/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 The cost of consumer purchases s... [FREE SOLUTION] | 91Ó°ÊÓ

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The cost of consumer purchases such as single-family housing, gasoline, Internet services, tax preparation, and hospitalization was provided in The Wall-Street Journal (January 2 2007 ). Sample data typical of the cost of tax- return preparation by services such as \(\mathrm{H} \& \mathrm{R}\) Block are as shown. $$\begin{array}{lllll} 120 & 230 & 110 & 115 & 160 \\ 130 & 150 & 105 & 195 & 155 \\ 105 & 360 & 120 & 120 & 140 \\ 100 & 115 & 180 & 235 & 255 \end{array}$$ a. Compute the mean, median, and mode. b. Compute the first and third quartiles. c. Compute and interpret the 90 th percentile.

Short Answer

Expert verified
Mean: 148.81, Median: 130, Mode: 115, Q1: 115, Q3: 187.5, 90th Percentile: 251.

Step by step solution

01

Organize the Data

First, list all the data values in a single ordered array from smallest to largest for easier computation.\[100, 105, 105, 110, 115, 115, 115, 120, 120, 120, 130, 140, 150, 155, 160, 180, 195, 230, 235, 255, 360\]
02

Calculate the Mean

The mean (average) is computed by adding all the data values and dividing by the number of observations. \[\text{Mean} = \frac{100 + 105 + 105 + 110 + 115 + 115 + 115 + 120 + 120 + 120 + 130 + 140 + 150 + 155 + 160 + 180 + 195 + 230 + 235 + 255 + 360}{21} \]\[= \frac{3125}{21} \approx 148.81\]
03

Find the Median

Since there are 21 values, the median is the middle number, which is the 11th value when the data is ordered. In this list, the 11th value is:\[\text{Median} = 130\]
04

Determine the Mode

The mode is the number that appears most frequently in the data set. In this case, the number 115 appears three times, which is the most frequent occurrence.\[\text{Mode} = 115\]
05

Compute the First Quartile (Q1)

The first quartile divides the lowest 25% of data from the rest. For 21 data points, Q1 is at position \(\frac{1}{4}\) of the list:\(Q1 \approx \left(\frac{21+1}{4}\right) = \text{5.5th position}\)Interpolating between the 5th and 6th values, 115, we find:\[Q1 = 115\]
06

Compute the Third Quartile (Q3)

The third quartile divides the lowest 75% of data from the highest 25%. For 21 data points, Q3 is at position \(\frac{3}{4}\):\(Q3 \approx \left(3 \times \frac{21+1}{4}\right) = \text{16.5th position}\)Interpolating between the 16th (180) and 17th (195) values:\[Q3 = 187.5\]
07

Compute the 90th Percentile

The 90th percentile is the value below which 90% of the observations may be found. This can be found at position \((0.9 \times 22) = 19.8 \) in an ordered list, so we interpolate between the 19th (235) and 20th (255) values:\[P_{90} = 235 + 0.8 \times (255 - 235) = 251\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Mean
The mean is a measure of central tendency, often known simply as the average. It helps us understand the typical value around which the rest of the data can be compared. Calculating the mean involves summing all the data points and dividing the total by the number of data points.
For example, if we have data values such as 100, 150, and 200, the mean is calculated as follows:
\[\text{Mean} = \frac{100 + 150 + 200}{3} = 150\]
The mean is especially useful because it accounts for every value in our data set. However, it can be distorted by extreme values, known as outliers, which can make it a less reliable measure in some situations. In this exercise, the mean of tax return preparation costs is approximately 148.81, giving us a rough idea about the average cost for the service.
Exploring the Median
The median offers a different perspective. It is the middle value in a data set that has been arranged in order from smallest to largest. For odd-numbered data sets, the median is the exact middle value.
The median is calculated by simply picking the middle number when all values are listed in order. If there is an even number of observations, the median is the average of the two middle numbers.
In contrast to the mean, the median is not affected by outliers, making it a robust measure of central tendency when extremes are present.
In our exercise, with 21 observations in the data, the median is the 11th number, which is 130. This median tells us that half the values are less than 130, and half are more.
Delving into Quartiles
Quartiles divide a data set into four equal parts, helping understand the spread and central tendency better.
The first quartile (Q1) represents the 25th percentile, separating the lowest 25% of data from the rest, and the third quartile (Q3) marks the 75th percentile, dividing the lowest 75% from the highest 25%.

Calculating quartiles involves splitting the ordered data set accordingly:
  • First Quartile (Q1): Located at the one-fourth position in the data. For 21 data points, it's between the 5th and 6th values, which comes out as 115 using interpolation.
  • Third Quartile (Q3): Found three-fourths up the list. In our data, this lies between the 16th and 17th values. Interpolating these positions gives a third quartile of 187.5.
Quartiles provide a deeper insight into data distribution, helping identify where the bulk of data values lie.
Percentiles Explained
Percentiles indicate the relative standing of a value in a dataset. They show the percentage of observations below a specific value, allowing for more detailed understanding of distribution than quartiles offer.
The 90th percentile, specifically, shows us the value below which 90% of points fall. It can be particularly useful in comparing high performance or extreme values within a dataset.
To calculate the 90th percentile, find the position corresponding to 90% of the data. For our data with 21 points, this is the 19.8th position. By interpolating between the 19th and 20th values (235 and 255), we determine the 90th percentile to be 251.
Understanding percentiles helps in situations where you're assessing the relative position within large datasets, like test scores or income levels.

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Most popular questions from this chapter

The grade point average for college students is based on a weighted mean computation. For most colleges, the grades are given the following data values: \(A(4), B(3), C\) \((2), D(1),\) and \(F(0) .\) After 60 credit hours of course work, a student at State University earned 9 credit hours of \(A, 15\) credit hours of \(B, 33\) credit hours of \(C,\) and 3 credit hours of \(\mathrm{D}\) a. Compute the student's grade point average. b. Students at State University must maintain a 2.5 grade point average for their first 60 credit hours of course work in order to be admitted to the business college. Will this student be admitted?

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Does a major league baseball team's record during spring training indicate how the team will play during the regular season? Over the last six years, the correlation coefficient between a team's winning percentage in spring training and its winning percentage in the regular season is .18 (The Wall Street Journal, March 30,2009 ). Shown are the winning percentages for the 14 American League teams during the 2008 season. a. What is the correlation coefficient between the spring training and the regular season winning percentages? b. What is your conclusion about a team's record during spring training indicating how the team will play during the regular season? What are some of the reasons why this occurs? Discuss.

In automobile mileage and gasoline-consumption testing, 13 automobiles were road tested for 300 miles in both city and highway driving conditions. The following data were recorded for miles-per-gallon performance. $$\begin{array}{lllllllllllllll} \text {City:} & 16.2 & 16.7 & 15.9 & 14.4 & 13.2 & 15.3 & 16.8 & 16.0 & 16.1 & 15.3 & 15.2 & 15.3 & 16.2 \\ \text {Highway}: & 19.4 & 20.6 & 18.3 & 18.6 & 19.2 & 17.4 & 17.2 & 18.6 & 19.0 & 21.1 & 19.4 & 18.5 & 18.7 \end{array}$$ Use the mean, median, and mode to make a statement about the difference in performance for city and highway driving.

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