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Assume that the given function has an inverse function. If \(f\) is a one-to-one function and \(f(0)=5, f(1)=2,\) and \(f(2)=7,\) find: a. \(f^{-1}(5)\) b. \(f^{-1}(2)\)

Short Answer

Expert verified
\(f^{-1}(5) = 0\) and \(f^{-1}(2) = 1\)

Step by step solution

01

Identify the Input for the Inverse Function

First we're tasked with finding the inverse function at the value 5, i.e., \(f^{-1}(5)\). We need to identify which input value \(x\) into the function \(f\) produced the output value 5.
02

Find the Corresponding Input Value

Looking back to the given values for \(f\), we can see that when \(x=0\) the function \(f\) returned 5. So, \(f^{-1}(5) = 0\).
03

Repeat for the other value

Next we're tasked with finding the inverse function at the value 2, i.e, \(f^{-1}(2)\). We need to identify which input value \(x\) into the function \(f\) produced the output value 2.
04

Find the corresponding input value

Looking back to the given values for \(f\), we see that when \(x=1\) the function \(f\) returned 2, so \(f^{-1}(2) = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-to-One Functions
Understanding one-to-one functions is essential in the realm of precalculus, especially when discussing the concept of inverse functions. A one-to-one function, also known as an injective function, is a type of mapping where each element of the function's domain (the set of all possible input values) is paired with a unique element of its range (the set of all possible output values). This means that no two different inputs can produce the same output.

Take the function from our exercise, for instance. We were told that when inputting 0, 1, and 2 into the function, the outputs were uniquely 5, 2, and 7, respectively. This is characteristic of one-to-one functions. The function must pass the 'Horizontal Line Test', which implies that if a horizontal line intersects the graph of the function at more than one point, then the function is not one-to-one, hence, not invertible.

In practical terms, if you think of the function as a party organizer matching guests to tables, a one-to-one function would mean every guest is seated at their own unique table. If two guests were assigned to the same table, it would not be one-to-one.
Finding Inverses of Functions
Turning to finding inverses of functions, this is akin to figuring out the original guest-list from the table assignments—the reverse process. The inverse of a function, denoted as \(f^{-1}\), essentially 'undoes' what the original function did. To find an inverse, we swap the input and output roles; if \(f(x)=y\), then \(f^{-1}(y)=x\). But, it is critical to remember that only one-to-one functions have inverses that are also functions.

Steps to Find a Function's Inverse

  • Write down the function equation, swapping the roles of \(x\) and \(y\).
  • Solve this new equation for \(y\), which will then represent \(f^{-1}(x)\).
The textbook exercise asked for \(f^{-1}(5)\) and \(f^{-1}(2)\), which involved identifying what inputs into the original function produced those specific outputs. This is a direct application of the concept of function inverses, where we utilize the given outputs to back-calculate their corresponding inputs.
Mapping of Functions
The mapping of functions is a visual or conceptual representation of how inputs are paired with outputs. Think of it as a system of roads on a map, with each input being a starting location and the outputs being the destinations. A function can be represented as a set of ordered pairs, with each pair consisting of an element from the domain and its corresponding element in the range.

For a one-to-one function, each input has its own unique destination. In contrast, functions that are not one-to-one will have some destinations (outputs) that can be reached from different starting points (inputs). The exercise provided demonstrates a one-to-one mapping—each input '0', '1', and '2' is paired with a distinct output '5', '2', and '7', similar to different landmarks on a map.

Understanding the mapping of functions is vital when exploring the concept of inverses since it allows us to trace back the route from each output to the singular starting point that leads us to it. This is what we accomplished by finding \(f^{-1}(5)\) and \(f^{-1}(2)\). Each output value in the range was traced back to one particular input in the domain, showcasing a perfect one-to-one correspondence.

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