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A regional director responsible for business development in the state of Pennsylvania is concerned about the number of small business failures. If the mean number of small busi- ness failures per month is \(10,\) what is the probability that exactly four small businesses will fail during a given month? Assume that the probability of a failure is the same for any two months and that the occurrence or nonoccurrence of a failure in any month is independent of failures in any other month.

Short Answer

Expert verified
The probability that exactly four small businesses will fail in a month is approximately 1.83%.

Step by step solution

01

Identify the Distribution

The problem states that the mean number of small business failures per month is \(10\). This suggests the use of a Poisson distribution, since it models the number of events happening in a fixed interval of time with a known average rate of occurrence.
02

Define the Parameters

The Poisson distribution is defined by the parameter \( \lambda \) which is the average (mean) number of occurrences in the interval. In this case, \( \lambda = 10 \), as given for the mean number of small business failures per month.
03

Write the Probability Formula

For a Poisson distribution, the probability of observing \( k \) events (in this case, failures) in the given time period is given by the formula: \[P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}\] Here, \( X \) represents the random variable for the number of failures, \( k = 4 \), and \( \lambda = 10 \).
04

Calculate the Probability

Substitute \( k = 4 \) and \( \lambda = 10 \) into the Poisson probability formula: \[P(X = 4) = \frac{e^{-10} \times 10^4}{4!}\] Calculate this step by step: 1. Calculate \( 10^4 = 10000 \).2. Calculate \( 4! = 24 \).3. Using the constant \( e \approx 2.71828 \), find \( e^{-10} \approx 0.0000454 \).4. The probability \( P(X = 4) \approx \frac{0.0000454 \times 10000}{24} \approx 0.01832 \) or 1.83%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
When trying to understand probability calculation in the context of a Poisson distribution, it is essential to understand the basic formula that represents it. The Poisson distribution is specifically useful in calculating probabilities in situations where you are counting discrete events over a fixed interval, such as the number of business failures per month.

The probability of observing exactly \( k \) events (e.g., failures) which occur randomly but with a known mean rate \( \lambda \) (in our scenario, this is 10 failures) can be derived from the formula:
  • \( P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \)
To solve the problem of finding the probability that exactly 4 businesses fail in a month, simply substitute the known values:
  • Set \( k = 4 \)
  • \( \lambda = 10 \)
By inserting these values into the Poisson distribution formula, you can then calculate the probability step by step. Always make sure to perform each arithmetic operation carefully, and remember that the value of \( e \) (approximately equal to 2.71828) is a constant that arises in many probability contexts.

This methodical approach ensures precision and clarity when calculating probabilities using the Poisson distribution.
Mean Number of Occurrences
The mean number of occurrences is a crucial parameter in any Poisson distribution. It represents the average or expected number of times an event happens within the defined interval. In our exercise, it is labeled as \( \lambda \), which equals 10 business failures per month.

The significance of \( \lambda \) in this context is as follows:
  • \( \lambda \) directly affects the probability outcome, acting as the primary variable in our calculation formula.
  • The higher the \( \lambda \), the more likely you are to observe a greater number of events in your distribution's interval.
  • Conversely, a smaller \( \lambda \) indicates fewer expected events.
Remember, in practice, \( \lambda \) is usually derived from historical or real data figures that give insight into the average performance of the system being analyzed.

In the business scenario outlined here, knowing \( \lambda = 10 \) sets the stage for all subsequent calculations. As such, always ensure your mean value accurately represents the scenario at hand. Understanding this aspect makes other statistical interpretations, such as variances or deviations, more intuitive for advanced calculations.
Random Variable
In probability and statistics, a random variable denotes a variable whose possible outcomes are numerical and arise from some form of chance or randomness. In the Poisson distribution exercise regarding business failures:
  • The random variable \( X \) represents the number of business failures in a month.
This random variable can take on various non-negative integer values such as 0, 1, 2, 3, etc., depending on the situation. In our case, we focus on \( X = 4 \).

In any probability calculation, identifying the random variable is crucial because:
  • It serves as the core element through which probability distributions are understood and defined.
  • The corresponding probability determined by the Poisson formula helps to quantify the likelihood of a specific occurrence.
Understanding random variables allows us to predict and manage real-world outcomes based on historical occurrences, a skill that is particularly valuable in risk management and decision-making processes.

Therefore, when analyzing any given problem, always start by clearly defining what your random variable represents within the larger system.

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