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Two different simple random samples are drawn from two different populations. The first sample consists of 20 people with 10 having a common attribute. The second sample consists of 2000 people with 1404 of them having the same common attribute. Compare the results from a hypothesis test of \(p_{1}=p_{2}\) (with a \(0.05\) significance level) and a \(95 \%\) confidence interval estimate of \(p_{1}-p_{2}\).

Short Answer

Expert verified
The hypothesis test rejects the null hypothesis, suggesting different proportions. However, the confidence interval includes 0, indicating insufficient evidence for a difference.

Step by step solution

01

- Define Sample Proportions

Calculate the sample proportions of the common attribute for each sample. \[ p_1 = \frac{10}{20} = 0.5 \] \[ p_2 = \frac{1404}{2000} = 0.702 \]
02

- State Hypotheses

Set up the null and alternative hypotheses. The null hypothesis will state that the proportions are equal, while the alternative hypothesis will state they are not equal. \[ H_0: p_1 = p_2 \] \[ H_a: p_1 eq p_2 \]
03

- Calculate the Pooled Proportion

Calculate the pooled sample proportion \( \hat{p} \). \[ \hat{p} = \frac{x_1 + x_2}{n_1 + n_2} = \frac{10 + 1404}{20 + 2000} = \frac{1414}{2020} = 0.7 \]
04

- Calculate the Test Statistic

Use the pooled proportion to calculate the test statistic \( z \). \[ z = \frac{p_1 - p_2}{\sqrt{\hat{p}(1 - \hat{p})\left(\frac{1}{n_1} + \frac{1}{n_2}\right)}} = \frac{0.5 - 0.702}{\sqrt{0.7(1 - 0.7)\left(\frac{1}{20} + \frac{1}{2000}\right)}} \approx -2.008 \]
05

- Determine the Critical Value

For a two-tailed test at \( \alpha = 0.05 \), the critical values are \( z = \pm 1.96 \). Compare the test statistic to these critical values to decide if the null hypothesis should be rejected.
06

- Conclusion of Hypothesis Test

Since \( -2.008 \) is less than \( -1.96 \), we reject the null hypothesis. There is significant evidence at the 0.05 level to conclude the proportions are different.
07

- Calculate the Confidence Interval

Calculate the 95% confidence interval for \( p_1 - p_2 \) using the formula: \[ (p_1 - p_2) \pm z \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1 - p_2)}{n_2} } \] where \( z = 1.96 \) for a 95% confidence interval. \[ 0.5 - 0.702 \pm 1.96 \sqrt{ \frac{0.5 (0.5)}{20} + \frac{0.702 (0.298)}{2000} } \] \[ -0.202 \pm 1.96 \times 0.11 \approx [-0.418, 0.014] \]
08

- Conclusion of Confidence Interval

Since the confidence interval \( [-0.418, 0.014] \) includes 0, it indicates there is insufficient evidence at the 95% confidence level to state that there is a difference in the proportions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions
In hypothesis testing, one important concept is sample proportions. A sample proportion represents the ratio of individuals in a sample with a particular attribute to the total number of individuals in that sample. In our exercise, we calculate the sample proportions for two different groups on the common attribute they possess. For the first sample of 20 people, 10 have the attribute, thus the sample proportion is calculated as:
Step 1: Determine sample proportion for first group: The first sample has 10 people with the attribute out of 20, making the sample proportion: For the second sample, which consists of 2000 people where 1404 have the attribute, the sample proportion is: Step 1: Determine sample proportion for second group: We compare the sample proportions to understand differences between the two independent samples. The formulas we use are:



  • For the first sample:


    p_1 = \(\frac{10}{20} = 0.5\)
  • For the second sample: p_2 = \(\frac{1404}{2000} = 0.702\)
Confidence Intervals
Confidence intervals help us estimate the range within which the true difference between two population proportions lies, based on our sample data. It provides a range of values which is believed to contain the true parameter with a specified level of confidence, such as 95%. In our example, we calculate a 95% confidence interval for the difference between the two proportions:



A 95% confidence level means we are 95% confident the true difference lies within this interval.

Here’s how we calculate:



  • Difference in proportions: \(p_1 - p_2\) = -0.202

  • Standard error formula includes both sampling variations:
  • Confidence interval is calculated as:






  • 95% Confidence Interval = \(-0.202\pm 1.96\times 0.11\approx [-0.418, 0.014]\)



Pooled Proportion
The pooled proportion is an estimate of a single proportion based on the combined data from both samples. This concept is essential in hypothesis testing when comparing two proportions. By pooling the data, we get a weighted average of the two sample proportions.



Calculation involves summing the individual successes and the total sample size:

  • Combined successes: \(x_1+x_2 = 10+1404 = 1414\)
  • Total sample size: \(n_1+n_2 = 20+2000 = 2020\)







    Pooled Proportion = \(\hat{p}=\frac{1414}{2020}=0.7\)
Test Statistic
The test statistic helps determine whether to reject the null hypothesis. This value is derived from a specific formula and compared against critical values to make a decision. For our scenario, we calculate the test statistic by:



  • Using the difference of sample proportions: \(p_1-p_2\)

    [...]
  • Pooled proportion \(\hat{p}\)
  • Standard error formula which incorporates the pooled proportion and sample sizes
    [...]




    The Test Statistic (z value) = \(\frac{0.5-0.702}{\sqrt{{0.7(1-0.7)(\frac{1}{20}+\frac{1}{2000})}}}\approx-2.008\)
Null Hypothesis
In hypothesis testing, the null hypothesis \((H_0)\) is a statement we aim to test. It represents no effect or no difference and is assumed true until proven otherwise. In our problem, we tested: \(H_0:p_1=p_2\)




The goal is to examine if the difference between sample proportions is due to random chance or a real difference:
  • If the test statistic falls within critical values for a chosen significance level \((\alpha=0.05)\), we reject \(H_0\).

  • Critical values for two-tailed test: \(\pm1.96\). Since our calculated z is -2.008, we reject \(H_0\), indicating significant difference between proportions.


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Most popular questions from this chapter

Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, \(P\) -value or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we consider passenger cars and commercial trucks. Among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates (based on samples collected by the author). A reasonable hypothesis is that passenger car owners violate license plate laws at a higher rate than owners of commercial trucks. Use a \(0.05\) significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval.

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