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A \(95 \%\) confidence interval for the ages of the first six presidents at their inaugurations is \((56.2,59.5)\). Either interpret the interval or explain why it should not be interpreted.

Short Answer

Expert verified
The 95% confidence interval of (56.2,59.5) represents that if it were possible to take 100 random samples of sets of first six U.S. presidents, the average inauguration age would lie within this interval 95 times. However, this is somewhat moot as we have discrete age data and not a continually variability subject to sampling.

Step by step solution

01

Understanding Confidence Interval

A confidence interval in statistics is a range of values, derived from data, which is likely to contain the value of an unknown population parameter. The level of confidence of the confidence interval would indicate the probability that the confidence range captures this true population parameter given a distribution of samples. A 95% level of confidence would mean that if we take many samples and for each sample compute a 95% confidence interval, then for 95% of the samples, the confidence interval will contain the population mean.
02

Interpretation of Confidence Interval

The provided 95% confidence interval is (56.2,59.5). Specifically, it suggests that if we were to take 100 random samples, then 95 out of 100 times, the average age of the first six U.S. presidents at their inaugurations would fall between 56.2 and 59.5.
03

Evaluation of Interpretation Validity

However, the interpretation carries limitations as being inferential. First, the case of averages of the first six U.S. presidents' inauguration ages isn't subjected to sampling since we have well-documented ages as discrete data. Second, even if we were to consider the 95% confidence interval brute-forced onto this data, it represents a population parameter for an 'imaginary' population, making the classical confidence interval approach less meaningful.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Statistics
When we talk about statistics, we're diving into the realm of data and how we can make sense of it. Statistics are the tools that allow us to collect, analyze, interpret, and present data in a meaningful way. It's all about gaining information from numbers to make decisions or predictions. In the classroom, students often encounter statistics when they look at different types of data sets and try to determine trends, averages, or patterns. For instance, examining the ages of the first six U.S. presidents at their inauguration requires statistical analysis to identify the average age, which can be a point of interest for historians or political scientists.

One of the most fundamental statistical tools is the confidence interval. It's a way of expressing uncertainty in estimated figures. A confidence interval gives us a range within which we usually expect the true value to fall, and it comes with a certain level of confidence or probability, say 95%. It's key to remember that while statistics can give us a powerful insight into data, they also come with limitations and assumptions that must be clearly understood and considered.
What are Population Parameters?
Population parameters are numerical values that summarize the characteristics of an entire population. For example, the average age of all present and past U.S. presidents at inauguration is a parameter that tells something about this specific group. When statisticians use the term 'population', they refer to the full set of subjects or events they're interested in - it could be the entire group of people living in a city, all the trees in a forest, or every coin minted in a year.

Importantly, we often can't measure every individual in a population due to time, cost or logistical restraints. That's where statistical inference comes in. We use a sample - a subset of the population - to estimate population parameters. This is where the idea of a confidence interval is crucial; it's used to estimate the unknown parameter with a stated level of confidence.
The Role of Sampling Distribution
Sampling distribution is a statistical term that represents the range of values that a given statistic (like an average or a mean) can take. This range is built based on the results from many random samples taken from a population. In simpler terms, if we repeatedly took samples and calculated the average or any other statistic for each sample, the sampling distribution would show us how those statistics are spread out.

Why is this concept important? Because it forms the very backbone of inferential statistics, allowing us to use samples to make generalizations about populations. For example, if we wanted to understand the average age at which U.S. presidents are inaugurated, we don’t have to look at each and every president; we can examine a sample and use the sampling distribution to estimate the average for all presidents. This distribution, in many situations, follows a normal curve, which is fundamental for calculating confidence intervals.
Interpreting Confidence Intervals
A 95% confidence interval is one of the most common types of intervals used in statistics. It provides a range that is likely to include the population parameter with a 95% probability. In our presidential ages example, the confidence interval (56.2, 59.5) implies that there's a 95% chance that the average inauguration age of all presidents (if they could be repeatedly sampled) falls between these two numbers.

However, interpreting confidence intervals requires care. They are not about the probability of the parameter falling in the range. Instead, they are about the method's reliability: if we were to repeat the sampling many times, 95% of the computed intervals would capture the true average age. In cases where the data points are a complete set - such as the first six U.S. presidents - a confidence interval might not be the appropriate statistical tool, because we have exact ages, and there's no sampling uncertainty to account for.

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Most popular questions from this chapter

Use the data from exercise \(9.36\). a. Using the four-step procedure with a two-sided alternative hypothesis, should you be able to reject the hypothesis that the population mean is 5 pounds using a significance level of \(0.05\) ? Why or why not? The confidence interval is reported here: I am \(95 \%\) confident the population mean is between \(4.9\) and \(5.3\) pounds. b. Now test the hypothesis that the population mean is not 5 pounds using the four-step procedure. Use a significance level of \(0.05\) and number your steps.

Construct heights for 3 or more sets of twins \((6\) or more people). Make the twins similar, but not exactly the same, in height. Put all of the shorter twins in set A and all of the taller twins in set B. Create the numbers such that a two-sample \(t\) -test will \(n o t\) show a significant difference in the mean heights of the shortest of each pair, and the mean heights of the tallest of each pair, but the paired \(t\) -test does show a significant difference. (Hint: Make one of the pairs really tall, one of the pairs really short, and one of the pairs in between.) Report all the numbers and the \(t\) - and \(\mathrm{p}\) -values for the tests. Explain why the paired \(t\) -test shows a difference and the twosample \(t\) -test does not show a difference. Remember that 5 feet is 60 inches and that 6 feet is 72 inches.

According to a 2018 Money magazine article, the average income in Kansas is $$\$ 53,906$$. Suppose the standard deviation is $$\$ 3000$$ and the distribution of income is rightskewed. Repeated random samples of 400 Kansas residents are taken, and the sample mean of incomes is calculated for each sample. a. The population distribution is right-skewed. Will the distribution of sample means be Normal? Why or why not? b. Find and interpret a \(z\) -score that corresponds with a sample mean of $$\$ 53,606 .$$ c. Would it be unusual to find a sample mean of $$\$ 54,500 ?$$ Why or why not?

The mean age of all 118 used Toyota vans for sale (see exercise \(9.16\) ) was \(3.1\) years with a standard deviation of \(2.7\) years. The distribution of ages is rightskewed. For a statistics project, a student randomly selects 35 vans from this data set and finds the mean of the sample is \(2.7\) years with a standard deviation of \(2.1\) years. a. Find each of these values: \(\mu=? \quad \sigma=? \bar{x}=? \quad s=?\) b. Which of the values listed in part a are parameters? Which are statistics? c. Are the conditions for using the CLT fulfilled? What would be the shape of the approximate sampling distribution of a large number of means, each from a sample of 35 vans?

In exercise \(9.31\), two intervals were given for the same data, one for \(95 \%\) confidence and one for \(90 \%\) confidence. a. How would a \(99 \%\) interval compare? Would it be narrower than both. wider than both, or between the two in width. Explain. b. If we wanted to use a \(99 \%\) confidence level and get a narrower width. how could we change our data collection?

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