Chapter 3: Problem 13
Change each equation to its logarithmic form. Assume \(y>0\) and \(b>0\). $$4^{-2}=\frac{1}{16}$$
Short Answer
Expert verified
The logarithmic form of the equation \(4^{-2}=\frac{1}{16}\) is \(\log_4 \frac{1}{16} = -2\).
Step by step solution
01
Identify the components
For the equation \(4^{-2}=\frac{1}{16}\), \(4\) is the base \(b\), \(-2\) is the exponent \(y\), and \(\frac{1}{16}\) is the result \(x\). In an exponential equation, the base raised to the power of the exponent equals the result, which correlates to \(b^y = x\).
02
Apply the logarithm form
To convert the equation to logarithmic form, use the formula \(\log_b x = y\). Substitute \(b=4\), \(x=\frac{1}{16}\) and \(y=-2\) into the formula \(\log_b x = y\).
03
Write the final equation
The logarithmic form of the equation is \(\log_4 \frac{1}{16} = -2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Equations
Understanding exponential equations is crucial for students delving into algebra and higher-level mathematics. An exponential equation is a form where a constant base is raised to a variable exponent, producing a certain result. The general format of an exponential equation is \( b^y = x \), where \( b \) is the base, \( y \) is the exponent, and \( x \) represents the result or the output.
In the sample problem \( 4^{-2} = \frac{1}{16} \), recognizing that \( 4 \) is continually multiplied by itself in negative exponent form simplifies to \( \frac{1}{4^2} \), which equals \( \frac{1}{16} \). This illustrates how the base and the exponent relate to the result.
There are keys to solving these equations effectively:
In the sample problem \( 4^{-2} = \frac{1}{16} \), recognizing that \( 4 \) is continually multiplied by itself in negative exponent form simplifies to \( \frac{1}{4^2} \), which equals \( \frac{1}{16} \). This illustrates how the base and the exponent relate to the result.
There are keys to solving these equations effectively:
- Identifying the base, exponent, and the result.
- Understanding the rules of exponents, such as negative exponents translating to reciprocals.
- Manipulating the equation to isolate the variable, if necessary.
Exponents
Exponents represent how many times a number, known as the base, is multiplied by itself. For example, \( 4^2 \) signifies \( 4 \) multiplied by itself twice. Negative exponents, such as \( -2 \) in the given problem \( 4^{-2} \) imply the reciprocal, meaning \( 4^{-2} = \frac{1}{4^2} \).
A solid grasp of exponent rules is vital when working with exponential equations. Some of these rules are:
When you encounter a tricky exponential equation, remember these rules to simplify the expression.
A solid grasp of exponent rules is vital when working with exponential equations. Some of these rules are:
- The Product Rule (\( a^m \cdot a^n = a^{m+n} \))
- The Quotient Rule (\( \frac{a^m}{a^n} = a^{m-n} \))
- The Power Rule ((\( (a^m)^n = a^{mn} \))
- Zero Exponent Rule (\( a^0 = 1 \), for \( a eq 0 \))
- Negative Exponent Rule (\( a^{-n} = \frac{1}{a^n} \))
When you encounter a tricky exponential equation, remember these rules to simplify the expression.
Logarithms
Logarithms are essentially the inverse of exponential functions, offering a different perspective on the relationship between the base, exponent, and result. To express \( b^y = x \) logarithmically, one would use the form \( \log_b x = y \), where \( \log \) denotes the logarithm, \( b \) is the base, \( x \) is the result we had from the exponential equation, and \( y \) remains the exponent.
In the sample exercise, the equation \( 4^{-2} = \frac{1}{16} \) converted into logarithmic form becomes \( \log_4 \frac{1}{16} = -2 \). This equation now tells us that the logarithm of \( \frac{1}{16} \) with base \( 4 \) is \( -2 \).
Here’s how one can understand logarithms:
In the sample exercise, the equation \( 4^{-2} = \frac{1}{16} \) converted into logarithmic form becomes \( \log_4 \frac{1}{16} = -2 \). This equation now tells us that the logarithm of \( \frac{1}{16} \) with base \( 4 \) is \( -2 \).
Here’s how one can understand logarithms:
- A logarithm asks the question: To what exponent must we raise the base to produce a certain number?
- Logarithmic and exponential forms are interchangeable using the base and the result.
- Calculations become easier when converting certain exponential forms to logarithmic form, particularly in solving for unknown exponents.