/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Find \(f^{-1}(x) .\) State any r... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(f^{-1}(x) .\) State any restrictions on the domain of \(f^{-1}(x)\) $$f(x)=x^{2}+1, \quad x \geq 0$$

Short Answer

Expert verified
The inverse function is \(f^{-1}(x) = \sqrt{x - 1}\) and its domain is \(x \geq 1\).

Step by step solution

01

Write down the equation.

First, consider the original equation, \(f(x) = x^2 + 1\). We will solve this equation for \(x\) to find \(f^{-1}(x)\).
02

Swap \(x\) and \(y\)

Next, interchange the roles of \(x\) and \(y\) in the equation. Thus we get \(x = y^2 + 1\).
03

Solve for \(y\)

Determine the value of \(y\). Subtract 1 from both sides to get \(x - 1 = y^2\). To isolate \(y\), we can take the square root of both sides. However, we should remember that the square root function includes both positive and negative roots. Since our original function is defined for \(x \geq 0\), the square root will only take the positive value. The inverse function is thus \(y = \sqrt{x - 1}\).
04

Establish the domain of \(f^{-1}(x)\)

Finally, we need to determine the domain of the inverse function \(f^{-1}(x)\), which is the set of possible values for \(x\). For the value under the square root to be a real number, \(x-1\) must be greater than or equal to 0. Therefore, the domain for \(f^{-1}(x)\) is \(x \geq 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finding the Inverse Function
When working with functions in precalculus, one interesting concept is that of the inverse function. Essentially, finding the inverse function, denoted as \(f^{-1}(x)\), involves reversing the original function to solve for the input given the output.

Imagine a function as a machine where you input 'x' and get out 'f(x)'. The inverse function reverses this process. If you know 'f(x)', you can determine the corresponding 'x'. The steps are straightforward: write down the original equation, swap 'x' and 'y', and then solve for 'y'.

This process often requires algebraic manipulation, such as factoring, dividing, or in our case, invoking the square root function. The aim is to isolate 'y' on one side of the equation to establish the inverse function. It's a critical skill in precalculus problem-solving and has practical applications in many areas including calculus and beyond.
Domain Restrictions of Inverse Functions
Understanding the domain restrictions of an inverse function is paramount to accurately utilizing and graphing these functions. Just as the domain of a function consists of all possible input values 'x', the domain of the inverse is the range of the original function and vice versa.

However, not all functions have inverses that are also functions. For an inverse to be a function, each input must correspond to exactly one output. This is known as the Horizontal Line Test. If any horizontal line crosses the function more than once, the function doesn't have an inverse that is also a function, unless we restrict the domain.

For example, the function \(f(x) = x^2\) doesn't have an inverse that's a function over all real numbers because it fails the Horizontal Line Test. Yet, by restricting the domain (like in our exercise to \(x \geq 0\)), we ensure the inverse also passes this test and thus behaves as a function. Understanding domain restrictions helps avoid assigning multiple outputs to a single input in the inverse, maintaining its function status.
Square Root Functions
Square root functions make frequent appearances in inverse function problems, especially when the original function involves squaring an input. The square root function, denoted as \(\sqrt{x}\), brings us back to the number which, when squared, results in 'x'. However, it's crucial to remember that every positive number actually has two square roots - one positive and one negative.

In our exercise, the original function is \(f(x) = x^2 + 1\), for which the inverse involves the principle (positive) square root, since the domain was restricted to \(x \geq 0\). In contrast, had there been no such restriction, considering both positive and negative square roots would've been necessary, but the result would not have been a function. Thus, paying attention to the domain is critical when dealing with square root functions to maintain function properties.
Precalculus Problem Solving
Problem-solving in precalculus involves more than just crunching numbers; it requires understanding concepts and applying them in a step-by-step manner. An effective strategy starts with a clear definition of the problem - in our case, finding the inverse function and its domain.

Step-by-step solutions guide learners through the reasoning process, from manipulating expressions to examining the implications of each operation. Recognizing patterns, such as the correlation between an equation involving squares and its inverse involving square roots, is a key skill. Also, awareness of the inherent limitations or restrictions, like those on domain and range, is essential.

As we solve problems, we're also learning to communicate our reasoning clearly, which is a valuable skill in any analytical or technical field. Therefore, while tackling precalculus exercises, remember that the journey through each problem enhances your broader mathematical understanding and ability to think critically.

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