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Simple random sampling uses a sample of size \(n\) from a population of size \(N\) to obtain data that can be used to make inferences about the characteristics of a population. Suppose that, from a population of 50 bank accounts, we want to take a random sample of 4 accounts in order to learn about the population. How many different random samples of 4 accounts are possible?

Short Answer

Expert verified
There are 230300 different random samples possible.

Step by step solution

01

Understand the problem

We need to determine how many different ways we can select 4 accounts from a total of 50 bank accounts. This requires calculating a combination where order does not matter.
02

Set up the combination formula

The formula for combinations is given by \( \binom{N}{n} = \frac{N!}{n!(N-n)!} \), where \(N\) is the total number of items, \(n\) is the number of items to choose, and \(!\) denotes factorial.
03

Substitute the values into the formula

Here, \(N = 50\) and \(n = 4\). Using these values, the formula becomes: \[ \binom{50}{4} = \frac{50!}{4!(50-4)!} = \frac{50!}{4! \, 46!} \].
04

simplify factorial terms

First, calculate the factorial terms. \(50!\) is the product of all integers from 50 to 1, \(4! = 24\), and \(46!\) is the product of all integers from 46 to 1. Note that \(50!\) over \(46!\) simplifies to \(50 \times 49 \times 48 \times 47\) because the other terms cancel each other out.
05

Calculate the numerical result

Perform the multiplication and division: \( 50 \times 49 \times 48 \times 47 = 5527200 \) and then divide this by \(24\). So, \( \frac{5527200}{24} = 230300 \).
06

Conclude the calculation

The number of different random samples of 4 bank accounts from 50 is \(230300\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations
When it comes to selecting a subset from a larger set, combinations are essential. Combinations help us determine how many ways we can choose a certain number of items from a larger collection, without regard to the order of selection. This is important in scenarios where only the selection matters, not the sequence.
The mathematical formula for combinations is expressed as:\[\binom{N}{n} = \frac{N!}{n!(N-n)!}\]Here, \(N\) represents the total number of items in the population, while \(n\) indicates the number of items selected for the sample. The \(!\) symbolizes the factorial operation, meaning the product of an integer and all the integers below it.
Understanding how to use this formula is key to calculating possibilities accurately. For example, if you are choosing 4 items from a total of 50, you'd replace \(N\) with 50 and \(n\) with 4. This way, you can cleverly calculate the total number of unique combinations possible, in this case giving us a result of 230300 combinations.
Sample Size
A sample size is a vital component in statistical analysis. It represents the number of observations or data points selected from a population for analysis. When performing a simple random sampling, the size of the sample is denoted by \(n\).
The right sample size is crucial because:
  • It impacts the accuracy of the conclusions.
  • A larger sample size usually provides a better representation of the population, reducing the margin of error.
  • Conversely, a small sample size may lead to incorrect inferences.
In our scenario with bank accounts, choosing a sample size of 4 out of 50 means we want to closely examine 4 accounts to gain insights into the broader population of accounts. Selecting an appropriate sample size can guide the robustness of the analysis and is a primary task in planning statistical studies.
Population Size
Population size is the total number of items, observations, or data points that are under consideration for a study regarding a certain phenomenon or characteristic. When discussing simple random sampling, population size is represented by \(N\).
Here’s what you need to know about population size:
  • It's critical for understanding the scale at which the sample is selected.
  • Population size influences the diversity of possible samples.
  • In this context, a population size of 50 bank accounts means we have 50 different items to consider for potential inclusion in our sample.
The population size defines the possible scope from which samples can be drawn. When using the combination formula, \[\binom{N}{n} = \frac{N!}{n!(N-n)!}\]You substitute \(N\) with the population size to start calculating how many ways you can form viable samples. Understanding the population size helps in planning the sampling strategy effectively and ensuring that the chosen sample mirrors the broader population accurately.

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Most popular questions from this chapter

Information about mutual funds provided by Morningstar Investment Research includes the type of mutual fund (Domestic Equity, International Equity, or Fixed Income) and the Morningstar rating for the fund. The rating is expressed from 1-star (lowest rating) to 5-star (highest rating). A sample of 25 mutual funds was selected from Morningstar Funds \(500(2008) .\) The following counts were obtained: \(\bullet\)Assume that one of these 25 mutual funds will be randomly selected in order to learn more about the mutual fund and its investment strategy. a. What is the probability of selecting a Domestic Equity fund? b. What is the probability of selecting a fund with a 4 -star or 5 -star rating? c. What is the probability of selecting a fund that is both a Domestic Equity fund and a fund with a 4 -star or 5 -star rating? d. What is the probability of selecting a fund that is a Domestic Equity fund or a fund with a 4 -star or 5 -star rating?Sixteen mutual funds were Domestic Equity funds. \(\bullet\)Thirteen mutual funds were rated 3 -star or less. \(\bullet\)Seven of the Domestic Equity funds were rated 4-star. \(\bullet\)Two of the Domestic Equity funds were rated 5 -star. Assume that one of these 25 mutual funds will be randomly selected in order to learn more about the mutual fund and its investment strategy. a. What is the probability of selecting a Domestic Equity fund? b. What is the probability of selecting a fund with a 4 -star or 5 -star rating? c. What is the probability of selecting a fund that is both a Domestic Equity fund and a fund with a 4 -star or 5 -star rating? d. What is the probability of selecting a fund that is a Domestic Equity fund or a fund with a 4 -star or 5 -star rating?

A financial manager made two new investments-one in the oil industry and one in municipal bonds. After a one-year period, each of the investments will be classified as either successful or unsuccessful. Consider the making of the two investments as an experiment. a. How many sample points exist for this experiment? b. Show a tree diagram and list the sample points. c. Let \(O=\) the event that the oil industry investment is successful and \(M=\) the event that the municipal bond investment is successful. List the sample points in \(O\) and in \(M\). d. List the sample points in the union of the events \((O \cup M)\). e. List the sample points in the intersection of the events \((O \cap M)\). f. Are events \(O\) and \(M\) mutually exclusive? Explain.

Suppose that we have a sample space with five equally likely experimental outcomes: \(E_{1}\). \\[ \begin{aligned} E_{2}, E_{3}, E_{4}, E_{5} . \text { Let } \\ \qquad \begin{aligned} A &=\left\\{E_{1}, E_{2}\right\\} \\ B &=\left\\{E_{3}, E_{4}\right\\} \\ C &=\left\\{E_{2}, E_{3}, E_{5}\right\\} \end{aligned} \end{aligned} \\] a. \(\quad\) Find \(P(A), P(B),\) and \(P(C)\). b. Find \(P(A \cup B)\). Are \(A\) and \(B\) mutually exclusive? c. \(\quad\) Find \(A^{c}, C^{c}, P\left(A^{c}\right),\) and \(P\left(C^{c}\right)\). d. Find \(A \cup B^{c}\) and \(P\left(A \cup B^{c}\right)\). e. Find \(P(B \cup C)\).

Consider the experiment of tossing a coin three times. a. Develop a tree diagram for the experiment. b. List the experimental outcomes. c. What is the probability for each experimental outcome?

An experiment with three outcomes has been repeated 50 times, and it was learned that \(E_{1}\) occurred 20 times, \(E_{2}\) occurred 13 times, and \(E_{3}\) occurred 17 times. Assign probabilities to the outcomes. What method did you use?

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