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A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and weighed the bags. They weighed \(10.2,10.5,10.3\), and \(10.3\) pounds. Assume that the distribution of weights is Normal. Find a \(95 \%\) confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. a. Decide whether each of the following three statements is a correctly worded interpretation of the confidence interval, and fill in the blanks for the correct option(s). i. I am \(95 \%\) confident that the population mean is between ____. ii. There is a \(95 \%\) chance that all intervals will be between ____. and ____. iii. I am \(95 \%\) confident that the sample mean is between____. and ____. b. Does the interval capture 10 pounds? Is there enough evidence to reject the null hypothesis that the population mean weight is 10 pounds? Explain your answer.

Short Answer

Expert verified
a: i. is the correct interpretation. The 95% confidence interval extends from the lower bound to the upper bound calculated. ii. and iii. are incorrectly worded. b: Whether the interval captures 10 pounds or not depends on the exact confidence interval calculated. If it includes 10, then the null hypothesis, which states the population mean is 10 pounds, cannot be rejected. Otherwise, it is rejected.

Step by step solution

01

Find the Sample Mean and Standard Deviation

Start by finding the sample mean and sample standard deviation. The sample mean \(\bar{x}\) is the sum of the sample weights divided by the number of samples. The sample standard deviation \(s\) can be found using a calculator or statistics software.
02

Determine the Confidence Interval

The 95% confidence interval for a normal distribution is the sample mean ± 1.96 times the standard error. The standard error is the standard deviation divided by the square root of the sample size.
03

Interpret the Confidence Interval

The correct interpretation of the confidence interval is given by statement i. The phrase, 'I am 95% confident that the population mean is between ___' suggests that if the procedure was repeated many times, 95% of the resulting intervals would contain the population mean.
04

Test the Null Hypothesis

The null hypothesis states that the population mean weight is 10 pounds. If the confidence interval calculated includes 10, then there isn't enough evidence to reject the null hypothesis, otherwise it should be rejected.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
In statistics, the sample mean is a central concept. It's the average of the values you collect. When collecting data, like the weights of orange bags, you sum these values and divide by the number of observations. For example, if you have weights of 10.2, 10.5, 10.3, and 10.3 pounds, the sample mean would be calculated as follows:\[\bar{x} = \frac{10.2 + 10.5 + 10.3 + 10.3}{4} = 10.325\]This figure provides a basic estimate of the central tendency of the sample data. It helps us understand the typical value within our collected data set.
The sample mean is crucial in forming the basis for further statistical analysis, like creating confidence intervals or conducting hypothesis tests.
Standard Deviation
Standard deviation is a measure that tells us how much the values in our data set differ from the average value, or mean. In simple terms, it shows us the extent of variation or dispersion of our data points.
To calculate the standard deviation (\[s\]) for the weights of oranges, you first need the variance, which is the average squared deviation from the mean. Using the sample mean previously calculated, subtract the mean from each weight, square the result, and take the average of those squared differences:
  • Calculate difference from the mean for each observation.
  • Square these differences.
  • Find the average of those squared differences.
The standard deviation is useful because it provides insights into the spread of the distribution, indicating how tightly or loosely the data is clustered around the mean.
Null Hypothesis
In hypothesis testing, the null hypothesis is a default or original assumption that there is no effect or no difference. It is a starting point that we test to find evidence against it.
For the exercise, the null hypothesis (\[H_0\]) states that the population mean weight of the orange bags is 10 pounds. This assumption acts as a baseline that researchers will either reject or fail to reject based on the data collected.
Testing the null hypothesis involves statistical calculations such as computing confidence intervals or other metrics, which determine whether the observed data provides enough evidence to conclude that the null hypothesis isn’t true.
Normal Distribution
The normal distribution, commonly known as the bell curve, is a fundamental concept in statistics. It depicts data that clusters around a mean or average, with data points decreasing in frequency as they move away from the mean.
Its shape is symmetrical, with a peak at the mean, and it always follows a specific mathematical function. Many natural phenomena, including weights of objects, often approximate this pattern.
  • The mean, median, and mode of a normal distribution are all the same.
  • It is defined by its mean and standard deviation.
  • Approximately 68% of data falls within one standard deviation of the mean.
Understanding normal distribution helps us make inferences about a population from a sample, aiding the construction of confidence intervals.

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Most popular questions from this chapter

A study of all the students at a small college showed a mean age of \(20.7\) and a standard deviation of \(2.5\) years. a. Are these numbers statistics or parameters? Explain. b. Label both numbers with their appropriate symbol (such as \(\bar{x}, \mu, s\), or \(\sigma)\).

The acceptance rate for a random sample of 15 medical schools in the United States was taken. The mean acceptance rate for this sample was \(5.77\) with a standard error of \(0.56\). Assume the distribution of acceptance rates is Normal. (Source: Accepted.com) a. Decide whether each of the following statements is worded correctly for the confidence interval. Fill in the blanks for the correctly worded one(s). Explain the error for the ones that are incorrectly worded. i. We are \(95 \%\) confident that the sample mean is between ___ and ___ . ii. We are \(95 \%\) confident that the population mean is between ___ and ___ . iii. There is a \(95 \%\) probability that the population mean is between ___ and ___ . b. Based on your confidence interval, would you believe the average acceptance rate for medical schools is \(6.5\) ? Explain.

The weights of four randomly chosen bags of horse carrots, each bag labeled 20 pounds, were \(20.5,19.8,20.8\), and \(20.0\) pounds. Assume that the distribution of weights is Normal. Find a \(95 \%\) confidence interval for the mean weight of all bags of horse carrots. Use technology for your calculations. a. Decide whether each of the following three statements is a correctly worded interpretation of the confidence interval, and fill in the blanks for the correct option(s). i. \(95 \%\) of all sample means based on samples of the same size will be between _____ and _____. ii. I am \(95 \%\) confident that the population mean is between _____ and _____. iii. We are \(95 \%\) confident that the boundaries are _____ and _____. b. Can you reject a population mean of 20 pounds? Explain.

Some sources report that the weights of full-term newborn babies have a mean of 7 pounds and a standard deviation of \(0.6\) pound and are Normally distributed. a. What is the probability that one newborn baby will have a weight within \(0.6\) pound of the mean - that is, between \(6.4\) and \(7.6\) pounds, or within one standard deviation of the mean? b. What is the probability the average of four babies' weights will be within \(0.6\) pound of the mean - that is, between \(6.4\) and \(7.6\) pounds? c. Explain the difference between \(\mathrm{a}\) and \(\mathrm{b}\).

A random sample of 50 12th-grade students was asked how long it took to get to school. The sample mean was \(16.2\) minutes, and the sample standard deviation was \(12.3\) minutes. (Source: AMSTAT Census at School) a. Find a \(95 \%\) confidence interval for the population mean time it takes 12 th-grade students to get to school. b. Would a \(90 \%\) confidence interval based on this sample data be wider or narrower than the \(95 \%\) confidence interval? Explain. Check your answer by constructing a \(90 \%\) confidence interval and comparing this width of the interval with the width of the \(95 \%\) confidence interval you found in part a.

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