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According to an annual consumer spending survey, the average monthly Bank of America Visa credit card charge was \(\$ 1838\) (U.S. Airways Attaché Magazine, December 2003 ). A sample of monthly credit card charges provides the following data. $$\begin{array}{llrrr} 236 & 1710 & 1351 & 825 & 7450 \\ 316 & 4135 & 1333 & 1584 & 387 \\ 991 & 3396 & 170 & 1428 & 1688 \end{array}$$ a. Compute the mean and median. b. Compute the first and third quartiles. c. Compute the range and interquartile range. d. Compute the variance and standard deviation. e. The skewness measure for these data is \(2.12 .\) Comment on the shape of this distribution. Is it the shape you would expect? Why or why not? f. Do the data contain outliers?

Short Answer

Expert verified
The mean is approximately 1673.33, and the median is 1351. Outliers include 3396, 4135, and 7450, affecting distribution skewness.

Step by step solution

01

Organize the Data

First, organize the data in increasing order to facilitate the calculation of statistics such as the median and quartiles. The ordered data is: 170, 236, 316, 387, 825, 991, 1333, 1351, 1428, 1584, 1688, 1710, 3396, 4135, 7450.
02

Compute the Mean

The mean is calculated by adding all data values and dividing by the number of data points. \[\text{Mean} = \frac{170 + 236 + 316 + 387 + 825 + 991 + 1333 + 1351 + 1428 + 1584 + 1688 + 1710 + 3396 + 4135 + 7450}{15} = \frac{25100}{15} \approx 1673.33 \]
03

Compute the Median

The median is the middle value in the ordered dataset. For 15 data points, the median is the 8th value. Thus, the median is 1351.
04

Compute the First and Third Quartiles

The first quartile (Q1) is the median of the first half of the data, and the third quartile (Q3) is the median of the second half. For Q1: The first half is 170, 236, 316, 387, 825, 991, 1333. The median is (387 + 825)/2 = 606. For Q3: The second half is 1351, 1428, 1584, 1688, 1710, 3396, 4135, 7450. The median is (1584 + 1688)/2 = 1636.
05

Compute the Range and Interquartile Range

The range is the difference between the maximum and minimum values. \[\text{Range} = 7450 - 170 = 7280\]The interquartile range (IQR) is the difference between the third and first quartiles. \[\text{IQR} = 1636 - 606 = 1030\]
06

Compute the Variance

Variance is the average of the squared differences from the Mean. Firstly, calculate the squared differences for each data point from the mean, then average these squared differences: \[\text{Variance} = \frac{\sum (x_i - \text{Mean})^2}{n} \approx 2644953.07\]
07

Compute the Standard Deviation

The standard deviation is the square root of the variance. \[\text{Standard Deviation} = \sqrt{2644953.07} \approx 1626.61\]
08

Analyze Skewness and Distribution Shape

A skewness measure of 2.12 suggests a highly positively skewed distribution. This is consistent with the presence of high outliers such as 7450 and 4135, which are pulling the mean higher than the median.
09

Detect Outliers

Outliers are data points that lie outside 1.5 times the interquartile range above the third quartile and below the first quartile. 1.5 * IQR = 1.5 * 1030 = 1545. Lower bound = 606 - 1545 = -939. Upper bound = 1636 + 1545 = 3181. Data points 3396, 4135, and 7450 are greater than 3181, thus they are outliers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Median
The mean and median are fundamental concepts in descriptive statistics that offer insight into the central tendency of your data. The **mean**, often called the average, is the sum of all data points divided by the number of data points. In mathematical terms, this is represented as:
  • Mean = \( \frac{\sum x_i}{n} \)
where \( x_i \) represents each data value and \( n \) is the total number of data points.

In our example, the mean was calculated as approximately \( 1673.33 \), giving us a sense of the overall expenditure.

The **median** is the middle value when the dataset is ordered. It provides a measure that isn't as affected by extreme values like outliers. For our dataset with 15 points, the median is simply the 8th value in the ordered list, which is 1351. This shows us a value that symbolizes the midpoint of our data.

Both the mean and median help illustrate different aspects of the dataset's distribution and provide a foundation for further analysis.
Quartiles
Quartiles divide a dataset into four equal parts and are crucial for understanding the spread and distribution of data. The primary quartiles are:
  • **First Quartile (Q1):** Represents the 25th percentile of the data, marking the start of the middle half of the data. It's the median of the first half of the data.
  • **Third Quartile (Q3):** Represents the 75th percentile, indicating the end of the middle half and the beginning of the top quarter.
In our dataset, after ordering the data, Q1 was calculated to be 606 and Q3 was 1636.

These quartiles are important because they help us find the Interquartile Range (IQR), which is Q3 minus Q1. In this instance, the IQR is 1030, offering insight into the variability and spread of the central 50% of the data.

Quartiles provide a more detailed view of data distribution than mean or median alone, especially with skewed data.
Variance and Standard Deviation
Variance and standard deviation are statistics that describe the variability within a dataset. **Variance** measures how far each data point in the set is from the mean and from each other. It's calculated as:
  • Variance = \( \frac{\sum (x_i - \text{Mean})^2}{n} \)
Here, the variance of our dataset is roughly 2644953.07, which is a large value due to the presence of extreme data points.

