Chapter 5: Problem 56
Use the Law of Cosines to show that $$\cos A=\frac{(b+c-a)(b+c+a)}{2 b c}-1$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 5: Problem 56
Use the Law of Cosines to show that $$\cos A=\frac{(b+c-a)(b+c+a)}{2 b c}-1$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
In Exercises 67 to \(72,\) find the exact value of the given function. Given \(\sin \alpha=-\frac{7}{25}, \alpha\) in Quadrant IV, and \(\cos \beta=\frac{8}{17}, \beta\) in Quadrant IV, find \(\tan (\alpha+\beta)\)
$$\text { Prove that } c(\mathbf{v} \cdot \mathbf{w})=(c \mathbf{v}) \cdot \mathbf{w}$$.
A right triangle has sides of lengths \(3,4,\) and 5 inches. a. Find the perimeter of the triangle. b. Find the area of the triangle.
Evaluate \(\frac{\pi}{2}+2 k \pi\) for \(k=1,2,\) and 3.
$$\text { Prove that } \mathbf{v} \cdot \mathbf{w}=\mathbf{w} \cdot \mathbf{v}$$
What do you think about this solution?
We value your feedback to improve our textbook solutions.