/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 An FDA guideline is that the mer... [FREE SOLUTION] | 91Ó°ÊÓ

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An FDA guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in New York City. The study was sponsored by the New York Times, and the stores (in order) are D'Agostino, Eli's Manhattan, Fairway, Food Emporium, Gourmet Garage, Grace's Marketplace, and Whole Foods. Construct a \(98 \%\) confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi?

Short Answer

Expert verified
Yes, within the confidence interval, the mercury in tuna sushi is below the FDA guideline of 1 ppm.

Step by step solution

01

Gather the Data

List the given amounts of mercury (ppm) from the stores: D'Agostino: 0.8, Eli's Manhattan: 0.9, Fairway: 0.9, Food Emporium: 0.8, Gourmet Garage: 1.1, Grace's Marketplace: 0.7, Whole Foods: 0.6.
02

Calculate the Sample Mean

Find the average amount of mercury by summing the data points and dividing by the number of data points. Formula: \[ \bar{x} = \frac{\sum{x_i}}{n} \] Calculation: \[ \bar{x} = \frac{0.8 + 0.9 + 0.9 + 0.8 + 1.1 + 0.7 + 0.6}{7} \approx 0.8286 \]
03

Calculate the Sample Standard Deviation

Use the formula for sample standard deviation: \[ s = \sqrt{\frac{\sum{(x_i - \bar{x})^2}}{n-1}} \] Calculation involves finding the deviations from the mean, squaring them, summing them, and then dividing by the degrees of freedom (n-1), and taking the square root.
04

Find the t-Score for the Confidence Interval

Use a t-distribution table to find the t-score corresponding to a 98% confidence interval with 6 degrees of freedom. For a 98% confidence interval and df = 6, \[ t \approx 2.447 \]
05

Calculate the Margin of Error

Use the formula for margin of error: \[ E = t \times \frac{s}{\sqrt{n}} \] Substitute the values: \[ E = 2.447 \times \frac{s}{\sqrt{7}} \]
06

Construct the Confidence Interval

The confidence interval for the population mean is calculated as: \[ \left( \bar{x} - E, \bar{x} + E \right) \] Substitute \( \bar{x} = 0.8286 \), \( E \) from the previous step to get the interval.
07

Interpret the Confidence Interval

Compare the confidence interval with the FDA guideline of 1 ppm. If the upper bound of the interval is below 1 ppm, it suggests that mercury levels are within the safe limit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean Calculation
To find the average amount of mercury in tuna sushi from the data given, we need to calculate the sample mean. This can be done by summing all the mercury levels from the sampled stores and then dividing by the number of stores. The formula for the sample mean is given by:
\(\bar{x} = \frac{\text{\textbackslash sum{x_i}}}{n}\)
Where:
\(\bar{x}\) = sample mean,
\(\text{\textbackslash sum{x_i}}\) = sum of all sample values,
\({n}\) = number of samples.
In our example, the mercury levels are: 0.8, 0.9, 0.9, 0.8, 1.1, 0.7, and 0.6. Using the formula, we find:
\(\bar{x} = \frac{0.8 + 0.9 + 0.9 + 0.8 + 1.1 + 0.7 + 0.6}{7} \approx 0.8286\)
This gives us the sample mean of about 0.8286 ppm.
Sample Standard Deviation
The sample standard deviation helps us understand the variability or spread of mercury levels in our sampled sushi. It is calculated by measuring how much each sample value deviates from the sample mean.
The formula for the sample standard deviation is:
\[ s = \sqrt{\frac{\sum{(x_i - \bar{x})^2}}{n-1}} \]
Where:
\(s\) = sample standard deviation,
\(x_i\) = each sample value,
\(\bar{x}\) = sample mean,
\(n\) = number of samples.
Steps involved:
1. Subtract the sample mean from each sample value to find the deviation.
2. Square each deviation.
3. Sum all squared deviations.
4. Divide by the degrees of freedom (which is \(n-1\)).
5. Take the square root of the result.
In this case, we would compute each of these steps to find the standard deviation of the mercury levels.
t-Score
The t-score is a critical value used in statistics when constructing confidence intervals, especially for smaller sample sizes. It comes from the t-distribution, which is similar to the normal distribution but with heavier tails.
To find the t-score for a given confidence interval, we use a t-distribution table based on our sample size and desired confidence level.
For a 98% confidence interval and 6 degrees of freedom (df = n-1), we look up the t-score in the table. In this problem, the t-score is approximately 2.447.
The t-score helps to adjust the margin of error, accounting for the uncertainty inherent in a smaller sample size.
Margin of Error
The margin of error quantifies the range within which we expect the true population mean to lie, given our sample data. It accounts for the variability in the sample and the confidence level we choose.
The formula for margin of error is:
\[ E = t \times \frac{s}{\sqrt{n}} \]
Where:
\(E\) = margin of error,
\(t\) = t-score,
\(s\) = sample standard deviation,
\(n\) = number of samples.
By substituting the values we have from earlier steps, we calculate the margin of error as:
\(E = 2.447 \times \frac{s}{\sqrt{7}}\)
This result allows us to construct the confidence interval by adding and subtracting the margin of error from the sample mean.

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