The **standard deviation** is the square root of the variance, providing a measure of spread in the same units as the data:
  • Standard Deviation = \( \sqrt{\text{Variance}} \)
For the given dataset, the standard deviation is approximately 1626.61. This high value suggests significant dispersion around the mean, confirming our dataset's variability.

These measures are key for understanding how tightly or loosely data points are clustered around the mean. They can help identify patterns or irregularities within your data.
Skewness
Skewness is a statistical measure of the asymmetry of the distribution of data points. In simple terms, it tells us how the data "leans." A skewness value of 0 would mean perfectly symmetrical data, while our dataset has a skewness of 2.12, indicating a significant right skew.
  • **Right (positive) skew:** More data points are concentrated on the left, with a tail extending to the right.
  • **Left (negative) skew:** More data points are concentrated on the right, with a tail extending to the left.
In our case, the right skewness reflects the presence of several large values like 7450 and 4135, which pull the mean towards higher values compared to the median.

Understanding skewness is crucial because it can affect other statistical analyses and inferences. Positive skewness, as shown here, may highlight an imbalance in data distribution that could imply outliers or the need for data transformation.
Outliers
Outliers are data points that differ significantly from other observations. They can skew and mislead statistical analysis. Outliers can be detected through the interquartile range (IQR). A common method involves identifying values that lie beyond 1.5 times the IQR above Q3 or below Q1.

In our dataset:
  • Lower Bound = \( Q1 - 1.5 \times \text{IQR} = 606 - 1545 = -939 \)
  • Upper Bound = \( Q3 + 1.5 \times \text{IQR} = 1636 + 1545 = 3181 \)
Any data points beyond these bounds are considered outliers. For this exercise, the values 3396, 4135, and 7450 are outliers as they exceed the upper limit of 3181.

Outliers might indicate variability in measurement, experimental errors, or a novel characteristic of the dataset. Recognizing them helps in making more accurate data interpretations and decisions.

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Most popular questions from this chapter

Consider a sample with a mean of 30 and a standard deviation of \(5 .\) Use Chebyshev's theorem to determine the percentage of the data within each of the following ranges: a. 20 to 40 b. 15 to 45 c. 22 to 38 d. 18 to 42 e. 12 to 48

Show the five-number summary and the box plot for the following data: 5,15,18,10,8 12,16,10,6

The following times were recorded by the quarter-mile and mile runners of a university track team (times are in minutes). $$\begin{array}{llllll} \text {Quarter-Mile Times:} & .92 & .98 & 1.04 & .90 & .99 \\ \text {Mile Times:} & 4.52 & 4.35 & 4.60 & 4.70 & 4.50 \end{array}$$ After viewing this sample of running times, one of the coaches commented that the quartermilers turned in the more consistent times, Use the standard deviation and the coefficient of variation to summarize the variability in the data. Does the use of the coefficient of variation indicate that the coach's statement should be qualified?

Consumer Reports provided overall customer satisfaction scores for AT\&T, Sprint, T-Mobile, and Verizon cell-phone services in major metropolitan areas throughout the United States. The rating for each service reflects the overall customer satisfaction considering a variety of factors such as cost, connectivity problems, dropped calls, static interference, and customer support. A satisfaction scale from 0 to 100 was used with 0 indicating completely dissatisfied and 100 indicating completely satisfied. The ratings for the four cellphone services in 20 metropolitan areas are as shown (Consumer Reports, January 2009 ). $$\begin{array}{lcccc} \text { Metropolitan Area } & \text { AT\&T } & \text { Sprint } & \text { T-Mobile } & \text { Verizon } \\ \text { Atlanta } & 70 & 66 & 71 & 79 \\ \text { Boston } & 69 & 64 & 74 & 76 \\ \text { Chicago } & 71 & 65 & 70 & 77 \\ \text { Dallas } & 75 & 65 & 74 & 78 \\ \text { Denver } & 71 & 67 & 73 & 77 \\ \text { Detroit } & 73 & 65 & 77 & 79 \\ \text { Jacksonville } & 73 & 64 & 75 & 81 \\ \text { Las Vegas } & 72 & 68 & 74 & 81 \\ \text { Los Angeles } & 66 & 65 & 68 & 78 \\ \text { Miami } & 68 & 69 & 73 & 80 \\ \text { Minneapolis } & 68 & 66 & 75 & 77 \\ \text { Philadelphia } & 72 & 66 & 71 & 78 \\ \text { Phoenix } & 68 & 66 & 76 & 81 \\ \text { San Antonio } & 75 & 65 & 75 & 80 \\ \text { San Diego } & 69 & 68 & 72 & 79 \\ \text { San Francisco } & 66 & 69 & 73 & 75 \\ \text { Seattle } & 68 & 67 & 74 & 77 \\ \text { St. Louis } & 74 & 66 & 74 & 79 \\ \text { Tampa } & 73 & 63 & 73 & 79 \\ \text { Washington } & 72 & 68 & 71 & 76 \end{array}$$ a. Consider T-Mobile first. What is the median rating? b. Develop a five-number summary for the T-Mobile service. c. Are there outliers for T-Mobile? Explain. d. Repeat parts (b) and (c) for the other three cell-phone services. e. Show the box plots for the four cell-phone services on one graph. Discuss what a comparison of the box plots tells about the four services. Which service did Consumer Reports recommend as being best in terms of overall customer satisfaction?

Consider a sample with a mean of 500 and a standard deviation of \(100 .\) What are the \(z\) -scores for the following data values: \(520,650,500,450,\) and \(280 ?\)

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