Chapter 5: Problem 11
Solve proportion. \(\frac{a}{3}=\frac{14}{21}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 5: Problem 11
Solve proportion. \(\frac{a}{3}=\frac{14}{21}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
In Exercises \(9-14\), is the triangle with sides of the given lengths a right triangle? \(3 \sqrt{3} \mathrm{cm}, 6 \mathrm{cm}, 3 \mathrm{cm}\)
Draw segments \(\overline{A B}, \overline{C D},\) and \(\overline{E F}\) such that \(A B\) is about 2 inches, \(C D\) is about 3 inches, and \(E F\) is about 4 inches. Construct \(\overline{U V}\) so that \(\frac{A B}{C D}=\frac{E F}{U V}\)
State whether the polygons are always, sometimes, or never similar. A right triangle and an acute triangle.
Prove that the ratio of the perimeters of two similar triangles equals the ratio of the lengths of any two corresponding sides.
The sides of a triangle are in the ratio of \(3: 4: 5 .\) If the perimeter is 90 centimeters, find the lengths of each side.
What do you think about this solution?
We value your feedback to improve our textbook solutions.