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91Ó°ÊÓ

The Fairfield County Department of Public Health tests water for the presence of \(E\). coli (Escherichia coli) bacteria. To reduce laboratory costs, water samples from 10 public swimming areas are combined for one test, and further testing is done only if the combined sample tests positive. Based on past results, there is a \(0.005\) probability of finding \(E\). coli bacteria in a public swimming area. Find the probability that a combined sample from 10 public swimming areas will reveal the presence of \(E\). coli bacteria. Is that probability low enough so that further testing of the individual samples is rarely necessary?

Short Answer

Expert verified
The probability is 0.049. This represents a 4.9% chance that further testing will be needed.

Step by step solution

01

- Identify the Probability of a Single Event

Let the probability of finding E. coli in one public swimming area be represented by p. Given, p = 0.005.
02

- Calculate the Probability of Not Finding E. coli in One Area

The probability of not finding E. coli in one swimming area is represented as 1 - p. Therefore, the probability is 1 - 0.005 = 0.995.
03

- Calculate the Probability of Not Finding E. coli in 10 Areas

Since the samples are combined, consider the 10 areas as independent events. The probability of not finding E. coli in all 10 swimming areas is \((0.995)^{10}\).
04

- Compute the Above Probability

Calculate \[ (0.995)^{10} \]. It equals approximately 0.951.
05

- Calculate the Probability of Finding E. coli in the Combined Sample

The probability of the combined sample revealing the presence of E. coli is 1 minus the probability of not finding it in any of the 10 areas: 1 - (0.995)^10. Hence, the probability is approximately 1 - 0.951 = 0.049.
06

- Analyze the Result

The probability obtained is 0.049, which means there is a 4.9% chance that the combined sample will test positive for E. coli. Assess if this probability is low enough for the context.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Understanding probability is essential in public health, especially when dealing with contaminants like E. coli. Probability measures how likely it is for an event to happen. Here, we need to find the chance of detecting E. coli in a combined sample.
First, we identify the probability of finding E. coli in one swimming area. Given, this probability is 0.005. Next, we calculate the chance of not finding E. coli in one swimming area, which is the complement of the first probability: 1 - 0.005 = 0.995.
For ten independent swimming areas, the probability of not finding E. coli in all areas is \( (0.995)^{10} \). This equals approximately 0.951.
Finally, the chance of finding E. coli in at least one of the ten areas is the complement: 1 - 0.951 = 0.049, or 4.9%. This step-by-step approach helps in understanding how different probabilities combine.
E. coli Testing
E. coli (Escherichia coli) testing is crucial for public health as this bacteria can cause serious illness. The Fairfield County Department of Public Health checks water in public swimming areas to ensure safety.
When the presence of E. coli is detected, it can indicate contamination, often from fecal matter, causing diseases such as diarrhea, urinary tract infections, and even kidney failure in severe cases.
Routine testing involves taking water samples and using biochemical tests to detect the bacteria. In this case, combining samples helps reduce the cost of laboratory tests while still monitoring public health risks.
Combined Sample Testing
To reduce costs, public health departments often pool samples from multiple sites. Here, samples from ten swimming areas are combined for a single test. This method maximizes resource efficiency.
If the combined sample tests positive for E. coli, further individual testing is required to pinpoint the contaminated location. Pooling samples is effective when the probability of contamination in individual samples is low.
The probability calculations help determine the efficiency of this method. When we found the 4.9% chance of a positive result in the combined sample, it meant that in around 1 out of 20 tests, additional testing would be needed.
Public Health Statistics
Public health statistics, like the probability of E. coli presence, inform decisions on testing protocols and resource allocation. By understanding these statistics, Public Health Departments can efficiently manage testing processes and respond to health risks.
Regularly collecting and analyzing data helps to identify trends, allocate resources, and implement preventive measures. For example, if a particular swimming area frequently shows contamination, targeted interventions can be applied. Efficient use of statistics ensures public health safety while managing costs.
In summary, understanding probabilities and statistics is essential in making informed, data-driven decisions to protect public health.

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