/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The Los Angeles Times regularly ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Los Angeles Times regularly reports the air quality index for various areas of Southern California. A sample of air quality index values for Pomona provided the following data: \(28,42,58,48,45,55,60,49,\) and 50 a. Compute the range and interquartile range. b. Compute the sample variance and sample standard deviation. c. \(\quad\) A sample of air quality index readings for Anaheim provided a sample mean of 48.5 a sample variance of \(136,\) and a sample standard deviation of \(11.66 .\) What comparisons can you make between the air quality in Pomona and that in Anaheim on the basis of these descriptive statistics?

Short Answer

Expert verified
Pomona has less variability than Anaheim, with a range of 32 and standard deviation of 10.15.

Step by step solution

01

Understanding Range and Interquartile Range

The **range** of a dataset is the difference between the maximum and minimum values. The **interquartile range (IQR)** is the difference between the third quartile (Q3) and the first quartile (Q1), which gives the spread of the middle 50% of the data.
02

Compute Range

First, identify the smallest and largest value in the Pomona dataset: Data: 28, 42, 58, 48, 45, 55, 60, 49, 50- Minimum = 28- Maximum = 60Then calculate the range: \[ \text{Range} = \text{Maximum} - \text{Minimum} = 60 - 28 = 32 \]
03

Compute Interquartile Range

Sort the dataset: 28, 42, 45, 48, 49, 50, 55, 58, 60. - Find Q1 (first quartile) and Q3 (third quartile). Since there are 9 data points, the median is the 5th data point: 49. \( Q1 \) is the median of the first half: 42, 45, 48 (median: 45). \( Q3 \) is the median of the second half: 50, 55, 58, 60 (median: 55).\[ \text{IQR} = Q3 - Q1 = 55 - 45 = 10 \]
04

Compute Sample Variance and Standard Deviation

Calculate the mean of the data: \[ \text{Mean} = \frac{28 + 42 + 58 + 48 + 45 + 55 + 60 + 49 + 50}{9} = 48.33 \] Calculate each deviation from the mean, square it, and find the variance: \[ s^2 = \frac{(28-48.33)^2 + ... + (50-48.33)^2}{9-1} \approx 103.07 \] Standard deviation, \( s \), is the square root of variance: \[ s \approx \sqrt{103.07} \approx 10.15 \]
05

Compare Pomona and Anaheim

The Pomona dataset has a range of 32 and IQR of 10, with a standard deviation of 10.15. Anaheim has a sample mean of 48.5, with variance 136 and standard deviation 11.66. The air quality in Anaheim is more spread out (higher variance and standard deviation) than in Pomona, indicating more variability in readings.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Range
When interpreting data, the range is one of the simplest measures we can use to understand the spread. The range is quite simply the difference between the largest and smallest values in a dataset. It helps us get a quick sense of the variability. For example, in our dataset gathered from Pomona, we identified that the highest air quality index is 60, and the lowest is 28. Therefore, the range is calculated by subtracting the smallest number 28 from the largest number 60, resulting in a range of 32. This indicates that the air quality indices spread is 32 points from lowest to highest. The simplicity of the range doesn't account for how the values are distributed in-between the smallest and largest values, so it's often paired with other statistics like interquartile range for a fuller picture.
Interquartile Range
The interquartile range (IQR), offers a more resistant measure of variability than the range. It considers the spread of the middle 50% of data, filtering out potential outliers. To compute the IQR, we first need to divide our dataset into quartiles. The first quartile (Q1) marks the 25th percentile, and the third quartile (Q3) the 75th percentile. In our sorted Pomona dataset, Q1 is 45 and Q3 is 55. Thus, the IQR is calculated as the difference between the third and first quartiles:
  • Q3 - Q1 = 55 - 45, leading to an IQR of 10.
This measure is particularly useful because it shows that the middle 50% of air quality index values in Pomona are spread out over a range of just 10 points, highlighting a concentrated central dispersion.
Sample Variance
Sample variance is a step further in understanding data variability. It gives us insights into how each data point differs from the mean value. It takes into account all the data points and measures the average squared deviations from the mean. In our case, after calculating the mean of the Pomona dataset as approximately 48.33, we calculate each data point's deviation from this mean, square it, and average those squared deviations. The formula for sample variance is:
  • \[ s^2 = \frac{(28 - 48.33)^2 + (42 - 48.33)^2 + ... + (50 - 48.33)^2}{9 - 1} \]
  • The sample variance is approximately 103.07, which indicates the extent to which the values deviate from the mean. A larger variance signifies that the numbers are more spread out.
Sample Standard Deviation
The sample standard deviation is closely related to the variance and provides a more intuitive measure of spread by returning to the original unit of measurement. This value is simply the square root of the sample variance. For the Pomona dataset, we calculated the standard deviation to be roughly 10.15. Given that the variance was 103.07, taking the square root simplifies this back to the unit of the data values.
  • \[ s \approx \sqrt{103.07} \approx 10.15 \]
  • This measure indicates how much the actual values of the dataset deviate, on average, from the mean value of the data. A standard deviation of 10.15 suggests that on average, each air quality index value is 10.15 points away from the mean of 48.33, giving us a tangible sense of the variability.
Compared to Anaheim with a higher standard deviation of 11.66, Pomona's air quality readings are relatively less variable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The grade point average for college students is based on a weighted mean computation. For most colleges, the grades are given the following data values: \(A(4), B(3), C\) \((2), D(1),\) and \(F(0) .\) After 60 credit hours of course work, a student at State University earned 9 credit hours of \(A, 15\) credit hours of \(B, 33\) credit hours of \(C,\) and 3 credit hours of \(\mathrm{D}\) a. Compute the student's grade point average. b. Students at State University must maintain a 2.5 grade point average for their first 60 credit hours of course work in order to be admitted to the business college. Will this student be admitted?

