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Use these parameters (based on Data Set 1 "Body Data" in Appendix B): \- Men's heights are normally distributed with mean \(68.6 \mathrm{in.}\) and standard deviation \(2.8 \mathrm{in} .\) \- Women's heights are normally distributed with mean 63.7 in. and standard deviation \(2.9 \mathrm{in}\). Air Force Pilots The U.S. Air Force requires that pilots have heights between 64 in. and 77 in. a. Find the percentage of men meeting the height requirement. b. If the Air Force height requirements are changed to exclude only the tallest \(2.5 \%\) of men and the shortest \(2.5 \%\) of men, what are the new height requirements?

Short Answer

Expert verified
a. 94.33% of men meet the original height requirements.b. New height requirements are 63.1 in. to 74.1 in.

Step by step solution

01

Understanding the Problem

Identify the given parameters for men's and women's heights, and the height requirements for Air Force pilots.
02

Calculate Z-scores for Men's Heights

Use the given mean \( \mu = 68.6 \) and standard deviation \( \sigma = 2.8 \). Convert the height requirements (64 in. and 77 in.) into Z-scores using the formula \[ Z = \frac{X - \mu}{\sigma} \].
03

Find Z-scores for 64 inches and 77 inches

Calculate the Z-scores as follows:\( Z_{64} = \frac{64 - 68.6}{2.8} = -1.64\)\( Z_{77} = \frac{77 - 68.6}{2.8} = 2.5\)
04

Use Z-scores to Find Percentages

Use the Z-table or standard normal distribution to find the percentage of data below these Z-scores. For \( Z = -1.64 \), the cumulative percentage is 5.05%. For \( Z = 2.5 \), the cumulative percentage is 99.38%. The percentage of men meeting the height requirements is \[ 99.38\text{\textpercent} - 5.05\text{\textpercent} = 94.33\text{\textpercent} \].
05

Adjust Height Requirements for Top 2.5% and Bottom 2.5%

Find the Z-scores corresponding to the 2.5th percentile and the 97.5th percentile from the Z-table. These Z-scores are \( Z = -1.96 \) and \( Z = 1.96 \).
06

Convert New Z-scores Back to Heights

Use the formula \[ X = Z \sigma + \mu \]. For \( Z = -1.96 \), \( X = -1.96 \times 2.8 + 68.6 = 63.1 \) in. For \( Z = 1.96 \), \( X = 1.96 \times 2.8 + 68.6 = 74.1 \) in. The new height requirements for men would be between 63.1 in. and 74.1 in.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
In statistics, the normal distribution is a key concept often referred to as the bell curve due to its bell-shaped appearance. It represents a continuous probability distribution characterized by its mean (µ) and standard deviation (σ). For example, men's heights are normally distributed with a mean of 68.6 inches and a standard deviation of 2.8 inches. This distribution implies that most men's heights cluster around the average, with fewer men being much shorter or much taller. The height data is symmetrical around the mean, and the standard deviation measures how spread out the heights are from the mean. Knowing that heights fit this pattern helps us make predictions and calculate probabilities related to heights, like determining the percentage of men within a specific height range.
Z-Scores
Z-scores, or standard scores, are a way of knowing how many standard deviations a data point (X) is from the mean (µ). To find a Z-score, you use the formula: his helps standardize different data points for easier comparison. For example, using the given heights: For a man who is 64 inches tall, the Z-score is calculated as: or a man 77 inches tall, the Z-score is: his helps us standardize different data points for easier comparison. For example, using the given heights: For a man who is 64 inches tall, the Z-score is calculated as: For a man 77 inches tall, the Z-score is: These Z-scores tell us how unusual a certain height is compared to the average height. A positive Z-score indicates a value above the mean, while a negative Z-score indicates a value below the mean. By converting heights into Z-scores, we make it easier to find the percentages of men who meet specific height requirements.
Standard Deviation
Standard deviation (σ) is a measure of the amount of variation or dispersion in a set of values. In the context of our problem, men's and women's heights have standard deviations of 2.8 inches and 2.9 inches, respectively. This means that most of the men's heights fall within 2.8 inches of their mean height (68.6 inches), and most of the women's heights fall within 2.9 inches of their mean height (63.7 inches).

