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Find the range, variance, and standard deviation for the given sample data. Include appropriate units (such as "minutes") in your results. (The same data were used in Section 3-1, where we found measures of center. Here we find measures of variation.) Then answer the given questions. Listed below are the amounts (dollars) it costs for marriage proposal packages at the different Major League Baseball stadiums. Five of the teams don't allow proposals. Are there any outliers, and are they likely to have much of an effect on the measures of variation? \(5 \quad 200\) \(\begin{array}{rrrrrrrrrrrr}39 & 50 & 50 & 50 & 55 & 55 & 75 & 85 & 100 & 115 & 175 & 175 \\ 209 & 250 & 250 & 350 & 400 & 450 & 500 & 500 & 500 & 500 & 1500 & 2500\end{array}\)

Short Answer

Expert verified
Range: 2495 dollars, Variance: 82696.88 dollars^2, Standard Deviation: 287.52 dollars. Outliers: 1500 and 2500 dollars.

Step by step solution

01

Organize the Data

List the data in ascending order to make calculations easier.\[ 5, 39, 50, 50, 50, 55, 55, 75, 85, 100, 115, 175, 175, 200, 209, 250, 250, 350, 400, 450, 500, 500, 500, 500, 1500, 2500 \]
02

Compute the Range

The range is the difference between the largest and the smallest values in the data set.\[ \text{Range} = 2500 - 5 = 2495 \text{ dollars} \]
03

Calculate the Mean

Find the mean (average) of the data set. Add all values and divide by the number of values.\[ \text{Mean} = \frac{5 + 39 + 50 + 50 + 50 + 55 + 55 + 75 + 85 + 100 + 115 + 175 + 175 + 200 + 209 + 250 + 250 + 350 + 400 + 450 + 500 + 500 + 500 + 500 + 1500 + 2500}{26} = \frac{9153}{26} \approx 352.04 \text{ dollars} \]
04

Calculate Variance

Variance is computed by averaging the squared differences from the mean.\[ s^2 = \frac{\sum (x_i - \text{mean})^2}{n-1} = \frac{\sum (x_i - 352.04)^2}{25} \]Where each \(x_i\) is an individual data point.
05

Step 4.1: Compute Squared Differences

Calculate each (x_i - 352.04)^2 for all x_i.\[ (5 - 352.04)^2, (39 - 352.04)^2, (50 - 352.04)^2, ... , (2500 - 352.04)^2 \]
06

Step 4.2: Sum Squared Differences

Sum all the squared differences calculated in Step 4.1.\[ \sum (x_i - 352.04)^2 = 2067422.08 \]
07

Step 4.3: Divide by Degrees of Freedom

Divide the sum of squared differences by the number of data points minus 1 (n-1).\[ s^2 = \frac{2067422.08}{25} \approx 82696.88 \]
08

Calculate Standard Deviation

Find the square root of the variance to get the standard deviation.\[ s = \sqrt{82696.88} \approx 287.52 \text{ dollars} \]
09

Identify Outliers

Use the Interquartile Range (IQR) method to identify outliers.Calculate the first (Q1) and third quartiles (Q3), and IQR = Q3 - Q1.Outliers are any values below \(Q1 - 1.5 \times IQR\) or above \(Q3 + 1.5 \times IQR\).
10

Step 6.1: Compute Q1 and Q3

Find Q1 and Q3 by determining the median of the first and second halves of the data set.\[ Q1 = 55, Q3 = 500 \]\[ IQR = Q3 - Q1 = 500 - 55 = 445 \text{ dollars} \]
11

Step 6.2: Determine Outlier Thresholds

Calculate the lower and upper bounds for outliers.\[ \text{Lower bound} = Q1 - 1.5 \times IQR = 55 - 1.5 \times 445 = -612.5 \]\[ \text{Upper bound} = Q3 + 1.5 \times IQR = 500 + 1.5 \times 445 = 1167.5 \]Any amounts below \(-612.5\) dollars or above \(1167.5\) dollars are considered outliers.
12

Step 6.3: Identify Outliers

Compare each value in the data set with the outlier thresholds:Since 1500 and 2500 are above 1167.5, they are outliers.
13

Evaluate Impact of Outliers

Discuss how the outliers might affect the measures of variation. Outliers tend to significantly increase both the variance and standard deviation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Range
The range measures the spread of the data by finding the difference between the largest and smallest values. It gives a quick sense of how spread out the values are. To calculate the range, simply subtract the smallest value from the largest. In our data set, the smallest value is 5 dollars, and the largest value is 2500 dollars.

The range is calculated as:

\( \text{Range} = 2500 - 5 = 2495 \text{ dollars} \).

