/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Consider the following data and ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the following data and corresponding weights. $$\begin{array}{cc} \boldsymbol{x}_{\boldsymbol{i}} & \text { Weight }\left(\boldsymbol{w}_{\boldsymbol{i}}\right) \\ 3.2 & 6 \\ 2.0 & 3 \\ 2.5 & 2 \\ 5.0 & 8 \end{array}$$ a. Compute the weighted mean. b. Compute the sample mean of the four data values without weighting. Note the difference in the results provided by the two computations.

Short Answer

Expert verified
The weighted mean is approximately 3.6947, and the sample mean is 3.175.

Step by step solution

01

Understanding the Weighted Mean

To compute the weighted mean of a set of data, you need both the data values and their corresponding weights. The formula for the weighted mean is given by: \( \bar{x}_w = \frac{\sum (x_i \cdot w_i)}{\sum w_i} \). Here, \( x_i \) represents each data point, and \( w_i \) is the weight associated with \( x_i \).
02

Calculating the Weighted Values

For each data point \( x_i \), multiply it by its corresponding weight \( w_i \): - \( 3.2 \times 6 = 19.2 \)- \( 2.0 \times 3 = 6.0 \)- \( 2.5 \times 2 = 5.0 \)- \( 5.0 \times 8 = 40.0 \)
03

Summing the Weighted Values and Weights

Sum all the weighted values: \( 19.2 + 6.0 + 5.0 + 40.0 = 70.2 \).Also, sum the weights: \( 6 + 3 + 2 + 8 = 19 \).
04

Computing the Weighted Mean

Use the weighted mean formula to calculate: \( \bar{x}_w = \frac{70.2}{19} = 3.6947 \) (approximately).
05

Understanding the Sample Mean

The sample mean is calculated by dividing the sum of all data points by the number of data points. The formula is \( \bar{x} = \frac{\sum x_i}{n} \), where \( n \) is the number of data values.
06

Calculating the Sample Mean

Add all data points: \( 3.2 + 2.0 + 2.5 + 5.0 = 12.7 \).There are 4 data points, so the sample mean is: \( \bar{x} = \frac{12.7}{4} = 3.175 \).
07

Comparing Results

The weighted mean calculated was approximately 3.6947, whereas the sample mean was 3.175. This shows how weights assigned to data points can influence the mean—primarily when higher weights are given to larger data values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a simple yet crucial concept in statistics. To find the sample mean, you add up all the data points in a dataset and then divide by the number of data points you have. It's like finding the average of your data.
For our exercise, we have the data values: 3.2, 2.0, 2.5, and 5.0. To calculate the sample mean (often represented by \( \bar{x} \)), we follow these steps:
  • Sum all data points: \( 3.2 + 2.0 + 2.5 + 5.0 = 12.7 \).
  • Count the number of data points: There are 4 data values.
  • Divide the sum by the number of points: \( \bar{x} = \frac{12.7}{4} = 3.175 \).
So, the sample mean of our data set is 3.175. This gives us a balanced average, not considering any weights or importance to individual values.
Data Values
Data values are the individual numbers or measurements we use in our calculations. In this exercise, these values are 3.2, 2.0, 2.5, and 5.0. These values are fundamental in statistical analyses because they form the raw dataset from which other metrics, such as means, are derived.
Understanding and working with data values involves recognizing their role in calculations:
  • Each value contributes equally to the sample mean.
  • In weighted calculations, each value may contribute differently based on associated weights.
When working with data, it's essential to ensure that each value is valid and accurately reflects the information being measured.
Weights in Statistics
Weights in statistics allow us to give different levels of importance to different data values. In some situations, certain data points might be more significant than others. This is where weights come into play, helping us to calculate a weighted mean instead of a simple mean.
In our exercise, each data value had a corresponding weight, such as 6 for 3.2 and 8 for 5.0. These weights affect the mean because they multiply the value they are associated with before summing. The formula for the weighted mean is:
  • \( \bar{x}_w = \frac{\sum (x_i \cdot w_i)}{\sum w_i} \)
  • This means we multiply each data point \( x_i \) by its weight \( w_i \), sum those products, and then divide by the total weight.
When weights are assigned, larger weights can significantly influence the weighted average, emphasizing more critical data points according to the problem's context.
Mean Comparison
Comparing the weighted mean to the sample mean shows how weights can influence the average. In this particular exercise, we calculated two types of means:For the unweighted or sample mean, each data point \( x_i \) is treated equally. This resulted in a mean of 3.175.
For the weighted mean, different importance is given to each value, based on assigned weights. This resulted in a weighted mean of approximately 3.6947.

Main Insights:

  • The weighted mean was higher than the sample mean because more significant weights were given to larger data values.
  • If a dataset has weights, the weighted mean can provide a better representation of the distribution according to those weights.
  • This disparity shows how the choice of mean can depend on the specific needs and context of the analysis.
Understanding both means allows for more flexibility and precision in statistical evaluations.