Calculating the standard deviation involves finding the square root of the variance, which is the average of the squared differences from the mean. A smaller standard deviation indicates that the data points are close to the mean, while a larger standard deviation shows that the data points are spread out over a wider range of values.

Understanding the standard deviation helps us grasp how spread out or concentrated the heights are, which is crucial for calculating Z-scores and eventually determining how many people meet specific requirements like the Air Force pilot height restrictions.
Percentiles
Percentiles help us understand how a particular value compares to the rest of the data. For example, if you are in the 90th percentile for height, you are taller than 90% of people in your group. In our exercise, percentiles are used to exclude the shortest and tallest men based on height.

The Air Force might want to exclude the shortest 2.5% and the tallest 2.5% of men. To find these heights, we convert the 2.5th percentile and the 97.5th percentile into Z-scores (which are -1.96 and +1.96, respectively) and then back into height measurements using the formula: This tells us exactly which heights fall at the top 2.5% and the bottom 2.5%, providing new, more precise height requirements for Air Force pilots. Utilizing percentiles allows organizations to set thresholds or benchmarks based on their specific needs.

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Most popular questions from this chapter

A professor gives a test and the scores are normally distributed with a mean of 60 and a standard deviation of \(12 .\) She plans to curve the scores. a. If she curves by adding 15 to each grade, what is the new mean and standard deviation? b. Is it fair to curve by adding 15 to each grade? Why or why not? c. If the grades are curved so that grades of \(\mathrm{B}\) are given to scores above the bottom \(70 \%\) and below the top \(10 \%\), find the numerical limits for a grade of \(\mathrm{B}\). d. Which method of curving the grades is fairer: adding 15 to each original score or using a scheme like the one given in part (c)? Explain.

Find the indicated area under the curve of the standard normal distribution; then convert it to a percentage and fill in the blank. The results form the basis for the range rule of thumb and the empirical rule introduced in Section 3-2. About \(\quad \%\) of the area is between \(z=-3.5\) and \(z=3.5\) (or within \(3.5\) standard deviations of the mean).

Use these parameters (based on Data Set 1 "Body Data" in Appendix B): \- Men's heights are normally distributed with mean \(68.6 \mathrm{in.}\) and standard deviation \(2.8 \mathrm{in} .\) \- Women's heights are normally distributed with mean 63.7 in. and standard deviation \(2.9 \mathrm{in}\). The U.S. Navy requires that fighter pilots have heights between 62 in. and 78 in. a. Find the percentage of women meeting the height requirement. Are many women not qualified because they are too short or too tall? b. If the Navy changes the height requirements so that all women are eligible except the shortest \(3 \%\) and the tallest \(3 \%\), what are the new height requirements for women?

Use the data in the table below for sitting adult males and females (based on anthropometric survey data from Gordon, Churchill, et al.). These data are used often in the design of different seats, including aircraft seats, train seats, theater seats, and classroom seats. (Hint: Draw a graph in each case.) $$ \begin{aligned} &\text { Sitting Back-to-Knee Length (inches) }\\\ &\begin{array}{l|c|c|c} \hline & \text { Mean } & \text { St. Dev. } & \text { Distribution } \\ \hline \text { Males } & 23.5 \text { in. } & 1.1 \text { in. } & \text { Normal } \\ \hline \text { Females } & 22.7 \text { in. } & 1.0 \text { in. } & \text { Normal } \\ \hline \end{array} \end{aligned} $$ For females, find the first quartile \(Q_{1}\), which is the length separating the bottom \(25 \%\) from the top \(75 \%\).

Outliers For the purposes of constructing modified boxplots as described in Section 3-3, outliers are defined as data values that are above \(Q_{3}\) by an amount greater than \(1.5 \times \mathrm{IQR}\) or below \(Q_{1}\) by an amount greater than \(1.5 \times\) IQR, where IQR is the interquartile range. Using this definition of outliers, find the probability that when a value is randomly selected from a normal distribution, it is an outlier.

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