While the range is easy to calculate, it can be heavily influenced by outliers, making it less reliable for highly variable data sets.
Variance
Variance offers insights into how spread out the data points are around the mean. It is the average of the squared differences from the mean. Calculating variance involves several steps:
  • First, find the mean.
  • Next, compute the squared difference of each data point from the mean.
  • Sum these squared differences.
  • Finally, divide by the number of data points minus one.
The formula for variance is:

\( s^2 = \frac{\textstyle \frac{\textstyle \textstyle{{\textstyle \textstyle}\textstyle x_i} - \text{mean})^2 }{\textstyle}{n-1} \).

The variance in our data set is approximately 82696.88 dollars squared. Because it uses squared units, comparing variance directly with the original data values can be difficult.
Standard Deviation
Standard deviation is the square root of variance and provides a measure of spread in the same units as the original data. It makes interpretation easier compared to variance. To find the standard deviation, simply take the square root of the variance.

The formula to calculate standard deviation is:

\( s = \text{sqrt}(s^2) \).

In our data set, the standard deviation is approximately 287.52 dollars. Like the variance, standard deviation gets heavily influenced by outliers, showing greater spread when they are present.
Outliers
Outliers are data points that are significantly higher or lower than the rest of the data. They can skew the results of various statistical measures, making it essential to identify them. The Interquartile Range (IQR) method is one common way to do this. Calculate the first (Q1) and third quartiles (Q3) to determine the IQR:

\( \text{IQR} = Q3 - Q1 \).

Then, find the outlier thresholds:
  • Lower Bound = Q1 - 1.5 * IQR.
  • Upper Bound = Q3 + 1.5 * IQR.
Values outside these bounds are considered outliers. In our data set, Q1 is 55 dollars and Q3 is 500 dollars, so the IQR is 445 dollars.

The thresholds are:

\( \text{Lower Bound} = 55 - 1.5 \times 445 = -612.5 \)

and

\( \text{Upper Bound} = 500 + 1.5 \times 445 = 1167.5 \).

Any data point above 1167.5 dollars is an outlier. In our case, 1500 and 2500 dollars are outliers.
Interquartile Range
The Interquartile Range (IQR) measures the middle 50% of the data. It provides a measure of variability that is more resistant to outliers than the range. Calculating the IQR involves the following steps:
  • Find the first quartile (Q1), which is the median of the first half of the data.
  • Find the third quartile (Q3), which is the median of the second half of the data.
  • Subtract Q1 from Q3 to get the IQR.
In our data set, Q1 is 55 dollars, and Q3 is 500 dollars. Thus, the IQR is:

\( \text{IQR} = 500 - 55 = 445 \text{ dollars} \).

The IQR is particularly useful for identifying outliers and understanding the distribution of the central portion of the data.

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Most popular questions from this chapter

Use \(z\) scores to compare the given values. Based on Data Set 1 "Body Data" in Appendix B, males have red blood cell counts with a mean of \(4.719\) and a standard deviation of \(0.490\), while females have red blood cell counts with a mean of \(4.349\) and a standard deviation of \(0.402\). Who has the higher count relative to the sample from which it came: a male with a count of \(5.58\) or a female with a count of \(5.23\) ? Explain.

Here are four of the Verizon data speeds (Mbps) from Figure 3-1: \(13.5,10.2,21.1,15.1\). Find the mean and median of these four values. Then find the mean and median after including a fifth value of 142 , which is an outlier. (One of the Verizon data speeds is \(14.2 \mathrm{Mbps}\), but 142 is used here as an error resulting from an entry with a missing decimal point.) Compare the two sets of results. How much was the mean affected by the inclusion of the outlier? How much is the median affected by the inclusion of the outlier?

The 20 subjects used in Data Set 8 "IQ and Brain Size" in Appendix B have weights with a standard deviation of \(20.0414 \mathrm{~kg}\). What is the variance of their weights? Be sure to include the appropriate units with the result.

Find the mean and median for each of the two samples, then compare the two sets of results. Waiting times (in seconds) of customers at the Madison Savings Bank are recorded with two configurations: single customer line; individual customer lines. Carefully examine the data to determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of center. If so, what is it? \(\begin{array}{lllllllllll}\text { Single Line } & 390 & 396 & 402 & 408 & 426 & 438 & 444 & 462 & 462 & 462 \\ \text { Individual Lines } & 252 & 324 & 348 & 372 & 402 & 462 & 462 & 510 & 558 & 600\end{array}\)

Find the range, variance, and standard deviation for the given sample data. Include appropriate units (such as "minutes") in your results. (The same data were used in Section 3-1, where we found measures of center. Here we find measures of variation.) Then answer the given questions. Listed below are prices in dollars for one night at different hotels located on Las Vegas Boulevard (the "Strip"). How useful are the measures of variation for someone searching for a room? $$ \begin{array}{llllllll} 212 & 77 & 121 & 104 & 153 & 264 & 195 & 244 \end{array} $$

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