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The American Community Survey showed that residents of New York City have the longest travel times to get to work compared to residents of other cities in the United States (U.S. Census Bureau website, August 2008 ). According to the latest statistics available, the average travel time to work for residents of New York City is 38.3 minutes. a. Assume the exponential probability distribution is applicable and show the probability density function for the travel time to work for a resident of this city. b. What is the probability that it will take a resident of this city between 20 and 40 minutes to travel to work? c. What is the probability that it will take a resident of this city more than one hour to travel to work?

Short Answer

Expert verified
a) The PDF is \( f(x; 0.0261) = 0.0261e^{-0.0261x} \). b) The probability is \( 0.2413 \). c) The probability is \( 0.2096 \).

Step by step solution

01

Understand the Exponential Distribution

The exponential distribution is defined as \( f(x; \lambda) = \lambda e^{-\lambda x} \) for \( x \geq 0 \), where \( \lambda \) is the rate parameter. Given the average travel time (mean) \( \mu = 38.3 \) minutes, we can find the rate parameter as \( \lambda = \frac{1}{\mu} = \frac{1}{38.3} \approx 0.0261 \).
02

Write the Probability Density Function

Substitute \( \lambda \) into the exponential probability density function: \( f(x; 0.0261) = 0.0261 e^{-0.0261 x} \). This function describes the probability distribution of travel times.
03

Calculate Probability Between 20 and 40 Minutes

For \( 20 \leq x \leq 40 \), the probability is found using: \( P(20 \leq x \leq 40) = \int_{20}^{40} 0.0261 e^{-0.0261 x} \, dx \). This can be calculated as:\( = -e^{-0.0261x} \Big|_{20}^{40} = -e^{-1.044} + e^{-0.522} \).
04

Solve Integral for 20 to 40 Minutes

Calculate the necessary terms for the expression: - Calculate \( e^{-1.044} \) \( \approx 0.3521 \) - Calculate \( e^{-0.522} \) \( \approx 0.5934 \)So: \( P(20 \leq x \leq 40) \approx 0.5934 - 0.3521 = 0.2413 \).
05

Calculate Probability of More Than 1 Hour

The probability that a resident takes more than one hour (60 minutes) is:\( P(x > 60) = 1 - P(x \leq 60) = 1 - \int_{0}^{60} 0.0261e^{-0.0261x} \, dx \).Which simplifies to:\( P(x > 60) = e^{-0.0261 \times 60} = e^{-1.566} \approx 0.2096 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
The probability density function (PDF) is a key concept used to describe the behavior of continuous random variables. It provides a powerful tool to understand how probabilities are distributed over different outcomes. For the exponential distribution, the PDF is given by the formula:
\[ f(x; \lambda) = \lambda e^{-\lambda x} \]where:
  • \( x \) is the value of the continuous random variable.
  • \( \lambda \) is the rate parameter, which is the inverse of the mean \( \mu \) (i.e., \( \lambda = \frac{1}{\mu} \)).
In the context of travel time to work for New York City residents, the average travel time is given as 38.3 minutes. Hence, the rate parameter is \( \lambda = \frac{1}{38.3} \approx 0.0261 \). Using this rate, the PDF describing the travel time for New York City residents is:\[ f(x; 0.0261) = 0.0261 e^{-0.0261 x} \]This function helps us determine the probabilities associated with various ranges of travel times.
Travel Time Statistics
Travel time statistics give us insights into how long journeys typically take for commuters, providing a useful basis for calculating probabilities. In our scenario, New York City residents experience an average travel time of 38.3 minutes to get to work.
The exponential distribution is particularly useful for modeling travel times because it represents the time between events in a Poisson process. Assumptions underlying this model include:
  • Events occur continuously and independently at a constant average rate over time.
  • The probability of more than one event occurring in an infinitesimally small time interval is negligible.
For New York City residents, modeling travel times using the exponential distribution simplifies the probability calculations, leveraging the memoryless property of the exponential function, where the future probability is independent of the past.
Probability Calculation
Probabilities for specific travel time intervals can be calculated using the PDF and integration techniques. Let's address two cases for New York City residents' travel times:
Probability of Travel Time Between 20 and 40 Minutes
To calculate this, we find the area under the PDF for \( 20 \leq x \leq 40 \):\[ P(20 \leq x \leq 40) = \int_{20}^{40} 0.0261 e^{-0.0261 x} \, dx \]Using calculus, this integral evaluates to:\[ -e^{-0.0261 \times 40} + e^{-0.0261 \times 20} \]Calculations show \( P(20 \leq x \leq 40) \approx 0.2413 \).
Probability of Travel Time More Than One Hour
To find the probability that a commute takes longer than 60 minutes:\[ P(x > 60) = 1 - \int_{0}^{60} 0.0261e^{-0.0261x} \, dx \]This simplifies to:\[ P(x > 60) = e^{-0.0261 \times 60} \approx 0.2096 \]These calculations allow commuters to understand the likelihood of their journey times and plan accordingly.

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