
The population mean estimate is 93 units, and the standard deviation estimate is approximately 5.385 units.

Step by step solution

01

Understand the Problem

We have data from 5 months about the number of units sold, and we need to find the point estimate of both the mean and the standard deviation based on this sample data.
02

Calculate the Sample Mean

The sample mean provides an estimate of the population mean. We sum the units sold and divide by the number of months. Calculate as follows: \[ \bar{x} = \frac{94 + 100 + 85 + 94 + 92}{5} = \frac{465}{5} = 93 \] So, the sample mean is 93 units.
03

Compute Deviations from Mean

For each month, find the deviation from the mean: \[(94 - 93), (100 - 93), (85 - 93), (94 - 93), (92 - 93)\] which result in: \[1, 7, -8, 1, -1\].
04

Square Each Deviation

Square each of the deviations calculated in the previous step: \[1^2, 7^2, (-8)^2, 1^2, (-1)^2\] which yields: \[1, 49, 64, 1, 1\].
05

Calculate the Sample Variance

Find the variance by averaging the squared deviations: \[ s^2 = \frac{1 + 49 + 64 + 1 + 1}{4} = \frac{116}{4} = 29\]. Since we have a sample (not the whole population), we divide by \(n - 1\).
06

Compute the Sample Standard Deviation

To find the sample standard deviation, take the square root of the variance: \[ s = \sqrt{29} \approx 5.385 \] units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point Estimate
A point estimate is a single value that serves as an estimate of a population parameter based on sample data. In business statistics, point estimates are commonly used to make inferences about a population, such as the average number of units sold or the average sales revenue within a certain period. Point estimates are derived from calculations based on sample data, and they provide a concise and direct estimate. For example, if a business owner wants to estimate the average number of units sold per month across an entire year, they might use the point estimate of the mean from a sample of a few months' data, like the ones given in our exercise. This estimate helps in strategic planning without resorting to surveying the entire population, which might be costly or time-consuming. To summarize, point estimates are practical and useful tools in statistics, especially in business scenarios that require quick decision-making based on limited data.
Sample Mean
The sample mean, often denoted as \( \bar{x} \), is a statistical measure that provides an estimate of the average value of a dataset. It is calculated by summing every observation in the sample and then dividing that sum by the number of observations. The sample mean is a straightforward yet powerful tool for understanding underlying trends in data. In the sales data example, the sample mean was calculated as follows:- Add up the units sold: \( 94 + 100 + 85 + 94 + 92 = 465 \)- Divide by the number of observations (months): \( \frac{465}{5} = 93 \)This result tells us that, on average, 93 units were sold per month during this 5-month period. The sample mean is essential because it gives businesses a snapshot of their performance in terms of sales or other measured metrics, which aids in identifying both strengths and areas that need improvement.
Standard Deviation
Standard deviation is a measure of variability or dispersion in a dataset. It indicates how spread out the data points are around the mean. A small standard deviation suggests that the data points tend to be close to the mean, whereas a large standard deviation indicates a wide range of values. In calculating the standard deviation for the sample sales data, several steps are involved:- Firstly, find the deviation of each data point from the sample mean, which are \( 1, 7, -8, 1, -1 \) for this data.- Squares of these deviations are calculated to eliminate negative values: \( 1^2, 7^2, (-8)^2, 1^2, (-1)^2 \).- The average of the squared deviations, or variance, is calculated by dividing them by \( n - 1 \), which is the sample size minus one: \( \frac{116}{4} = 29 \).- Finally, the standard deviation is the square root of the variance: \( \sqrt{29} \approx 5.385 \).Understanding standard deviation helps businesses assess the consistency of their performance and identify potential anomalies within the data. For instance, if the standard deviation in unit sales is high, it might indicate a need to stabilize sales through improved forecasting and inventory management strategies.

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Most popular questions from this chapter

The County and City Data Book, published by the Census Bureau, lists information on 3139 counties throughout the United States. Assume that a national study will collect data from 30 randomly selected counties. Use four- digit random numbers from the last column of Table 7.1 to identify the numbers corresponding to the first five counties selected for the sample. Ignore the first digits and begin with the four-digit random numbers \(9945,8364,5702,\) and so on.

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A sample of 50 Fortune 500 companies (Fortune, April 14,2003 ) showed 5 were based in New York, 6 in California, 2 in Minnesota, and 1 in Wisconsin. a. Develop an estimate of the proportion of Fortune 500 companies based in New York. b. Develop an estimate of the number of Fortune 500 companies based in Minnesota. c. Develop an estimate of the proportion of Fortune 500 companies that are not based in these four states.

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