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Solve each right triangle in Exercises \(1-18 .\) Remember that \(m \angle C=90^{\circ} .\) Round to the same number of decimal places as in the given information. $$a=12 \text { and } c=13$$

Short Answer

Expert verified
The missing side is \(b = 5\). The angles are \(\angle A \approx 22.62^{\text{°}}\) and \(\angle B \approx 67.38^{\text{°}}\).

Step by step solution

01

- Identify the given information

The given sides of the right triangle are: \(a = 12\) and \(c = 13\), where \(a\) is one of the legs, and \(c\) is the hypotenuse.
02

- Use the Pythagorean Theorem

Apply the Pythagorean theorem: \[ a^2 + b^2 = c^2 \] Plug in the given values: \[ 12^2 + b^2 = 13^2 \] \[ 144 + b^2 = 169 \]
03

- Solve for the missing side \(b\)

Rearrange the equation to isolate \(b^2\): \[ b^2 = 169 - 144 \] \[ b^2 = 25 \] Take the square root of both sides: \( b = 5 \)
04

- Calculate the angles using trigonometric ratios

Use the definition of the cosine function to find \(\angle A\): \[ \cos(A) = \frac{a}{c} = \frac{12}{13} \] Find \(\angle A\) using the inverse cosine function: \[ A = \cos^{-1}(\frac{12}{13}) \approx 22.62^{\text{°}} \] Since \(m \angle C = 90^{\text{°}} \), \(\angle B\) can be found as: \[ B = 90^{\text{°}} - A \approx 90^{\text{°}} - 22.62^{\text{°}} \approx 67.38^{\text{°}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Theorem
The Pythagorean Theorem is a fundamental tool in geometry, especially for right triangles. It states that in a right triangle, the sum of the squares of the two legs is equal to the square of the hypotenuse. This can be written as: \[ a^2 + b^2 = c^2 \].

Here, \(a\) and \(b\) are the lengths of the legs, and \(c\) is the length of the hypotenuse.
In the given problem, \(a = 12\) and \(c = 13\).
We rearranged the Pythagorean Theorem to solve for \(b\):
\[ b^2 = c^2 - a^2 \]
Plugging in the values, we found: \[ b^2 = 169 - 144 = 25 \]
And then taking the square root of both sides, we found \(b = 5\).

Useful tip: Always make sure to double-check your calculations for accuracy.
Trigonometric Ratios
Trigonometric ratios are ratios of two sides of a right triangle. There are three primary trigonometric ratios: sine, cosine, and tangent. These ratios help in finding missing angles or sides of right triangles.
For angle \(A\) in the given triangle:
  • Cosine (cos): \( \text{cos}(A) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{a}{c} \)
  • Sine (sin): \( \text{sin}(A) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{b}{c} \)
  • Tangent (tan): \( \text{tan}(A) = \frac{\text{opposite}}{\text{adjacent}} = \frac{b}{a} \)
Using the given values, \(\text{cos}(A) = \frac{12}{13}\), which is found by the ratio of the length of the adjacent side to the hypotenuse.
Inverse Cosine
The inverse cosine function, also known as \(\text{cos}^{-1}\), allows us to find an angle when we know the cosine of that angle. It's a powerful function for solving right triangles.
To find angle \(A\) in our problem, we used the inverse cosine function:\( A = \text{cos}^{-1}\bigg(\frac{12}{13}\bigg) \approx 22.62^\text{°} \).

Remember that a right triangle's angles always add up to \(90^\text{°}\).
So, to find the remaining angle \(B\), we calculated:
\( B = 90^\text{°} - 22.62^\text{°} \approx 67.38^\text{°} \).

Note: Always ensure your calculator is set to degree mode when working with angles in degrees!

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