The National Association of Realtors reported the median home price in the United States and the increase in median home price over a five-year period (The Wall Street Journal, January 16,2006 ). Use the sample home prices shown here to answer the following questions. $$\begin{array}{llllll} 995.9 & 48.8 & 175.0 & 263.5 & 298.0 & 218.9 & 209.0 \\ 628.3 & 111.0 & 212.9 & 92.6 & 2325.0 & 958.0 & 212.5 \end{array}$$ a. What is the sample median home price? b. In January 2001 , the National Association of Realtors reported a median home price of \(\$ 139,300\) in the United States. What was the percentage increase in the median home price over the five-year period? c. What are the first quartile and the third quartile for the sample data? d. Provide a five-number summary for the home prices. e. Do the data contain any outliers? f. What is the mean home price for the sample? Why does the National Association of Realtors prefer to use the median home price in its reports?

The U.S. Census Bureau provides statistics on family life in the United States, including the age at the time of first marriage, current marital status, and size of household (U.S. Census Bureau website, March 20,2006 ). The following data show the age at the time of first marriage for a sample of men and a sample of women. $$\begin{array}{lcccccccc} \text { Men } & 26 & 23 & 28 & 25 & 27 & 30 & 26 & 35 & 28 \\ & 21 & 24 & 27 & 29 & 30 & 27 & 32 & 27 & 25 \\ \text { Women } & 20 & 28 & 23 & 30 & 24 & 29 & 26 & 25 & \\ & 22 & 22 & 25 & 23 & 27 & 26 & 19 & & \end{array}$$ a. Determine the median age at the time of first marriage for men and women. b. Compute the first and third quartiles for both men and women. c. Twenty-five years ago the median age at the time of first marriage was 25 for men and 22 for women. What insight does this information provide about the decision of when to marry among young people today?

Endowment income is a critical part of the annual budgets at colleges and universities. A study by the National Association of College and University Business Officers reported that the 435 colleges and universities surveyed held a total of \(\$ 413\) billion in endowments. The 10 wealthiest universities are shown in the following table (The Wall Street Journal, January 27,2009 ). Amounts are in billions of dollars. $$\begin{array}{lccc} \text { University } & \text { Endowment (\$billion) } & \text { University } & \text { Endowment (Sbillion) } \\ \text { Columbia } & 7.2 & \text { Princeton } & 16.4 \\ \text { Harvard } & 36.6 & \text { Stanford } & 17.2 \\ \text { M.I.T. } & 10.1 & \text { Texas } & 16.1 \\ \text { Michigan } & 7.6 & \text { Texas A\&M } & 6.7 \\ \text { Northwestern } & 7.2 & \text { Yale } & 22.9 \end{array}$$ a. What is the mean endowment for these universities? b. What is the median endowment? c. What is the mode endowment? d. Compute the first and third quartiles. e. What is the total endowment at these 10 universities? These universities represent \(2.3 \%\) of the 435 colleges and universities surveyed. What percentage of the total \(\$ 413\) billion in endowments is held by these 10 universities? f. The Wall Street Journal reported that over a recent five-month period, a downturn in the economy has caused endowments to decline \(23 \%\). What is the estimate of the dollar amount of the decline in the total endowments held by these 10 universities? Given this situation, what are some of the steps you would expect university administrators to be considering?

Five observations taken for two variables follow. $$\begin{array}{c|ccccc} x_{i} & 6 & 11 & 15 & 21 & 27 \\ \hline y_{i} & 6 & 9 & 6 & 17 & 12 \end{array}$$ a. Develop a scatter diagram for these data. b. What does the scatter diagram indicate about a relationship between \(x\) and \(y ?\) c. Compute and interpret the sample covariance. d. Compute and interpret the sample correlation coefficient.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.