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Most popular questions from this chapter

The grade point average for college students is based on a weighted mean computation. For most colleges, the grades are given the following data values: \(A(4), B(3), C\) \((2), D(1),\) and \(F(0) .\) After 60 credit hours of course work, a student at State University earned 9 credit hours of \(A, 15\) credit hours of \(B, 33\) credit hours of \(C,\) and 3 credit hours of \(\mathrm{D}\) a. Compute the student's grade point average. b. Students at State University must maintain a 2.5 grade point average for their first 60 credit hours of course work in order to be admitted to the business college. Will this student be admitted?

During the \(2007-2008\) NCAA college basketball season, men's basketball teams attempted an all-time high number of 3 -point shots, averaging 19.07 shots per game (Associated Press Sports, January 24,2009 ). In an attempt to discourage so many 3 -point shots and encourage more inside play, the NCAA rules committee moved the 3 -point line back from 19 feet, 9 inches to 20 feet, 9 inches at the beginning of the \(2008-2009\) basketball season. Shown in the following table are the 3 -point shots taken and the 3 -point shots made for a sample of 19 NCAA basketball games during the \(2008-2009\) season. $$\begin{array}{cccc} \text { 3-Point Shots } & \text { Shots Made } & \text { 3-Point Shots } & \text { Shots Made } \\ 23 & 4 & 17 & 7 \\ 20 & 6 & 19 & 10 \\ 17 & 5 & 22 & 7 \\ 18 & 8 & 25 & 11 \\ 13 & 4 & 15 & 6 \\ 16 & 4 & 10 & 5 \\ 8 & 5 & 11 & 3 \\ 19 & 8 & 25 & 8 \\ 28 & 5 & 23 & 7 \\ 21 & 7 & & \end{array}$$ a. What is the mean number of 3 -point shots taken per game? b. What is the mean number of 3 -point shots made per game? c. Using the closer 3 -point line, players were making \(35.2 \%\) of their shots. What percentage of shots were players making from the new 3 -point line? d. What was the impact of the NCAA rules change that moved the 3 -point line back to 20 feet, 9 inches for the \(2008-2009\) season? Would you agree with the Associated Press Sports article that stated," Moving back the 3 -point line hasn't changed the game dramatically"? Explain.

A panel of economists provided forecasts of the U.S. economy for the first six months of 2007 (The Wall Street Journal, January 2,2007 ). The percent changes in the gross domestic product (GDP) forecasted by 30 economists are as follows. $$\begin{array}{cccccccccc} 2.6 & 3.1 & 2.3 & 2.7 & 3.4 & 0.9 & 2.6 & 2.8 & 2.0 & 2.4 \\ 2.7 & 2.7 & 2.7 & 2.9 & 3.1 & 2.8 & 1.7 & 2.3 & 2.8 & 3.5 \\ 0.4 & 2.5 & 2.2 & 1.9 & 1.8 & 1.1 & 2.0 & 2.1 & 2.5 & 0.5 \end{array}$$ a. What is the minimum forecast for the percent change in the GDP? What is the maximum? b. Compute the mean, median, and mode. c. \(\quad\) Compute the first and third quartiles. d. Did the economists provide an optimistic or pessimistic outlook for the U.S. economy? Discuss.

The national average for the math portion of the College Board's SAT test is 515 (The World Almanac, 2009 ). The College Board periodically rescales the test scores such that the standard deviation is approximately \(100 .\) Answer the following questions using a bellshaped distribution and the empirical rule for the math test scores. a. What percentage of students have an SAT math score greater than \(615 ?\) b. What percentage of students have an SAT math score greater than \(715 ?\) c. What percentage of students have an SAT math score between 415 and \(515 ?\) d. What percentage of students have an SAT math score between 315 and \(615 ?\)

The U.S. Census Bureau provides statistics on family life in the United States, including the age at the time of first marriage, current marital status, and size of household (U.S. Census Bureau website, March 20,2006 ). The following data show the age at the time of first marriage for a sample of men and a sample of women. $$\begin{array}{lcccccccc} \text { Men } & 26 & 23 & 28 & 25 & 27 & 30 & 26 & 35 & 28 \\ & 21 & 24 & 27 & 29 & 30 & 27 & 32 & 27 & 25 \\ \text { Women } & 20 & 28 & 23 & 30 & 24 & 29 & 26 & 25 & \\ & 22 & 22 & 25 & 23 & 27 & 26 & 19 & & \end{array}$$ a. Determine the median age at the time of first marriage for men and women. b. Compute the first and third quartiles for both men and women. c. Twenty-five years ago the median age at the time of first marriage was 25 for men and 22 for women. What insight does this information provide about the decision of when to marry among young people today?

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