Chapter 1: Problem 36
Graph each equation by plotting points that satisfy the equation. $$y=x^{2}-2 x-8$$
Short Answer
Expert verified
The vertex of the parabola is (1, -9) and it opens upwards. Two additional points that lie on the graph are (0, -8) and (2, -8).
Step by step solution
01
Identify the Form of the Equation
The given equation \(y = x^2 - 2x - 8\) is in the form \(y = ax^2 + bx + c\) where a=1, b=-2, and c=-8. From the value of `a` which is 1 (a positive number), we know that the graph opens upwards.
02
Determine the Vertex of the Parabola
In this form of the equation, the vertex of the graph, a point \((h,k)\), can be found by using the formula \(h = -b/2a\) to find `x`, and then substituting `h` into the original equation to get `y`. In this case, \(h = -(-2)/2*1 = 1\), substituting that into the original equation gives \(y = (1)^2 - 2*(1) - 8 = -9\) . So, the vertex is \((1, -9)\).
03
Find Additional Points for the Graph
To get a nice sketch of the graph, choose a couple of points smaller and larger than `h`. Here, we can select 0 and 2. When \(x=0, y = (0)^2 - 2*(0) - 8 = -8\), so we have the point \((0, -8)\). When \(x=2, y = (2)^2 - 2*(2) - 8 = -8\), and we have another point \((2, -8)\).
04
Graph the Equation
Now, plot the vertex and the two extra points on your graph. Draw a smooth curve through these points. Because the parabola opens upward, extend the ends of the graph upwards on both sides.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Parabolas
A parabola is a U-shaped curve that can open either upwards or downwards. It is the graph of a quadratic equation of the form \( y = ax^2 + bx + c \). The direction in which a parabola opens is determined by the coefficient \( a \). If \( a \) is positive, the parabola opens upward, and if it's negative, it opens downward. In the equation \( y = x^2 - 2x - 8 \), the coefficient \( a = 1 \) is positive, so this parabola opens upward, resembling a smiling face.
This visual characteristic is crucial because it helps predict how the graph behaves as \( x \) moves away from the vertex. Parabolas are symmetrical, meaning the left side is a mirror image of the right side, which is foundational when graphing.
This visual characteristic is crucial because it helps predict how the graph behaves as \( x \) moves away from the vertex. Parabolas are symmetrical, meaning the left side is a mirror image of the right side, which is foundational when graphing.
Finding the Vertex of a Parabola
The vertex of a parabola is its highest or lowest point, serving as a critical plot point. For the quadratic equation \( y = ax^2 + bx + c \), the vertex can be found using a formula for the x-coordinate of the vertex \( h = -\frac{b}{2a} \). After identifying \( h \), you substitute it back into the equation to find \( k \), the y-coordinate.
For the equation \( y = x^2 - 2x - 8 \), \( a = 1 \) and \( b = -2 \). Using the formula, we calculate \( h = 1 \). Substituting \( h \) back into the equation, \( y = 1^2 - 2(1) - 8 \), results in \( k = -9 \). Hence, our vertex is located at \( (1, -9) \).
Understanding how to find the vertex is essential for graphing, providing insight into the parabola's axis of symmetry and its extremity point.
For the equation \( y = x^2 - 2x - 8 \), \( a = 1 \) and \( b = -2 \). Using the formula, we calculate \( h = 1 \). Substituting \( h \) back into the equation, \( y = 1^2 - 2(1) - 8 \), results in \( k = -9 \). Hence, our vertex is located at \( (1, -9) \).
Understanding how to find the vertex is essential for graphing, providing insight into the parabola's axis of symmetry and its extremity point.
Plotting Points on a Parabola
Plotting points is a straightforward way to graph a parabola by calculating y-values for various x-values. Once the vertex is located, as demonstrated earlier, additional points can be calculated by choosing x-values around the vertex, both smaller and larger.
For the equation \( y = x^2 - 2x - 8 \), after finding the vertex at \( (1, -9) \), we calculate additional points by picking \( x = 0 \) and \( x = 2 \). Substituting these into the equation results in points \( (0, -8) \) and \( (2, -8) \).
It's beneficial to choose x-values on both sides of the vertex to ensure symmetry and accuracy in the curve's path. By plotting these points, you prepare for sketching a smooth, continuous curve that forms the parabola.
For the equation \( y = x^2 - 2x - 8 \), after finding the vertex at \( (1, -9) \), we calculate additional points by picking \( x = 0 \) and \( x = 2 \). Substituting these into the equation results in points \( (0, -8) \) and \( (2, -8) \).
It's beneficial to choose x-values on both sides of the vertex to ensure symmetry and accuracy in the curve's path. By plotting these points, you prepare for sketching a smooth, continuous curve that forms the parabola.
Applying the Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations and finding x-intercepts or roots. However, in the context of graphing, it helps gain a deeper understanding of the parabola's behavior.
For a quadratic equation \( ax^2 + bx + c = 0 \), the solutions for \( x \) are given by \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]. This formula can identify the x-intercepts by solving \( y = 0 \) for the given quadratic equation.
Although not necessary for graphing, knowing the roots, if they exist, helps graphers understand where the parabola crosses the x-axis, thus broadening the comprehension of the graph's orientation and intercepts. It's a complement to point-plotting, providing a fuller graphical picture.
For a quadratic equation \( ax^2 + bx + c = 0 \), the solutions for \( x \) are given by \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]. This formula can identify the x-intercepts by solving \( y = 0 \) for the given quadratic equation.
Although not necessary for graphing, knowing the roots, if they exist, helps graphers understand where the parabola crosses the x-axis, thus broadening the comprehension of the graph's orientation and intercepts. It's a complement to point-plotting, providing a fuller graphical picture.