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Find \(f^{-1}(x) .\) State any restrictions on the domain of \(f^{-1}(x)\) $$f(x)=\sqrt{4-x}, \quad x \leq 4$$

Short Answer

Expert verified
The inverse function is \(f^{-1}(x) = 4 - x^2\) with domain \(-\infty < x \leq 2\).

Step by step solution

01

Swap \(x\) and \(y\)

The first step in finding the inverse of a function is to swap \(x\) and \(y\). So we replace \(f(x)\) with \(y\) to get \(y = \sqrt{4-x}\) and then swap \(x\) and \(y\) to get \(x = \sqrt{4-y}\).
02

Solve for \(y\)

Next we solve the equation for \(y\). Squaring both sides to eliminate the square root, we get \(x^2 = 4-y\). Then move \(y\) to the left side and \(x^2\) to the right side to get \(y = 4 - x^2\).
03

Define the domain

Finally we need to state the domain of the inverse function. The domain of the original function was \(x \leq 4\), and since \(x\) and \(y\) are swapped in the inverse function, the domain of the inverse function is \(y \leq 4\) or \(-\infty < x \leq 2\). This is because the inverse function \(f^{-1}(x) = 4 - x^2\) is defined for all real numbers \(x\), but we must restrict it to \(x \leq 2\) to be consistent with the original function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
When dealing with inverse functions, understanding domain and range is crucial. The **domain** of a function is the set of all possible input values (usually represented as "x"), while the **range** is the set of all possible outputs (usually represented as "y"). For inverse functions, the domain and range swap roles. This means that for the inverse function, the range of the original function becomes the domain, and vice versa.

In the exercise provided, the domain of the original function is given as \((x \leq 4)\). This implies that the function takes input values of "x" up to and including 4. Consequently, when finding the inverse function, we swap the domain and range, resulting in the inverse having a domain of \((-\infty < x \leq 2)\). This restriction ensures that the inverse function maintains a one-to-one correspondence with the original function, providing consistent evaluations.
Square Root Functions
Square root functions are an important class of functions that involve the operation of taking the square root of an expression. The basic form is \(f(x) = \sqrt{a \cdot x + b}\) where "a" and "b" are constants. In our example, the square root function starts as \(f(x) = \sqrt{4-x}\).

A primary characteristic of square root functions is their domain limitations. Because you cannot take the square root of a negative number in the set of real numbers, you need to ensure that the expression inside the square root is non-negative. Thus, for \(f(x) = \sqrt{4-x}\), the values of \((4-x)\) must be non-negative. This means \(x\) must be less than or equal to 4, aligning with the traditional shift and transformation considerations of square root functions.

Square root functions generally produce output values (range) from zero upwards because the square root of a number is always non-negative (in real numbers). Therefore, the range of the original function \(\sqrt{4-x}\) will be from 0 to 2 (as a result of substituting the maximum input value).
Function Transformation
Function transformations involve shifting, stretching, compressing, or reflecting the graph of a function. Let's consider the given square root function \(f(x) = \sqrt{4-x}\). This function exemplifies a horizontal reflection and translation.

1. **Horizontal Reflection**: Since the "x" term is negated within the square root, \(4-x\) instead of \(x-4\), the square root function is horizontally reflected over the y-axis.
2. **Translation**: The "+ 4" inside the square root brackets shifts the graph horizontally to the right by four units. This step counterbalances the traditional root function's position.

Transformations are essential to ensure that the inverse function reflects the change perfectly, maintaining a one-to-one nature and the logical sequence of operations when reflected or transformed.

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