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Explain how to use the graph of the first function \(f\) to produce the graph of the second function \(F\). $$f(x)=\left(\frac{3}{2}\right)^{x}, F(x)=\left(\frac{3}{2}\right)^{-x}$$

Short Answer

Expert verified
The graph of \(F(x) = \left(\frac{3}{2}\right)^{-x}\) can be obtained from the graph of \(f(x) = \left(\frac{3}{2}\right)^x\) by reflecting the graph of \(f\) in the y-axis. This is because a change in sign in the exponent is equivalent to reflecting the function in relation to the y-axis.

Step by step solution

01

Sketch the graph of the first function

Start by plotting the graph of the function \(f(x)=\left(\frac{3}{2}\right)^{x}\). The graph will be exponential with a base \(>\) 1, which means that it will increase as \(x\) increases, crossing the y-axis at \(y=1\).
02

Understand the effect of the negative exponent

Now, note that \(F(x)\) is obtained from \(f(x)\) by replacing \(x\) with \(-x\). This is a reflection of the function in the y-axis. This means, if the original function \(f\) was increasing, the function \(F\) will be decreasing.
03

Create the graph of the second function

Finally, draw the graph of \(F(x)=\left(\frac{3}{2}\right)^{-x}\). Notice that for any given \(x\), \(F(x)\) is the reciprocal of \(f(x)\). So, where \(f(x)\) was above the x-axis (meaning its y-values were greater than 1), \(F(x)\) will be below it (y-values will be less than 1), and vice versa. The graph of \(F(x)\) will also cross the y-axis at \(y=1\), but it will decrease as \(x\) increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Negative Exponents
A negative exponent signifies taking the reciprocal of the base raised to the absolute value of the exponent. In simpler terms, when you see an expression like \(a^{-n}\), this is equivalent to \(\frac{1}{a^n}\). Understanding this concept is crucial when graphing exponential functions.

For instance, if you have the function \(f(x) = (\frac{3}{2})^{x}\), applying a negative exponent will transform this function into \(F(x) = (\frac{3}{2})^{-x} = \frac{1}{(\frac{3}{2})^{x}}\). In essence, for every value of \(x\), you would be looking at the reciprocal of what \(f(x)\) would originally produce. This plays an integral role in how the graph of the function \(F\) will look as it will be a mirror image of \(f\) across the y-axis.
Exponential Function Transformations
Transformations in exponential functions include operations such as shifting, reflecting, stretching, or compressing the graph. An exponential function of the form \(c \cdot a^{(b\cdot x + d)} + h\), where \(c\), \(a\), \(b\), \(d\), and \(h\) dictate these transformations, adopts various shapes and orientations based on their values.

Reflecting across the Y-Axis

Specifically, when we apply a negative exponent, we're implementing a horizontal reflection. In our exercise, converting \(f(x)\) into \(F(x) = f(-x)\) mirrors every point of the graph across the y-axis, meaning the point \( (x, y) \) in \(f\) would become \( (-x, y) \) in \(F\). This is a fundamental concept in understanding how the shape and position of the graph change when the signs of the exponents are altered.
Reflecting Functions Across Axes
Reflections are a type of transformation that 'flip' the graph over a specific axis. When reflecting a function across the y-axis, as seen with \(f(x)\) and \(F(x)\), the x-coordinates of the graph's points change sign while the y-coordinates remain the same.

Imagine the y-axis as a mirror; the graph of \(f(x)\) serves as the original image, and \(F(x)\) is its mirror image. So, any points that are \(k\) units to the right of the y-axis on the graph of \(f(x)\) will now be \(k\) units to the left for \(F(x)\). The graphs will have the same vertical intercepts as these points lie directly on the mirror line itself. The overarching rule is that if \(f(x)\) has a point \( (a, b) \), then after reflection in the y-axis, the corresponding point in \(F(x)\) will be \( (-a, b) \)—this is crucial in drawing accurate reflections for exponential functions.

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