Chapter 2: Problem 37
Use synthetic division and the Factor Theorem to determine whether the given binomial is a factor of \(P(x)\). $$P(x)=2 x^{3}+x^{2}-3 x-1, x+1$$
Short Answer
Expert verified
No, the binomial \(x + 1\) is not a factor of the polynomial \(P(x) = 2x^3 + x^2 - 3x - 1\).
Step by step solution
01
Convert the Binomial into a Usable Format for Synthetic Division
Convert the binomial factor into the form \(x - c\) (needed for synthetic division). Here, that translates to \(x - (-1)\) which is \(x + 1\). So, \(c = -1\).
02
Prepare for Synthetic Division
List the coefficients of \(P(x)\) in descending order of their associated power of x. Our polynomial has the terms arranged as \(2x^3 + x^2 - 3x - 1\). So the coefficients are \(2, 1, -3,-1\). Also, remember the value of \(c\) from the earlier step: \(c = -1\).
03
Perform Synthetic Division
Perform synthetic division with the coefficients of \(P(x)\) and the value of \(c\). Usual synthetic division rules apply: drop down the first coefficient, multiply by \(c\), add down, then repeat until done. Listed here are the results of those operations lined up underneath their counterparts: \n\n- -1 | 2 1 -3 -1 \n -2 1 2 \n -----------------\n 2 -1 -2 1 \n\nFinal row of numbers from the division are 2, -1, -2, and 1. These represent the coefficients of the quotient polynomial.
04
Interpret the Results
If the binomial is a factor of \(P(x)\), the remainder (the last number on the bottom row from synthetic division) should equal to zero. Here, the remainder is 1, not zero. Thus, \(x + 1\) is not a factor of \(P(x)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factor Theorem
Factor Theorem is a powerful concept that can help determine whether a given binomial is a factor of a polynomial. The theorem states that if a polynomial \(P(x)\) has a factor \(x - c\), then \(P(c) = 0\). This means, in simpler terms: if you substitute \(c\) into the polynomial and the result is zero, \(x - c\) is a factor. This process uses the root of the binomial (the \(c\) in \(x - c\)).
In the problem at hand, we consider the polynomial \(P(x) = 2x^3 + x^2 - 3x - 1\) and the binomial \(x + 1\), we convert the binomial to the form \(x - c\), giving us \(c = -1\). By substituting \(-1\) into \(P(x)\):
In the problem at hand, we consider the polynomial \(P(x) = 2x^3 + x^2 - 3x - 1\) and the binomial \(x + 1\), we convert the binomial to the form \(x - c\), giving us \(c = -1\). By substituting \(-1\) into \(P(x)\):
- We calculate \(P(-1)\) to verify if it equals zero.
- If it does, \(x+1\) is a factor.
- If not, \(x+1\) is not a factor.
Polynomial Division
When working with polynomials, division is as essential as addition and multiplication. Polynomial division allows you to express a polynomial as the product of its factors, plus a remainder. Similar to long division, but instead of numbers, you divide polynomials. There are two primary methods: long division and synthetic division.
**Synthetic Division:**Synthetic division is a streamlined way of dividing a polynomial by a binomial of the form \(x - c\). It involves only the coefficients of the polynomials, making it a much simpler and faster process. For the polynomial \(P(x) = 2x^3 + x^2 - 3x - 1\) and the factor \(x + 1\), we first rewrite \(x + 1\) as \(x - (-1)\) to meet the needs of synthetic division, where \(c = -1\).
*Steps involved in Synthetic Division:*
**Synthetic Division:**Synthetic division is a streamlined way of dividing a polynomial by a binomial of the form \(x - c\). It involves only the coefficients of the polynomials, making it a much simpler and faster process. For the polynomial \(P(x) = 2x^3 + x^2 - 3x - 1\) and the factor \(x + 1\), we first rewrite \(x + 1\) as \(x - (-1)\) to meet the needs of synthetic division, where \(c = -1\).
*Steps involved in Synthetic Division:*
- List the coefficients of \(P(x)\).
- Drop the first coefficient down after setting up the division with the box containing \(c = -1\).
- Multiply \(-1\) by the dropped coefficient, and place the result below the next coefficient, then add down.
- Repeat until all coefficients have been processed.
Remainder Theorem
The Remainder Theorem is intimately linked with both the Factor Theorem and synthetic division. It tells us that when a polynomial \(P(x)\) is divided by \(x - c\), the remainder of that division is \(P(c)\). This can be utilized to find out if \(x - c\) is a factor of \(P(x)\) simply by checking if \(P(c) = 0\).
In our exercise, using synthetic division on \(P(x) = 2x^3 + x^2 - 3x - 1\) with \(c = -1\), we ended with a remainder of 1.
In our exercise, using synthetic division on \(P(x) = 2x^3 + x^2 - 3x - 1\) with \(c = -1\), we ended with a remainder of 1.
- If the remainder is zero, it signifies that \(x - c\) is indeed a factor.
- If not, like in this case, the binomial is not a factor since the remainder isn't zero.